How to use 'unknown' without instanceof in a meaningful way?





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Since TypeScript 3.0 the new top type unknown is available as a type-safe counterpart of any.



I really love this type, as it makes the code even more robust.



My main problem with this is, that TypeScript (obviously) does not provide an instanceof-feature at runtime for interfaces. If it would (be possible), this code would work quite well:



class Test {

doSomething(value: unknown) {
if(value instanceof MySuperInterface) {
return value.superFunction();
}

return false;
}

}


My question



How do I use this type in a meaningful way, without the need of checking each property of my interface?










share|improve this question


















  • 1





    In conjunction with discriminated unions maybe?

    – Fenton
    Nov 23 '18 at 14:17











  • Pick a couple of properties that are significant and use custom type guard to narrow unknown to your specific interface type ?

    – Titian Cernicova-Dragomir
    Nov 23 '18 at 14:19


















0















Since TypeScript 3.0 the new top type unknown is available as a type-safe counterpart of any.



I really love this type, as it makes the code even more robust.



My main problem with this is, that TypeScript (obviously) does not provide an instanceof-feature at runtime for interfaces. If it would (be possible), this code would work quite well:



class Test {

doSomething(value: unknown) {
if(value instanceof MySuperInterface) {
return value.superFunction();
}

return false;
}

}


My question



How do I use this type in a meaningful way, without the need of checking each property of my interface?










share|improve this question


















  • 1





    In conjunction with discriminated unions maybe?

    – Fenton
    Nov 23 '18 at 14:17











  • Pick a couple of properties that are significant and use custom type guard to narrow unknown to your specific interface type ?

    – Titian Cernicova-Dragomir
    Nov 23 '18 at 14:19














0












0








0








Since TypeScript 3.0 the new top type unknown is available as a type-safe counterpart of any.



I really love this type, as it makes the code even more robust.



My main problem with this is, that TypeScript (obviously) does not provide an instanceof-feature at runtime for interfaces. If it would (be possible), this code would work quite well:



class Test {

doSomething(value: unknown) {
if(value instanceof MySuperInterface) {
return value.superFunction();
}

return false;
}

}


My question



How do I use this type in a meaningful way, without the need of checking each property of my interface?










share|improve this question














Since TypeScript 3.0 the new top type unknown is available as a type-safe counterpart of any.



I really love this type, as it makes the code even more robust.



My main problem with this is, that TypeScript (obviously) does not provide an instanceof-feature at runtime for interfaces. If it would (be possible), this code would work quite well:



class Test {

doSomething(value: unknown) {
if(value instanceof MySuperInterface) {
return value.superFunction();
}

return false;
}

}


My question



How do I use this type in a meaningful way, without the need of checking each property of my interface?







typescript






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asked Nov 23 '18 at 14:10









scipperscipper

1,4631424




1,4631424








  • 1





    In conjunction with discriminated unions maybe?

    – Fenton
    Nov 23 '18 at 14:17











  • Pick a couple of properties that are significant and use custom type guard to narrow unknown to your specific interface type ?

    – Titian Cernicova-Dragomir
    Nov 23 '18 at 14:19














  • 1





    In conjunction with discriminated unions maybe?

    – Fenton
    Nov 23 '18 at 14:17











  • Pick a couple of properties that are significant and use custom type guard to narrow unknown to your specific interface type ?

    – Titian Cernicova-Dragomir
    Nov 23 '18 at 14:19








1




1





In conjunction with discriminated unions maybe?

– Fenton
Nov 23 '18 at 14:17





In conjunction with discriminated unions maybe?

– Fenton
Nov 23 '18 at 14:17













Pick a couple of properties that are significant and use custom type guard to narrow unknown to your specific interface type ?

– Titian Cernicova-Dragomir
Nov 23 '18 at 14:19





Pick a couple of properties that are significant and use custom type guard to narrow unknown to your specific interface type ?

– Titian Cernicova-Dragomir
Nov 23 '18 at 14:19












1 Answer
1






active

oldest

votes


















0














Javascipt does not check for interface type at runtime.



