If a black hole is created from light, can this black hole then move at the speed of light?
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Imagine we managed to squeeze light into a very tiny region of space so that the energy concentration at that point becomes a black hole. Can this black hole then move at the speed of light?
black-holes mass speed-of-light mass-energy speed
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add a comment |
$begingroup$
Imagine we managed to squeeze light into a very tiny region of space so that the energy concentration at that point becomes a black hole. Can this black hole then move at the speed of light?
black-holes mass speed-of-light mass-energy speed
$endgroup$
add a comment |
$begingroup$
Imagine we managed to squeeze light into a very tiny region of space so that the energy concentration at that point becomes a black hole. Can this black hole then move at the speed of light?
black-holes mass speed-of-light mass-energy speed
$endgroup$
Imagine we managed to squeeze light into a very tiny region of space so that the energy concentration at that point becomes a black hole. Can this black hole then move at the speed of light?
black-holes mass speed-of-light mass-energy speed
black-holes mass speed-of-light mass-energy speed
edited Mar 30 at 8:07
Peter Mortensen
1,95511323
1,95511323
asked Mar 29 at 11:00
user6760user6760
3,06212144
3,06212144
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add a comment |
2 Answers
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No. I assume you're thinking that a black hole made from light would have a zero rest mass and could therefore travel at the speed of light. However the rest mass of any black hole is due not only to the mass that went into it but also the energy (e.g. photons) that went into it. The increase in mass due to the energy is given by Einstein's famous equation $E = mc^2$.
So if we create the black hole from purely mass $m$ the rest mass of the black hole is just $m$.
If we create the black hole from purely energy $E$, e.g. from photons with a total energy $E$, then the rest mass of the black hole is $E/c^2$.
Or for completeness we could use a mixture of mass $m$ and energy $E$ in which case the rest mass would be $m + E/c^2$.
So a black hole made from just photons would not have a zero rest mass and therefore could not travel at the speed of light.
This conversion of photons to a mass isn't unique to a black hole. For example suppose we start with a hydrogen atom in the ground state, $1s$, and let it absorb a 10.2eV photon to excite it to the $2p$ state. This would increase the mass by $10.2textrm{eV}/c^2$ i.e. even though the photon is massless absorbing it increases the mass of the hydrogen atom. As a general rule mass is not a conserved quantity either in special or general relativity.
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Comments are not for extended discussion; this conversation has been moved to chat.
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– ACuriousMind♦
Mar 29 at 22:23
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No. Nothing with non-zero mass can move at lightspeed. A kugelblitz would behave just like a more conventional black hole formed from matter, due to the no-hair theorem.
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'formed directly from matter'. If it's a black hole it has mass. If it has mass that means the photons collided and became electrons and positrons. = no lightspeed :(
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– Mazura
Mar 29 at 22:10
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Lightspeed - qualify by being in vacuum (I am thinking of Cherenkov radiation)?
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– Peter Mortensen
Mar 30 at 3:23
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@Mazura Yes, the black hole formed from photons has mass, but that doesn't necessarily mean that the photons produced matter. See chat.stackexchange.com/transcript/message/49710715#49710715
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– PM 2Ring
Mar 30 at 10:49
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@Peter Yes, by "lightspeed" I mean c, the speed of light in a perfect vacuum, 299792458 m/s.
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– PM 2Ring
Mar 30 at 11:06
add a comment |
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2 Answers
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2 Answers
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$begingroup$
No. I assume you're thinking that a black hole made from light would have a zero rest mass and could therefore travel at the speed of light. However the rest mass of any black hole is due not only to the mass that went into it but also the energy (e.g. photons) that went into it. The increase in mass due to the energy is given by Einstein's famous equation $E = mc^2$.
So if we create the black hole from purely mass $m$ the rest mass of the black hole is just $m$.
If we create the black hole from purely energy $E$, e.g. from photons with a total energy $E$, then the rest mass of the black hole is $E/c^2$.
Or for completeness we could use a mixture of mass $m$ and energy $E$ in which case the rest mass would be $m + E/c^2$.
So a black hole made from just photons would not have a zero rest mass and therefore could not travel at the speed of light.
This conversion of photons to a mass isn't unique to a black hole. For example suppose we start with a hydrogen atom in the ground state, $1s$, and let it absorb a 10.2eV photon to excite it to the $2p$ state. This would increase the mass by $10.2textrm{eV}/c^2$ i.e. even though the photon is massless absorbing it increases the mass of the hydrogen atom. As a general rule mass is not a conserved quantity either in special or general relativity.
$endgroup$
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
Mar 29 at 22:23
add a comment |
$begingroup$
No. I assume you're thinking that a black hole made from light would have a zero rest mass and could therefore travel at the speed of light. However the rest mass of any black hole is due not only to the mass that went into it but also the energy (e.g. photons) that went into it. The increase in mass due to the energy is given by Einstein's famous equation $E = mc^2$.
