Scope of a function variable












-1















I have the following function saved as dummy_function.py



def abc():

return q*q


On the Python console, I run



from dummy_function import *
q=4
b=abc()


I get the following error:
NameError: name 'q' is not defined



I understand that even though I have defined q in my current environment, it doesn't belong in the scope of the function abc. My question is how to solve this. I cannot define q in dummy_function. It will be in my current program but I have to run imported customized code on variables in the current program.










share|improve this question




















  • 5





    why not pass q to your function as a parameter?

    – Mike Scotty
    Nov 23 '18 at 9:14











  • This is just a raw example. I am passing a data-frame to the imported function but the range of the column value is available only in the current program. So if I say, xyz(df.iloc[:,range]), it says range not defined even though I have passed df as an argument in the function building

    – Abhishek Kulkarni
    Nov 23 '18 at 9:18






  • 1





    raw examples get raw answers. how should we help you if you do not provide a Minimal, Complete, and Verifiable example? your approach still sounds like a bad design choice to me. imported modules should not rely on magical global variables from the main program.

    – Mike Scotty
    Nov 23 '18 at 9:21






  • 1





    Anyway, what you are essentially asking for is dynamic scoping, but python (and pretty much all modern languages) use lexical scope. The sane way of doing this is to pass the values you need as arguments to the function.

    – juanpa.arrivillaga
    Nov 23 '18 at 9:21






  • 2





    what name error? Please provide a Minimal, Complete, and Verifiable example

    – juanpa.arrivillaga
    Nov 23 '18 at 9:26
















-1















I have the following function saved as dummy_function.py



def abc():

return q*q


On the Python console, I run



from dummy_function import *
q=4
b=abc()


I get the following error:
NameError: name 'q' is not defined



I understand that even though I have defined q in my current environment, it doesn't belong in the scope of the function abc. My question is how to solve this. I cannot define q in dummy_function. It will be in my current program but I have to run imported customized code on variables in the current program.










share|improve this question




















  • 5





    why not pass q to your function as a parameter?

    – Mike Scotty
    Nov 23 '18 at 9:14











  • This is just a raw example. I am passing a data-frame to the imported function but the range of the column value is available only in the current program. So if I say, xyz(df.iloc[:,range]), it says range not defined even though I have passed df as an argument in the function building

    – Abhishek Kulkarni
    Nov 23 '18 at 9:18






  • 1





    raw examples get raw answers. how should we help you if you do not provide a Minimal, Complete, and Verifiable example? your approach still sounds like a bad design choice to me. imported modules should not rely on magical global variables from the main program.

    – Mike Scotty
    Nov 23 '18 at 9:21






  • 1





    Anyway, what you are essentially asking for is dynamic scoping, but python (and pretty much all modern languages) use lexical scope. The sane way of doing this is to pass the values you need as arguments to the function.

    – juanpa.arrivillaga
    Nov 23 '18 at 9:21






  • 2





    what name error? Please provide a Minimal, Complete, and Verifiable example

    – juanpa.arrivillaga
    Nov 23 '18 at 9:26














-1












-1








-1








I have the following function saved as dummy_function.py



def abc():

return q*q


On the Python console, I run



from dummy_function import *
q=4
b=abc()


I get the following error:
NameError: name 'q' is not defined



I understand that even though I have defined q in my current environment, it doesn't belong in the scope of the function abc. My question is how to solve this. I cannot define q in dummy_function. It will be in my current program but I have to run imported customized code on variables in the current program.










share|improve this question
















I have the following function saved as dummy_function.py



def abc():

return q*q


On the Python console, I run



from dummy_function import *
q=4
b=abc()


I get the following error:
NameError: name 'q' is not defined



I understand that even though I have defined q in my current environment, it doesn't belong in the scope of the function abc. My question is how to solve this. I cannot define q in dummy_function. It will be in my current program but I have to run imported customized code on variables in the current program.







python function scope






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 9:48









9769953

1,5881416




1,5881416










asked Nov 23 '18 at 9:12









Abhishek KulkarniAbhishek Kulkarni

1348




1348








  • 5





    why not pass q to your function as a parameter?

    – Mike Scotty
    Nov 23 '18 at 9:14











  • This is just a raw example. I am passing a data-frame to the imported function but the range of the column value is available only in the current program. So if I say, xyz(df.iloc[:,range]), it says range not defined even though I have passed df as an argument in the function building

    – Abhishek Kulkarni
    Nov 23 '18 at 9:18






  • 1





    raw examples get raw answers. how should we help you if you do not provide a Minimal, Complete, and Verifiable example? your approach still sounds like a bad design choice to me. imported modules should not rely on magical global variables from the main program.

    – Mike Scotty
    Nov 23 '18 at 9:21






  • 1





    Anyway, what you are essentially asking for is dynamic scoping, but python (and pretty much all modern languages) use lexical scope. The sane way of doing this is to pass the values you need as arguments to the function.

    – juanpa.arrivillaga
    Nov 23 '18 at 9:21






  • 2





    what name error? Please provide a Minimal, Complete, and Verifiable example

    – juanpa.arrivillaga
    Nov 23 '18 at 9:26














  • 5





    why not pass q to your function as a parameter?

