Neo4j - extract all subgraphs from neo4j database





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







0















I have a similar question to the one asked here, however, the solution proposed didn't work for me.



My Neo4j database has a lot of sub-graphs, each one of them contains varying number of nodes.



I would like to extract some kind of a list which will contain all sub-graphs separated.



enter image description here



In the example given, I would like to get 3 groups, where each group contains all the nodes in the sub-graph which the group represents.



How can I get all groups of nodes by Cypher query?



All the solutions that I have found for this problem require "root" node which I don't have in this case.










share|improve this question































    0















    I have a similar question to the one asked here, however, the solution proposed didn't work for me.



    My Neo4j database has a lot of sub-graphs, each one of them contains varying number of nodes.



    I would like to extract some kind of a list which will contain all sub-graphs separated.



    enter image description here



    In the example given, I would like to get 3 groups, where each group contains all the nodes in the sub-graph which the group represents.



    How can I get all groups of nodes by Cypher query?



    All the solutions that I have found for this problem require "root" node which I don't have in this case.










    share|improve this question



























      0












      0








      0








      I have a similar question to the one asked here, however, the solution proposed didn't work for me.



      My Neo4j database has a lot of sub-graphs, each one of them contains varying number of nodes.



      I would like to extract some kind of a list which will contain all sub-graphs separated.



      enter image description here



      In the example given, I would like to get 3 groups, where each group contains all the nodes in the sub-graph which the group represents.



      How can I get all groups of nodes by Cypher query?



      All the solutions that I have found for this problem require "root" node which I don't have in this case.










      share|improve this question
















      I have a similar question to the one asked here, however, the solution proposed didn't work for me.



      My Neo4j database has a lot of sub-graphs, each one of them contains varying number of nodes.



      I would like to extract some kind of a list which will contain all sub-graphs separated.



      enter image description here



      In the example given, I would like to get 3 groups, where each group contains all the nodes in the sub-graph which the group represents.



      How can I get all groups of nodes by Cypher query?



      All the solutions that I have found for this problem require "root" node which I don't have in this case.







      neo4j cypher






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 23 '18 at 13:55









      Guy Coder

      16.3k44287




      16.3k44287










      asked Nov 23 '18 at 13:51









      DanDan

      53




      53
























          1 Answer
          1






          active

          oldest

          votes


















          3














          You could use graph algorithms plugin and specifically connected components algorithm to label all the isolated subgraphs in your graph and then export them and group them later when exported by set id.



          Example:



          enter image description here



          create a sample graph



          MERGE (nAlice:User {id:'Alice'})
          MERGE (nBridget:User {id:'Bridget'})
          MERGE (nCharles:User {id:'Charles'})
          MERGE (nDoug:User {id:'Doug'})
          MERGE (nMark:User {id:'Mark'})
          MERGE (nMichael:User {id:'Michael'})

          MERGE (nAlice)-[:FRIEND]->(nBridget)
          MERGE (nAlice)-[:FRIEND]->(nCharles)
          MERGE (nMark)-[:FRIEND]->(nDoug)
          MERGE (nMark)-[:FRIEND]->(nMichael);


          Run connected components (unionFind) algorithm and return nodes in the same subgraph:



          CALL algo.unionFind.stream('User', 'FRIEND', {})
          YIELD nodeId,setId
          RETURN setId,collect(algo.getNodeById(nodeId)) AS nodes_from_specific_subgraph


          This will return:



          ╒═══════╤══════════════════════════════════════════════════╕
          │"setId"│"specific_subgraph" │
          ╞═══════╪══════════════════════════════════════════════════╡
          │4 │[{"id":"Doug"},{"id":"Mark"},{"id":"Michael"}] │
          ├───────┼──────────────────────────────────────────────────┤
          │0 │[{"id":"Alice"},{"id":"Bridget"},{"id":"Charles"}]│
          └───────┴──────────────────────────────────────────────────┘





          share|improve this answer


























          • added an example

            – Tomaž Bratanič
            Nov 23 '18 at 19:50











          • Thank you! I wasn't familiar with the graph lgorithm plugin. I have followed your example and that worked for me!

