Why can methods be overriden but attributes can't?





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14















I have a class



public class A {
public String attr ="A attribute";
public void method() {
System.out.println(this+" , "+this.attr);
}
public String toString() {
return("Object A");
}
}


and another class that inherits from it



public class B extends A{
public String attr = "B attribute";
public void method() {
super.method();
}
public String toString() {
return("Object B");
}
}


Note that the method() of B is simply a wrapper for method() of A.



When I run the following code



B b = new B();
b.method();


I get Object B , A attribute as output which means that, this and this.attr accessed different things. Why is that the case?



Shouldn't System.out.println(this) refer to the toString() method of class A ?










share|improve this question




















  • 1





    A modern IDE will have the possibility to show a warning on the second definition of attr that it 'shadows' a similarly named field of a superclass.

    – Mark Jeronimus
    Mar 27 at 15:49











  • @Noah why did you revert the edited question name? I think the edited title Why can methods be overriden but attributes can't described the content of the question better than the current one. This is important for all other people looking for an answer to their question.

    – Ondra K.
    Mar 28 at 12:20


















14















I have a class



public class A {
public String attr ="A attribute";
public void method() {
System.out.println(this+" , "+this.attr);
}
public String toString() {
return("Object A");
}
}


and another class that inherits from it



public class B extends A{
public String attr = "B attribute";
public void method() {
super.method();
}
public String toString() {
return("Object B");
}
}


Note that the method() of B is simply a wrapper for method() of A.



When I run the following code



B b = new B();
b.method();


I get Object B , A attribute as output which means that, this and this.attr accessed different things. Why is that the case?



Shouldn't System.out.println(this) refer to the toString() method of class A ?










share|improve this question




















  • 1





    A modern IDE will have the possibility to show a warning on the second definition of attr that it 'shadows' a similarly named field of a superclass.

    – Mark Jeronimus
    Mar 27 at 15:49











  • @Noah why did you revert the edited question name? I think the edited title Why can methods be overriden but attributes can't described the content of the question better than the current one. This is important for all other people looking for an answer to their question.

    – Ondra K.
    Mar 28 at 12:20














14












14








14


6






I have a class



public class A {
public String attr ="A attribute";
public void method() {
System.out.println(this+" , "+this.attr);
}
public String toString() {
return("Object A");
}
}


and another class that inherits from it



public class B extends A{
public String attr = "B attribute";
public void method() {
super.method();
}
public String toString() {
return("Object B");
}
}


Note that the method() of B is simply a wrapper for method() of A.



When I run the following code



B b = new B();
b.method();


I get Object B , A attribute as output which means that, this and this.attr accessed different things. Why is that the case?



Shouldn't System.out.println(this) refer to the toString() method of class A ?










share|improve this question
















I have a class



public class A {
public String attr ="A attribute";
public void method() {
System.out.println(this+" , "+this.attr);
}
public String toString() {
return("Object A");
}
}


and another class that inherits from it



public class B extends A{
public String attr = "B attribute";
public void method() {
super.method();
}
public String toString() {
return("Object B");
}
}


Note that the method() of B is simply a wrapper for method() of A.



When I run the following code



B b = new B();
b.method();


I get Object B , A attribute as output which means that, this and this.attr accessed different things. Why is that the case?



Shouldn't System.out.println(this) refer to the toString() method of class A ?







java inheritance this






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 28 at 20:00









Ondra K.

1,016726




1,016726










asked Mar 27 at 14:44









Noah BishopNoah Bishop

1138




1138








  • 1





    A modern IDE will have the possibility to show a warning on the second definition of attr that it 'shadows' a similarly named field of a superclass.

    – Mark Jeronimus
    Mar 27 at 15:49











  • @Noah why did you revert the edited question name? I think the edited title Why can methods be overriden but attributes can't described the content of the question better than the current one. This is important for all other people looking for an answer to their question.

    – Ondra K.
    Mar 28 at 12:20














  • 1





    A modern IDE will have the possibility to show a warning on the second definition of attr that it 'shadows' a similarly named field of a superclass.

