Exception passing a header value to request library Create Session
I have the following in my Robotframework keyword:
${headers}= Set Variable {"Content-Type": "application/json"}
Create Session sample ${url} headers=${headers} disable_warnings=1
But I'm getting the following error in Create session.
ValueError: not enough values to unpack (expected 2, got 1)
This is not working only for this header. I have tried using
{"Content-Type": "application${/}json"}
which didnt help.
python json robotframework
edited Nov 23 '18 at 11:55
Todor Minakov
7,60712739
asked Nov 23 '18 at 8:40
sathyaduraisathyadurai
111
add a comment |
I have the following in my Robotframework keyword:
${headers}= Set Variable {"Content-Type": "application/json"}
Create Session sample ${url} headers=${headers} disable_warnings=1
But I'm getting the following error in Create session.
ValueError: not enough values to unpack (expected 2, got 1)
This is not working only for this header. I have tried using
{"Content-Type": "application${/}json"}
which didnt help.
python json robotframework
edited Nov 23 '18 at 11:55
Todor Minakov
7,60712739
asked Nov 23 '18 at 8:40
sathyaduraisathyadurai
111
add a comment |
I have the following in my Robotframework keyword:
${headers}= Set Variable {"Content-Type": "application/json"}
Create Session sample ${url} headers=${headers} disable_warnings=1
But I'm getting the following error in Create session.
ValueError: not enough values to unpack (expected 2, got 1)
This is not working only for this header. I have tried using
{"Content-Type": "application${/}json"}
which didnt help.
python json robotframework
edited Nov 23 '18 at 11:55
Todor Minakov
7,60712739
asked Nov 23 '18 at 8:40
sathyaduraisathyadurai
111
I have the following in my Robotframework keyword:
${headers}= Set Variable {"Content-Type": "application/json"}
Create Session sample ${url} headers=${headers} disable_warnings=1
But I'm getting the following error in Create session.
ValueError: not enough values to unpack (expected 2, got 1)
This is not working only for this header. I have tried using
{"Content-Type": "application${/}json"}
which didnt help.
python json robotframework
python json robotframework
edited Nov 23 '18 at 11:55
Todor Minakov
7,60712739
asked Nov 23 '18 at 8:40
sathyaduraisathyadurai
111
edited Nov 23 '18 at 11:55
Todor Minakov
7,60712739
asked Nov 23 '18 at 8:40
sathyaduraisathyadurai
111
edited Nov 23 '18 at 11:55
Todor Minakov
7,60712739
edited Nov 23 '18 at 11:55
Todor Minakov
7,60712739
edited Nov 23 '18 at 11:55
Todor Minakov
7,60712739
7,60712739
asked Nov 23 '18 at 8:40
sathyaduraisathyadurai
111
asked Nov 23 '18 at 8:40
sathyaduraisathyadurai
111
asked Nov 23 '18 at 8:40
sathyaduraisathyadurai
111
111
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
What you obviously tried to do is to create a dictionary (to pass as a headers argument), but that's not the way to accomplish this in Robotframework.
The keyword Set Variable creates a var of type string if you pass an argument that is string-like - it does not deduct that you tried to create a dictionary just by the presence of the curly brackets.
This is how you can create a real dictionary (a dict (sub)type in python):
${headers}= Create Dictionary Content-Type=application/json
When you pass this variable to Create Session it now will be a proper dict, and the keyword shouldn't fail because of that.
Create Session sample ${url} headers=${headers} disable_warnings=1
answered Nov 23 '18 at 8:55
Todor MinakovTodor Minakov
7,60712739
1
Thanks! this works fine
– sathyadurai
Nov 27 '18 at 9:05
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
What you obviously tried to do is to create a dictionary (to pass as a headers argument), but that's not the way to accomplish this in Robotframework.
The keyword Set Variable creates a var of type string if you pass an argument that is string-like - it does not deduct that you tried to create a dictionary just by the presence of the curly brackets.
This is how you can create a real dictionary (a dict (sub)type in python):
${headers}= Create Dictionary Content-Type=application/json
When you pass this variable to Create Session it now will be a proper dict, and the keyword shouldn't fail because of that.
Create Session sample ${url} headers=${headers} disable_warnings=1
answered Nov 23 '18 at 8:55
Todor MinakovTodor Minakov
7,60712739
1
Thanks! this works fine
– sathyadurai
Nov 27 '18 at 9:05
add a comment |
What you obviously tried to do is to create a dictionary (to pass as a headers argument), but that's not the way to accomplish this in Robotframework.
The keyword Set Variable creates a var of type string if you pass an argument that is string-like - it does not deduct that you tried to create a dictionary just by the presence of the curly brackets.
This is how you can create a real dictionary (a dict (sub)type in python):
${headers}= Create Dictionary Content-Type=application/json
When you pass this variable to Create Session it now will be a proper dict, and the keyword shouldn't fail because of that.
Create Session sample ${url} headers=${headers} disable_warnings=1
answered Nov 23 '18 at 8:55
Todor MinakovTodor Minakov
7,60712739
1
Thanks! this works fine
– sathyadurai
Nov 27 '18 at 9:05
add a comment |
What you obviously tried to do is to create a dictionary (to pass as a headers argument), but that's not the way to accomplish this in Robotframework.
The keyword Set Variable creates a var of type string if you pass an argument that is string-like - it does not deduct that you tried to create a dictionary just by the presence of the curly brackets.
This is how you can create a real dictionary (a dict (sub)type in python):
${headers}= Create Dictionary Content-Type=application/json
When you pass this variable to Create Session it now will be a proper dict, and the keyword shouldn't fail because of that.
Create Session sample ${url} headers=${headers} disable_warnings=1
answered Nov 23 '18 at 8:55
Todor MinakovTodor Minakov
7,60712739
What you obviously tried to do is to create a dictionary (to pass as a headers argument), but that's not the way to accomplish this in Robotframework.
The keyword Set Variable creates a var of type string if you pass an argument that is string-like - it does not deduct that you tried to create a dictionary just by the presence of the curly brackets.
This is how you can create a real dictionary (a dict (sub)type in python):
${headers}= Create Dictionary Content-Type=application/json
When you pass this variable to Create Session it now will be a proper dict, and the keyword shouldn't fail because of that.
Create Session sample ${url} headers=${headers} disable_warnings=1
answered Nov 23 '18 at 8:55
Todor MinakovTodor Minakov
7,60712739
answered Nov 23 '18 at 8:55
Todor MinakovTodor Minakov
7,60712739
answered Nov 23 '18 at 8:55
Todor MinakovTodor Minakov
7,60712739
answered Nov 23 '18 at 8:55
Todor MinakovTodor Minakov
7,60712739
7,60712739
1
Thanks! this works fine
– sathyadurai
Nov 27 '18 at 9:05
add a comment |
1
Thanks! this works fine
– sathyadurai
Nov 27 '18 at 9:05
1
1
Thanks! this works fine
– sathyadurai
Nov 27 '18 at 9:05
Thanks! this works fine
– sathyadurai
Nov 27 '18 at 9:05
add a comment |
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