Regex find second / and count 5 characters onwards












1














Is there a way to find and replace using regex here? I want to find the second /, then count 5 characters father and remove these 5 characters.



This:



fhp/wa_od/11111_picx

a_wpu/hxpokpa/HW18H_wdij

awo/p8i_dxawp/KW920poij_m


Should become this:



fhp/wa_od/_picx

a_wpu/hxpokpa/_wdij

awo/p8i_dxawp/poij_m





regex







share|improve this question






















  • Which language or tool are you using?
    – RAN_0915
    Nov 20 at 5:45
















1














Is there a way to find and replace using regex here? I want to find the second /, then count 5 characters father and remove these 5 characters.



This:



fhp/wa_od/11111_picx

a_wpu/hxpokpa/HW18H_wdij

awo/p8i_dxawp/KW920poij_m


Should become this:



fhp/wa_od/_picx

a_wpu/hxpokpa/_wdij

awo/p8i_dxawp/poij_m





regex







share|improve this question






















  • Which language or tool are you using?
    – RAN_0915
    Nov 20 at 5:45














1












1








1







Is there a way to find and replace using regex here? I want to find the second /, then count 5 characters father and remove these 5 characters.



This:



fhp/wa_od/11111_picx

a_wpu/hxpokpa/HW18H_wdij

awo/p8i_dxawp/KW920poij_m


Should become this:



fhp/wa_od/_picx

a_wpu/hxpokpa/_wdij

awo/p8i_dxawp/poij_m





regex







share|improve this question













Is there a way to find and replace using regex here? I want to find the second /, then count 5 characters father and remove these 5 characters.



This:



fhp/wa_od/11111_picx

a_wpu/hxpokpa/HW18H_wdij

awo/p8i_dxawp/KW920poij_m


Should become this:



fhp/wa_od/_picx

a_wpu/hxpokpa/_wdij

awo/p8i_dxawp/poij_m





regex




regex






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 20 at 5:35









Freddy Bonda

11110




11110












  • Which language or tool are you using?
    – RAN_0915
    Nov 20 at 5:45


















  • Which language or tool are you using?
    – RAN_0915
    Nov 20 at 5:45
















Which language or tool are you using?
– RAN_0915
Nov 20 at 5:45




Which language or tool are you using?
– RAN_0915
Nov 20 at 5:45












2 Answers
2






active

oldest

votes


















2














You can use this regex which captures some optional text followed by /, whole of this pattern two times and groups them in group1, then captures 5 characters next to it and then groups remaining characters after those five characters in group2 and finally replaces by whatever matched by group1 and group2.



((?:.*?/){2}).{5}(.*)


Replace it with 12



Demo






share|improve this answer

















  • 1




    Perfect. Thank you :)
    – Freddy Bonda
    Nov 20 at 6:18










  • Pleased to help :)
    – Pushpesh Kumar Rajwanshi
    Nov 20 at 6:19



















0














You can use the folowing regex:



/(w+?/w+?/).{5}(.*)/g


It creates a capturing Group that matches one or more Word characters, followed by a slash, then again one or more Word character, followed by a slash. Then it matches 5 of any character, followed by a Group that matches the rest.



You then replace with:



$1$2 (or in some regex flavors: 12)





share|improve this answer





















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    2 Answers
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    2 Answers
    2






    active

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    active

    oldest

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    2














    You can use this regex which captures some optional text followed by /, whole of this pattern two times and groups them in group1, then captures 5 characters next to it and then groups remaining characters after those five characters in group2 and finally replaces by whatever matched by group1 and group2.



    ((?:.*?/){2}).{5}(.*)


    Replace it with 12



    Demo






    share|improve this answer

















    • 1




      Perfect. Thank you :)
      – Freddy Bonda
      Nov 20 at 6:18










    • Pleased to help :)
      – Pushpesh Kumar Rajwanshi
      Nov 20 at 6:19
















    2














    You can use this regex which captures some optional text followed by /, whole of this pattern two times and groups them in group1, then captures 5 characters next to it and then groups remaining characters after those five characters in group2 and finally replaces by whatever matched by group1 and group2.



    ((?:.*?/){2}).{5}(.*)


    Replace it with 12



    Demo






    share|improve this answer

















    • 1




      Perfect. Thank you :)
      – Freddy Bonda
      Nov 20 at 6:18










    • Pleased to help :)
      – Pushpesh Kumar Rajwanshi
      Nov 20 at 6:19














    2












    2








    2






    You can use this regex which captures some optional text followed by /, whole of this pattern two times and groups them in group1, then captures 5 characters next to it and then groups remaining characters after those five characters in group2 and finally replaces by whatever matched by group1 and group2.



    ((?:.*?/){2}).{5}(.*)


    Replace it with 12



    Demo






    share|improve this answer












    You can use this regex which captures some optional text followed by /, whole of this pattern two times and groups them in group1, then captures 5 characters next to it and then groups remaining characters after those five characters in group2 and finally replaces by whatever matched by group1 and group2.



    ((?:.*?/){2}).{5}(.*)


    Replace it with 12



    Demo







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 20 at 6:01









    Pushpesh Kumar Rajwanshi

    5,1461827




    5,1461827








    • 1




      Perfect. Thank you :)
      – Freddy Bonda
      Nov 20 at 6:18










    • Pleased to help :)
      – Pushpesh Kumar Rajwanshi
      Nov 20 at 6:19














    • 1




      Perfect. Thank you :)
      – Freddy Bonda
      Nov 20 at 6:18










    • Pleased to help :)
      – Pushpesh Kumar Rajwanshi
      Nov 20 at 6:19








    1




    1




    Perfect. Thank you :)
    – Freddy Bonda
    Nov 20 at 6:18




    Perfect. Thank you :)
    – Freddy Bonda
    Nov 20 at 6:18












    Pleased to help :)
    – Pushpesh Kumar Rajwanshi
    Nov 20 at 6:19




    Pleased to help :)
    – Pushpesh Kumar Rajwanshi
    Nov 20 at 6:19













    0














    You can use the folowing regex:



    /(w+?/w+?/).{5}(.*)/g


    It creates a capturing Group that matches one or more Word characters, followed by a slash, then again one or more Word character, followed by a slash. Then it matches 5 of any character, followed by a Group that matches the rest.



    You then replace with:



    $1$2 (or in some regex flavors: 12)





    share|improve this answer


























      0














      You can use the folowing regex:



      /(w+?/w+?/).{5}(.*)/g


      It creates a capturing Group that matches one or more Word characters, followed by a slash, then again one or more Word character, followed by a slash. Then it matches 5 of any character, followed by a Group that matches the rest.



      You then replace with:



      $1$2 (or in some regex flavors: 12)





      share|improve this answer
























        0












        0








        0






        You can use the folowing regex:



        /(w+?/w+?/).{5}(.*)/g


        It creates a capturing Group that matches one or more Word characters, followed by a slash, then again one or more Word character, followed by a slash. Then it matches 5 of any character, followed by a Group that matches the rest.



        You then replace with:



        $1$2 (or in some regex flavors: 12)





        share|improve this answer












        You can use the folowing regex:



        /(w+?/w+?/).{5}(.*)/g


        It creates a capturing Group that matches one or more Word characters, followed by a slash, then again one or more Word character, followed by a slash. Then it matches 5 of any character, followed by a Group that matches the rest.



        You then replace with:



        $1$2 (or in some regex flavors: 12)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 at 6:09









        Poul Bak

        5,43331132




        5,43331132






























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