Typescript: instanceof check on interface



But, you can use unknown type with classes as shown below:



interface MySuperInterface {
superfunction(): string;
}

class MySuperImplementation implements MySuperInterface {
superfunction(): string {
return "Hello from super function";
}
}

class Greeter {
greeting: string;

constructor(message: string) {
this.greeting = message;
}

greet() {
return "Hello, " + this.greeting;
}

testSuperFunction(value: unknown) {
if (value instanceof MySuperImplementation) {
return value.superfunction();
}
else {
return "Error";
}
}
}

let greeter = new Greeter("world");

const sfunc = new MySuperImplementation();

console.log(greeter.testSuperFunction(sfunc));


https://www.typescriptlang.org/play/index.html#src=interface%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%3B%0D%0A%7D%0D%0A%0D%0Aclass%20MySuperImplementation%20implements%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%20from%20super%20function%22%3B%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Aclass%20Greeter%20%7B%0D%0A%20%20%20%20greeting%3A%20string%3B%0D%0A%0D%0A%20%20%20%20constructor(message%3A%20string)%20%7B%0D%0A%20%20%20%20%20%20%20%20this.greeting%20%3D%20message%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20greet()%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%2C%20%22%20%2B%20this.greeting%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20testSuperFunction(value%3A%20unknown)%20%7B%0D%0A%20%20%20%20%20%20%20%20if%20(value%20instanceof%20MySuperImplementation)%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20value.superfunction()%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%20%20%20%20else%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20%22Error%22%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Alet%20greeter%20%3D%20new%20Greeter(%22world%22)%3B%0D%0A%0D%0Aconst%20sfunc%20%3D%20new%20MySuperImplementation()%3B%0D%0A%0D%0Aconsole.log(greeter.testSuperFunction(sfunc))%3B






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    0














    Javascipt does not check for interface type at runtime.



    Typescript: instanceof check on interface



    But, you can use unknown type with classes as shown below:



    interface MySuperInterface {
    superfunction(): string;
    }

    class MySuperImplementation implements MySuperInterface {
    superfunction(): string {
    return "Hello from super function";
    }
    }

    class Greeter {
    greeting: string;

    constructor(message: string) {
    this.greeting = message;
    }

    greet() {
    return "Hello, " + this.greeting;
    }

    testSuperFunction(value: unknown) {
    if (value instanceof MySuperImplementation) {
    return value.superfunction();
    }
    else {
    return "Error";
    }
    }
    }

    let greeter = new Greeter("world");

    const sfunc = new MySuperImplementation();

    console.log(greeter.testSuperFunction(sfunc));


    https://www.typescriptlang.org/play/index.html#src=interface%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%3B%0D%0A%7D%0D%0A%0D%0Aclass%20MySuperImplementation%20implements%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%20from%20super%20function%22%3B%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Aclass%20Greeter%20%7B%0D%0A%20%20%20%20greeting%3A%20string%3B%0D%0A%0D%0A%20%20%20%20constructor(message%3A%20string)%20%7B%0D%0A%20%20%20%20%20%20%20%20this.greeting%20%3D%20message%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20greet()%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%2C%20%22%20%2B%20this.greeting%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20testSuperFunction(value%3A%20unknown)%20%7B%0D%0A%20%20%20%20%20%20%20%20if%20(value%20instanceof%20MySuperImplementation)%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20value.superfunction()%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%20%20%20%20else%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20%22Error%22%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Alet%20greeter%20%3D%20new%20Greeter(%22world%22)%3B%0D%0A%0D%0Aconst%20sfunc%20%3D%20new%20MySuperImplementation()%3B%0D%0A%0D%0Aconsole.log(greeter.testSuperFunction(sfunc))%3B






    share|improve this answer




























      0














      Javascipt does not check for interface type at runtime.



      Typescript: instanceof check on interface



      But, you can use unknown type with classes as shown below:



      interface MySuperInterface {
      superfunction(): string;
      }

      class MySuperImplementation implements MySuperInterface {
      superfunction(): string {
      return "Hello from super function";
      }
      }

      class Greeter {
      greeting: string;

      constructor(message: string) {
      this.greeting = message;
      }

      greet() {
      return "Hello, " + this.greeting;
      }

      testSuperFunction(value: unknown) {
      if (value instanceof MySuperImplementation) {
      return value.superfunction();
      }
      else {
      return "Error";
      }
      }
      }

      let greeter = new Greeter("world");

      const sfunc = new MySuperImplementation();

      console.log(greeter.testSuperFunction(sfunc));


      https://www.typescriptlang.org/play/index.html#src=interface%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%3B%0D%0A%7D%0D%0A%0D%0Aclass%20MySuperImplementation%20implements%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%20from%20super%20function%22%3B%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Aclass%20Greeter%20%7B%0D%0A%20%20%20%20greeting%3A%20string%3B%0D%0A%0D%0A%20%20%20%20constructor(message%3A%20string)%20%7B%0D%0A%20%20%20%20%20%20%20%20this.greeting%20%3D%20message%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20greet()%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%2C%20%22%20%2B%20this.greeting%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20testSuperFunction(value%3A%20unknown)%20%7B%0D%0A%20%20%20%20%20%20%20%20if%20(value%20instanceof%20MySuperImplementation)%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20value.superfunction()%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%20%20%20%20else%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20%22Error%22%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Alet%20greeter%20%3D%20new%20Greeter(%22world%22)%3B%0D%0A%0D%0Aconst%20sfunc%20%3D%20new%20MySuperImplementation()%3B%0D%0A%0D%0Aconsole.log(greeter.testSuperFunction(sfunc))%3B






      share|improve this answer


























        0












        0








        0







        Javascipt does not check for interface type at runtime.