So if we create the black hole from purely mass $m$ the rest mass of the black hole is just $m$.
If we create the black hole from purely energy $E$, e.g. from photons with a total energy $E$, then the rest mass of the black hole is $E/c^2$.
Or for completeness we could use a mixture of mass $m$ and energy $E$ in which case the rest mass would be $m + E/c^2$.
So a black hole made from just photons would not have a zero rest mass and therefore could not travel at the speed of light.
This conversion of photons to a mass isn't unique to a black hole. For example suppose we start with a hydrogen atom in the ground state, $1s$, and let it absorb a 10.2eV photon to excite it to the $2p$ state. This would increase the mass by $10.2textrm{eV}/c^2$ i.e. even though the photon is massless absorbing it increases the mass of the hydrogen atom. As a general rule mass is not a conserved quantity either in special or general relativity.
$endgroup$
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
Mar 29 at 22:23
add a comment |
$begingroup$
No. I assume you're thinking that a black hole made from light would have a zero rest mass and could therefore travel at the speed of light. However the rest mass of any black hole is due not only to the mass that went into it but also the energy (e.g. photons) that went into it. The increase in mass due to the energy is given by Einstein's famous equation $E = mc^2$.
So if we create the black hole from purely mass $m$ the rest mass of the black hole is just $m$.
If we create the black hole from purely energy $E$, e.g. from photons with a total energy $E$, then the rest mass of the black hole is $E/c^2$.
Or for completeness we could use a mixture of mass $m$ and energy $E$ in which case the rest mass would be $m + E/c^2$.
So a black hole made from just photons would not have a zero rest mass and therefore could not travel at the speed of light.
This conversion of photons to a mass isn't unique to a black hole. For example suppose we start with a hydrogen atom in the ground state, $1s$, and let it absorb a 10.2eV photon to excite it to the $2p$ state. This would increase the mass by $10.2textrm{eV}/c^2$ i.e. even though the photon is massless absorbing it increases the mass of the hydrogen atom. As a general rule mass is not a conserved quantity either in special or general relativity.
$endgroup$
No. I assume you're thinking that a black hole made from light would have a zero rest mass and could therefore travel at the speed of light. However the rest mass of any black hole is due not only to the mass that went into it but also the energy (e.g. photons) that went into it. The increase in mass due to the energy is given by Einstein's famous equation $E = mc^2$.
So if we create the black hole from purely mass $m$ the rest mass of the black hole is just $m$.
If we create the black hole from purely energy $E$, e.g. from photons with a total energy $E$, then the rest mass of the black hole is $E/c^2$.
Or for completeness we could use a mixture of mass $m$ and energy $E$ in which case the rest mass would be $m + E/c^2$.
So a black hole made from just photons would not have a zero rest mass and therefore could not travel at the speed of light.
This conversion of photons to a mass isn't unique to a black hole. For example suppose we start with a hydrogen atom in the ground state, $1s$, and let it absorb a 10.2eV photon to excite it to the $2p$ state. This would increase the mass by $10.2textrm{eV}/c^2$ i.e. even though the photon is massless absorbing it increases the mass of the hydrogen atom. As a general rule mass is not a conserved quantity either in special or general relativity.
answered Mar 29 at 12:17
John RennieJohn Rennie
280k44557806
280k44557806
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Comments are not for extended discussion; this conversation has been moved to chat.
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– ACuriousMind♦
Mar 29 at 22:23
add a comment |
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
Mar 29 at 22:23
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
Mar 29 at 22:23
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
Mar 29 at 22:23
add a comment |
$begingroup$
No. Nothing with non-zero mass can move at lightspeed. A kugelblitz would behave just like a more conventional black hole formed from matter, due to the no-hair theorem.
$endgroup$
$begingroup$
'formed directly from matter'. If it's a black hole it has mass. If it has mass that means the photons collided and became electrons and positrons. = no lightspeed :(
$endgroup$
– Mazura
Mar 29 at 22:10
$begingroup$
Lightspeed - qualify by being in vacuum (I am thinking of Cherenkov radiation)?
$endgroup$
– Peter Mortensen
Mar 30 at 3:23
$begingroup$
@Mazura Yes, the black hole formed from photons has mass, but that doesn't necessarily mean that the photons produced matter. See chat.stackexchange.com/transcript/message/49710715#49710715
$endgroup$
– PM 2Ring
Mar 30 at 10:49
$begingroup$
@Peter Yes, by "lightspeed" I mean c, the speed of light in a perfect vacuum, 299792458 m/s.
$endgroup$
– PM 2Ring
Mar 30 at 11:06
add a comment |
$begingroup$
No. Nothing with non-zero mass can move at lightspeed. A kugelblitz would behave just like a more conventional black hole formed from matter, due to the no-hair theorem.