    – Mark Jeronimus
    Mar 27 at 15:49











  • @Noah why did you revert the edited question name? I think the edited title Why can methods be overriden but attributes can't described the content of the question better than the current one. This is important for all other people looking for an answer to their question.

    – Ondra K.
    Mar 28 at 12:20








1




1





A modern IDE will have the possibility to show a warning on the second definition of attr that it 'shadows' a similarly named field of a superclass.

– Mark Jeronimus
Mar 27 at 15:49





A modern IDE will have the possibility to show a warning on the second definition of attr that it 'shadows' a similarly named field of a superclass.

– Mark Jeronimus
Mar 27 at 15:49













@Noah why did you revert the edited question name? I think the edited title Why can methods be overriden but attributes can't described the content of the question better than the current one. This is important for all other people looking for an answer to their question.

– Ondra K.
Mar 28 at 12:20





@Noah why did you revert the edited question name? I think the edited title Why can methods be overriden but attributes can't described the content of the question better than the current one. This is important for all other people looking for an answer to their question.

– Ondra K.
Mar 28 at 12:20












1 Answer
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14














By declaring a method with a same name as parent class, you override it, that is, replace the original behaviour. But if you declare a field with a same name, you effectively hide it, making it inaccessible from that subclass, but only by super.field. See oracle docs on variable hiding, as well as using the keyword super. Note that it is not recommended to use variable hiding, as it creates exactly the kind of confusion you're experiencing.



By calling super.method(), printing this results in calling the toString method, which was in fact overridden - so that's the reason why it prints "Object B", as you've called the method on an instance of B. But the this in this.attr actually refers to the parent object, as you're calling the method from the parent class (by super.method()).






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    14














    By declaring a method with a same name as parent class, you override it, that is, replace the original behaviour. But if you declare a field with a same name, you effectively hide it, making it inaccessible from that subclass, but only by super.field. See oracle docs on variable hiding, as well as using the keyword super. Note that it is not recommended to use variable hiding, as it creates exactly the kind of confusion you're experiencing.



    By calling super.method(), printing this results in calling the toString method, which was in fact overridden - so that's the reason why it prints "Object B", as you've called the method on an instance of B. But the this in this.attr actually refers to the parent object, as you're calling the method from the parent class (by super.method()).






    share|improve this answer






























      14














      By declaring a method with a same name as parent class, you override it, that is, replace the original behaviour. But if you declare a field with a same name, you effectively hide it, making it inaccessible from that subclass, but only by super.field. See oracle docs on variable hiding, as well as using the keyword super. Note that it is not recommended to use variable hiding, as it creates exactly the kind of confusion you're experiencing.



      By calling super.method(), printing this results in calling the toString method, which was in fact overridden - so that's the reason why it prints "Object B", as you've called the method on an instance of B. But the this in this.attr actually refers to the parent object, as you're calling the method from the parent class (by super.method()).






      share|improve this answer




























        14












        14








        14







        By declaring a method with a same name as parent class, you override it, that is, replace the original behaviour. But if you declare a field with a same name, you effectively hide it, making it inaccessible from that subclass, but only by super.field. See oracle docs on variable hiding, as well as using the keyword super. Note that it is not recommended to use variable hiding, as it creates exactly the kind of confusion you're experiencing.



        By calling super.method(), printing this results in calling the toString method, which was in fact overridden - so that's the reason why it prints "Object B", as you've called the method on an instance of B. But the this in this.attr actually refers to the parent object, as you're calling the method from the parent class (by super.method()).






        share|improve this answer















        By declaring a method with a same name as parent class, you override it, that is, replace the original behaviour. But if you declare a field with a same name, you effectively hide it, making it inaccessible from that subclass, but only by super.field. See oracle docs on variable hiding, as well as using the keyword super. Note that it is not recommended to use variable hiding, as it creates exactly the kind of confusion you're experiencing.



        By calling super.method(), printing this results in calling the toString method, which was in fact overridden - so that's the reason why it prints "Object B", as you've called the method on an instance of B. But the this in this.attr actually refers to the parent object, as you're calling the method from the parent class (by super.method()).







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Mar 27 at 15:15

























        answered Mar 27 at 14:49









        Ondra K.Ondra K.

        1,016726




        1,016726
































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