        Typescript: instanceof check on interface



        But, you can use unknown type with classes as shown below:



        interface MySuperInterface {
        superfunction(): string;
        }

        class MySuperImplementation implements MySuperInterface {
        superfunction(): string {
        return "Hello from super function";
        }
        }

        class Greeter {
        greeting: string;

        constructor(message: string) {
        this.greeting = message;
        }

        greet() {
        return "Hello, " + this.greeting;
        }

        testSuperFunction(value: unknown) {
        if (value instanceof MySuperImplementation) {
        return value.superfunction();
        }
        else {
        return "Error";
        }
        }
        }

        let greeter = new Greeter("world");

        const sfunc = new MySuperImplementation();

        console.log(greeter.testSuperFunction(sfunc));


        https://www.typescriptlang.org/play/index.html#src=interface%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%3B%0D%0A%7D%0D%0A%0D%0Aclass%20MySuperImplementation%20implements%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%20from%20super%20function%22%3B%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Aclass%20Greeter%20%7B%0D%0A%20%20%20%20greeting%3A%20string%3B%0D%0A%0D%0A%20%20%20%20constructor(message%3A%20string)%20%7B%0D%0A%20%20%20%20%20%20%20%20this.greeting%20%3D%20message%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20greet()%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%2C%20%22%20%2B%20this.greeting%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20testSuperFunction(value%3A%20unknown)%20%7B%0D%0A%20%20%20%20%20%20%20%20if%20(value%20instanceof%20MySuperImplementation)%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20value.superfunction()%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%20%20%20%20else%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20%22Error%22%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Alet%20greeter%20%3D%20new%20Greeter(%22world%22)%3B%0D%0A%0D%0Aconst%20sfunc%20%3D%20new%20MySuperImplementation()%3B%0D%0A%0D%0Aconsole.log(greeter.testSuperFunction(sfunc))%3B






        share|improve this answer













        Javascipt does not check for interface type at runtime.



        Typescript: instanceof check on interface



        But, you can use unknown type with classes as shown below:



        interface MySuperInterface {
        superfunction(): string;
        }

        class MySuperImplementation implements MySuperInterface {
        superfunction(): string {
        return "Hello from super function";
        }
        }

        class Greeter {
        greeting: string;

        constructor(message: string) {
        this.greeting = message;
        }

        greet() {
        return "Hello, " + this.greeting;
        }

        testSuperFunction(value: unknown) {
        if (value instanceof MySuperImplementation) {
        return value.superfunction();
        }
        else {
        return "Error";
        }
        }
        }

        let greeter = new Greeter("world");

        const sfunc = new MySuperImplementation();

        console.log(greeter.testSuperFunction(sfunc));


        https://www.typescriptlang.org/play/index.html#src=interface%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%3B%0D%0A%7D%0D%0A%0D%0Aclass%20MySuperImplementation%20implements%20MySuperInterface%20%7B%0D%0A%20%20%20%20superfunction()%3A%20string%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%20from%20super%20function%22%3B%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Aclass%20Greeter%20%7B%0D%0A%20%20%20%20greeting%3A%20string%3B%0D%0A%0D%0A%20%20%20%20constructor(message%3A%20string)%20%7B%0D%0A%20%20%20%20%20%20%20%20this.greeting%20%3D%20message%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20greet()%20%7B%0D%0A%20%20%20%20%20%20%20%20return%20%22Hello%2C%20%22%20%2B%20this.greeting%3B%0D%0A%20%20%20%20%7D%0D%0A%0D%0A%20%20%20%20testSuperFunction(value%3A%20unknown)%20%7B%0D%0A%20%20%20%20%20%20%20%20if%20(value%20instanceof%20MySuperImplementation)%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20value.superfunction()%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%20%20%20%20else%20%7B%0D%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20%22Error%22%3B%0D%0A%20%20%20%20%20%20%20%20%7D%0D%0A%20%20%20%20%7D%0D%0A%7D%0D%0A%0D%0Alet%20greeter%20%3D%20new%20Greeter(%22world%22)%3B%0D%0A%0D%0Aconst%20sfunc%20%3D%20new%20MySuperImplementation()%3B%0D%0A%0D%0Aconsole.log(greeter.testSuperFunction(sfunc))%3B







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        answered Nov 23 '18 at 17:31









        SSKSSK

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