            – Dan
            Nov 24 '18 at 10:19












          Your Answer






          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "1"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53447957%2fneo4j-extract-all-subgraphs-from-neo4j-database%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3














          You could use graph algorithms plugin and specifically connected components algorithm to label all the isolated subgraphs in your graph and then export them and group them later when exported by set id.



          Example:



          enter image description here



          create a sample graph



          MERGE (nAlice:User {id:'Alice'})
          MERGE (nBridget:User {id:'Bridget'})
          MERGE (nCharles:User {id:'Charles'})
          MERGE (nDoug:User {id:'Doug'})
          MERGE (nMark:User {id:'Mark'})
          MERGE (nMichael:User {id:'Michael'})

          MERGE (nAlice)-[:FRIEND]->(nBridget)
          MERGE (nAlice)-[:FRIEND]->(nCharles)
          MERGE (nMark)-[:FRIEND]->(nDoug)
          MERGE (nMark)-[:FRIEND]->(nMichael);


          Run connected components (unionFind) algorithm and return nodes in the same subgraph:



          CALL algo.unionFind.stream('User', 'FRIEND', {})
          YIELD nodeId,setId
          RETURN setId,collect(algo.getNodeById(nodeId)) AS nodes_from_specific_subgraph


          This will return:



          ╒═══════╤══════════════════════════════════════════════════╕
          │"setId"│"specific_subgraph" │
          ╞═══════╪══════════════════════════════════════════════════╡
          │4 │[{"id":"Doug"},{"id":"Mark"},{"id":"Michael"}] │
          ├───────┼──────────────────────────────────────────────────┤
          │0 │[{"id":"Alice"},{"id":"Bridget"},{"id":"Charles"}]│
          └───────┴──────────────────────────────────────────────────┘





          share|improve this answer


























          • added an example

            – Tomaž Bratanič
            Nov 23 '18 at 19:50











          • Thank you! I wasn't familiar with the graph lgorithm plugin. I have followed your example and that worked for me!

            – Dan
            Nov 24 '18 at 10:19
















          3














          You could use graph algorithms plugin and specifically connected components algorithm to label all the isolated subgraphs in your graph and then export them and group them later when exported by set id.



          Example:



          enter image description here



          create a sample graph



          MERGE (nAlice:User {id:'Alice'})
          MERGE (nBridget:User {id:'Bridget'})
          MERGE (nCharles:User {id:'Charles'})
          MERGE (nDoug:User {id:'Doug'})
          MERGE (nMark:User {id:'Mark'})
          MERGE (nMichael:User {id:'Michael'})

          MERGE (nAlice)-[:FRIEND]->(nBridget)
          MERGE (nAlice)-[:FRIEND]->(nCharles)
          MERGE (nMark)-[:FRIEND]->(nDoug)
          MERGE (nMark)-[:FRIEND]->(nMichael);


          Run connected components (unionFind) algorithm and return nodes in the same subgraph:



          CALL algo.unionFind.stream('User', 'FRIEND', {})
          YIELD nodeId,setId
          RETURN setId,collect(algo.getNodeById(nodeId)) AS nodes_from_specific_subgraph


          This will return:



          ╒═══════╤══════════════════════════════════════════════════╕
          │"setId"│"specific_subgraph" │
          ╞═══════╪══════════════════════════════════════════════════╡
          │4 │[{"id":"Doug"},{"id":"Mark"},{"id":"Michael"}] │
          ├───────┼──────────────────────────────────────────────────┤
          │0 │[{"id":"Alice"},{"id":"Bridget"},{"id":"Charles"}]│
          └───────┴──────────────────────────────────────────────────┘





          share|improve this answer


























          • added an example

            – Tomaž Bratanič
            Nov 23 '18 at 19:50











          • Thank you! I wasn't familiar with the graph lgorithm plugin. I have followed your example and that worked for me!

            – Dan
            Nov 24 '18 at 10:19














          3












          3








          3







          You could use graph algorithms plugin and specifically connected components algorithm to label all the isolated subgraphs in your graph and then export them and group them later when exported by set id.