    – Mike Scotty
    Nov 23 '18 at 9:14











  • This is just a raw example. I am passing a data-frame to the imported function but the range of the column value is available only in the current program. So if I say, xyz(df.iloc[:,range]), it says range not defined even though I have passed df as an argument in the function building

    – Abhishek Kulkarni
    Nov 23 '18 at 9:18






  • 1





    raw examples get raw answers. how should we help you if you do not provide a Minimal, Complete, and Verifiable example? your approach still sounds like a bad design choice to me. imported modules should not rely on magical global variables from the main program.

    – Mike Scotty
    Nov 23 '18 at 9:21






  • 1





    Anyway, what you are essentially asking for is dynamic scoping, but python (and pretty much all modern languages) use lexical scope. The sane way of doing this is to pass the values you need as arguments to the function.

    – juanpa.arrivillaga
    Nov 23 '18 at 9:21






  • 2





    what name error? Please provide a Minimal, Complete, and Verifiable example

    – juanpa.arrivillaga
    Nov 23 '18 at 9:26








5




5





why not pass q to your function as a parameter?

– Mike Scotty
Nov 23 '18 at 9:14





why not pass q to your function as a parameter?

– Mike Scotty
Nov 23 '18 at 9:14













This is just a raw example. I am passing a data-frame to the imported function but the range of the column value is available only in the current program. So if I say, xyz(df.iloc[:,range]), it says range not defined even though I have passed df as an argument in the function building

– Abhishek Kulkarni
Nov 23 '18 at 9:18





This is just a raw example. I am passing a data-frame to the imported function but the range of the column value is available only in the current program. So if I say, xyz(df.iloc[:,range]), it says range not defined even though I have passed df as an argument in the function building

– Abhishek Kulkarni
Nov 23 '18 at 9:18




1




1





raw examples get raw answers. how should we help you if you do not provide a Minimal, Complete, and Verifiable example? your approach still sounds like a bad design choice to me. imported modules should not rely on magical global variables from the main program.

– Mike Scotty
Nov 23 '18 at 9:21





raw examples get raw answers. how should we help you if you do not provide a Minimal, Complete, and Verifiable example? your approach still sounds like a bad design choice to me. imported modules should not rely on magical global variables from the main program.

– Mike Scotty
Nov 23 '18 at 9:21




1




1





Anyway, what you are essentially asking for is dynamic scoping, but python (and pretty much all modern languages) use lexical scope. The sane way of doing this is to pass the values you need as arguments to the function.

– juanpa.arrivillaga
Nov 23 '18 at 9:21





Anyway, what you are essentially asking for is dynamic scoping, but python (and pretty much all modern languages) use lexical scope. The sane way of doing this is to pass the values you need as arguments to the function.

– juanpa.arrivillaga
Nov 23 '18 at 9:21




2




2





what name error? Please provide a Minimal, Complete, and Verifiable example

– juanpa.arrivillaga
Nov 23 '18 at 9:26





what name error? Please provide a Minimal, Complete, and Verifiable example

– juanpa.arrivillaga
Nov 23 '18 at 9:26












1 Answer
1






active

oldest

votes


















2














You should put a parameter that your function will receive:



def abc(q):
return q*q


Then when you run your function, you should put what number you want the function to execute:



q = 4
print(abc(q))


Or you can do



print(abc(4))





share|improve this answer
























  • You can also define a default value of q in the abc function

    – Norfeldt
    Nov 23 '18 at 9:22












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














You should put a parameter that your function will receive:



def abc(q):
return q*q


Then when you run your function, you should put what number you want the function to execute:



q = 4
print(abc(q))


Or you can do



print(abc(4))





share|improve this answer
























  • You can also define a default value of q in the abc function

    – Norfeldt
    Nov 23 '18 at 9:22
















2














You should put a parameter that your function will receive:



def abc(q):
return q*q


Then when you run your function, you should put what number you want the function to execute:



q = 4
print(abc(q))


Or you can do



print(abc(4))





share|improve this answer
























  • You can also define a default value of q in the abc function

    – Norfeldt
    Nov 23 '18 at 9:22














2












2








2







You should put a parameter that your function will receive:



def abc(q):
return q*q


Then when you run your function, you should put what number you want the function to execute:



q = 4
print(abc(q))


Or you can do



print(abc(4))





share|improve this answer













You should put a parameter that your function will receive:



def abc(q):
return q*q


Then when you run your function, you should put what number you want the function to execute:



q = 4
print(abc(q))


Or you can do



print(abc(4))






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 23 '18 at 9:19









redgermanyredgermany

235




235













  • You can also define a default value of q in the abc function

    – Norfeldt
    Nov 23 '18 at 9:22



















  • You can also define a default value of q in the abc function

    – Norfeldt
    Nov 23 '18 at 9:22

















You can also define a default value of q in the abc function

– Norfeldt
Nov 23 '18 at 9:22





You can also define a default value of q in the abc function

– Norfeldt
Nov 23 '18 at 9:22




















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