$endgroup$
$begingroup$
'formed directly from matter'. If it's a black hole it has mass. If it has mass that means the photons collided and became electrons and positrons. = no lightspeed :(
$endgroup$
– Mazura
Mar 29 at 22:10
$begingroup$
Lightspeed - qualify by being in vacuum (I am thinking of Cherenkov radiation)?
$endgroup$
– Peter Mortensen
Mar 30 at 3:23
$begingroup$
@Mazura Yes, the black hole formed from photons has mass, but that doesn't necessarily mean that the photons produced matter. See chat.stackexchange.com/transcript/message/49710715#49710715
$endgroup$
– PM 2Ring
Mar 30 at 10:49
$begingroup$
@Peter Yes, by "lightspeed" I mean c, the speed of light in a perfect vacuum, 299792458 m/s.
$endgroup$
– PM 2Ring
Mar 30 at 11:06
add a comment |
$begingroup$
No. Nothing with non-zero mass can move at lightspeed. A kugelblitz would behave just like a more conventional black hole formed from matter, due to the no-hair theorem.
$endgroup$
No. Nothing with non-zero mass can move at lightspeed. A kugelblitz would behave just like a more conventional black hole formed from matter, due to the no-hair theorem.
answered Mar 29 at 11:19
PM 2RingPM 2Ring
3,65021123
3,65021123
$begingroup$
'formed directly from matter'. If it's a black hole it has mass. If it has mass that means the photons collided and became electrons and positrons. = no lightspeed :(
$endgroup$
– Mazura
Mar 29 at 22:10
$begingroup$
Lightspeed - qualify by being in vacuum (I am thinking of Cherenkov radiation)?
$endgroup$
– Peter Mortensen
Mar 30 at 3:23
$begingroup$
@Mazura Yes, the black hole formed from photons has mass, but that doesn't necessarily mean that the photons produced matter. See chat.stackexchange.com/transcript/message/49710715#49710715
$endgroup$
– PM 2Ring
Mar 30 at 10:49
$begingroup$
@Peter Yes, by "lightspeed" I mean c, the speed of light in a perfect vacuum, 299792458 m/s.
$endgroup$
– PM 2Ring
Mar 30 at 11:06
add a comment |
$begingroup$
'formed directly from matter'. If it's a black hole it has mass. If it has mass that means the photons collided and became electrons and positrons. = no lightspeed :(
$endgroup$
– Mazura
Mar 29 at 22:10
$begingroup$
Lightspeed - qualify by being in vacuum (I am thinking of Cherenkov radiation)?
$endgroup$
– Peter Mortensen
Mar 30 at 3:23
$begingroup$
@Mazura Yes, the black hole formed from photons has mass, but that doesn't necessarily mean that the photons produced matter. See chat.stackexchange.com/transcript/message/49710715#49710715
$endgroup$
– PM 2Ring
Mar 30 at 10:49
$begingroup$
@Peter Yes, by "lightspeed" I mean c, the speed of light in a perfect vacuum, 299792458 m/s.
$endgroup$
– PM 2Ring
Mar 30 at 11:06
$begingroup$
'formed directly from matter'. If it's a black hole it has mass. If it has mass that means the photons collided and became electrons and positrons. = no lightspeed :(
$endgroup$
– Mazura
Mar 29 at 22:10
$begingroup$
'formed directly from matter'. If it's a black hole it has mass. If it has mass that means the photons collided and became electrons and positrons. = no lightspeed :(
$endgroup$
– Mazura
Mar 29 at 22:10
$begingroup$
Lightspeed - qualify by being in vacuum (I am thinking of Cherenkov radiation)?
$endgroup$
– Peter Mortensen
Mar 30 at 3:23
$begingroup$
Lightspeed - qualify by being in vacuum (I am thinking of Cherenkov radiation)?
$endgroup$
– Peter Mortensen
Mar 30 at 3:23
$begingroup$
@Mazura Yes, the black hole formed from photons has mass, but that doesn't necessarily mean that the photons produced matter. See chat.stackexchange.com/transcript/message/49710715#49710715
$endgroup$
– PM 2Ring
Mar 30 at 10:49
$begingroup$
@Mazura Yes, the black hole formed from photons has mass, but that doesn't necessarily mean that the photons produced matter. See chat.stackexchange.com/transcript/message/49710715#49710715
$endgroup$
– PM 2Ring
Mar 30 at 10:49
$begingroup$
@Peter Yes, by "lightspeed" I mean c, the speed of light in a perfect vacuum, 299792458 m/s.
$endgroup$
– PM 2Ring
Mar 30 at 11:06
$begingroup$
@Peter Yes, by "lightspeed" I mean c, the speed of light in a perfect vacuum, 299792458 m/s.
$endgroup$
– PM 2Ring
Mar 30 at 11:06
add a comment |
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