          Example:



          enter image description here



          create a sample graph



          MERGE (nAlice:User {id:'Alice'})
          MERGE (nBridget:User {id:'Bridget'})
          MERGE (nCharles:User {id:'Charles'})
          MERGE (nDoug:User {id:'Doug'})
          MERGE (nMark:User {id:'Mark'})
          MERGE (nMichael:User {id:'Michael'})

          MERGE (nAlice)-[:FRIEND]->(nBridget)
          MERGE (nAlice)-[:FRIEND]->(nCharles)
          MERGE (nMark)-[:FRIEND]->(nDoug)
          MERGE (nMark)-[:FRIEND]->(nMichael);


          Run connected components (unionFind) algorithm and return nodes in the same subgraph:



          CALL algo.unionFind.stream('User', 'FRIEND', {})
          YIELD nodeId,setId
          RETURN setId,collect(algo.getNodeById(nodeId)) AS nodes_from_specific_subgraph


          This will return:



          ╒═══════╤══════════════════════════════════════════════════╕
          │"setId"│"specific_subgraph" │
          ╞═══════╪══════════════════════════════════════════════════╡
          │4 │[{"id":"Doug"},{"id":"Mark"},{"id":"Michael"}] │
          ├───────┼──────────────────────────────────────────────────┤
          │0 │[{"id":"Alice"},{"id":"Bridget"},{"id":"Charles"}]│
          └───────┴──────────────────────────────────────────────────┘





          share|improve this answer















          You could use graph algorithms plugin and specifically connected components algorithm to label all the isolated subgraphs in your graph and then export them and group them later when exported by set id.



          Example:



          enter image description here



          create a sample graph



          MERGE (nAlice:User {id:'Alice'})
          MERGE (nBridget:User {id:'Bridget'})
          MERGE (nCharles:User {id:'Charles'})
          MERGE (nDoug:User {id:'Doug'})
          MERGE (nMark:User {id:'Mark'})
          MERGE (nMichael:User {id:'Michael'})

          MERGE (nAlice)-[:FRIEND]->(nBridget)
          MERGE (nAlice)-[:FRIEND]->(nCharles)
          MERGE (nMark)-[:FRIEND]->(nDoug)
          MERGE (nMark)-[:FRIEND]->(nMichael);


          Run connected components (unionFind) algorithm and return nodes in the same subgraph:



          CALL algo.unionFind.stream('User', 'FRIEND', {})
          YIELD nodeId,setId
          RETURN setId,collect(algo.getNodeById(nodeId)) AS nodes_from_specific_subgraph


          This will return:



          ╒═══════╤══════════════════════════════════════════════════╕
          │"setId"│"specific_subgraph" │
          ╞═══════╪══════════════════════════════════════════════════╡
          │4 │[{"id":"Doug"},{"id":"Mark"},{"id":"Michael"}] │
          ├───────┼──────────────────────────────────────────────────┤
          │0 │[{"id":"Alice"},{"id":"Bridget"},{"id":"Charles"}]│
          └───────┴──────────────────────────────────────────────────┘






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 23 '18 at 19:50

























          answered Nov 23 '18 at 14:26









          Tomaž BrataničTomaž Bratanič

          1,9472820




          1,9472820













          • added an example

            – Tomaž Bratanič
            Nov 23 '18 at 19:50











          • Thank you! I wasn't familiar with the graph lgorithm plugin. I have followed your example and that worked for me!

            – Dan
            Nov 24 '18 at 10:19



















          • added an example

            – Tomaž Bratanič
            Nov 23 '18 at 19:50











          • Thank you! I wasn't familiar with the graph lgorithm plugin. I have followed your example and that worked for me!

            – Dan
            Nov 24 '18 at 10:19

















          added an example

          – Tomaž Bratanič
          Nov 23 '18 at 19:50





          added an example

          – Tomaž Bratanič
          Nov 23 '18 at 19:50













          Thank you! I wasn't familiar with the graph lgorithm plugin. I have followed your example and that worked for me!

          – Dan
          Nov 24 '18 at 10:19





          Thank you! I wasn't familiar with the graph lgorithm plugin. I have followed your example and that worked for me!

          – Dan
          Nov 24 '18 at 10:19




















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53447957%2fneo4j-extract-all-subgraphs-from-neo4j-database%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          "Incorrect syntax near the keyword 'ON'. (on update cascade, on delete cascade,)

          Alcedinidae

          RAC Tourist Trophy