Replacing each letter wich another letter












0















I am wondering how to replace each letter of a string with another letter. For example A -> D.



I have tried using .replace() (repeating it in each line for every letter) but when I replace the letter A with the letter D and then try to replace the letter D with the letter H it just replaces the letter A twice so instead of AD -> DH I end up with AD -> HH.



Im sure there is a better and simpler way of doing this.



Thank you in advance.






javascript node.js







share|improve this question



























    0















    I am wondering how to replace each letter of a string with another letter. For example A -> D.



    I have tried using .replace() (repeating it in each line for every letter) but when I replace the letter A with the letter D and then try to replace the letter D with the letter H it just replaces the letter A twice so instead of AD -> DH I end up with AD -> HH.



    Im sure there is a better and simpler way of doing this.



    Thank you in advance.






    javascript node.js







    share|improve this question

























      0












      0








      0








      I am wondering how to replace each letter of a string with another letter. For example A -> D.



      I have tried using .replace() (repeating it in each line for every letter) but when I replace the letter A with the letter D and then try to replace the letter D with the letter H it just replaces the letter A twice so instead of AD -> DH I end up with AD -> HH.



      Im sure there is a better and simpler way of doing this.



      Thank you in advance.






      javascript node.js







      share|improve this question














      I am wondering how to replace each letter of a string with another letter. For example A -> D.



      I have tried using .replace() (repeating it in each line for every letter) but when I replace the letter A with the letter D and then try to replace the letter D with the letter H it just replaces the letter A twice so instead of AD -> DH I end up with AD -> HH.



      Im sure there is a better and simpler way of doing this.



      Thank you in advance.






      javascript node.js




      javascript node.js






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 20 '18 at 18:51









      Artur DudekArtur Dudek

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          Build up a dictionary:



           const dict = { A: "D", D: "A", /*...*/ };


          Then split the string into an array, map that to a new array by applying the replacement and join the array back to a string:



           const output = input.split("").map(char => dict[char]).join("");





          share|improve this answer



















          • 2





            You may also use the replace method directly like so: input.replace(/./g, c => dict[c] || c).

            – Elias Toivanen
            Nov 20 '18 at 19:09











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          1 Answer
          1






          active

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          active

          oldest

          votes






          active

          oldest

          votes









          2














          Build up a dictionary:



           const dict = { A: "D", D: "A", /*...*/ };


          Then split the string into an array, map that to a new array by applying the replacement and join the array back to a string:



           const output = input.split("").map(char => dict[char]).join("");





          share|improve this answer



















          • 2





            You may also use the replace method directly like so: input.replace(/./g, c => dict[c] || c).

            – Elias Toivanen
            Nov 20 '18 at 19:09
















          2














          Build up a dictionary:



           const dict = { A: "D", D: "A", /*...*/ };


          Then split the string into an array, map that to a new array by applying the replacement and join the array back to a string:



           const output = input.split("").map(char => dict[char]).join("");





          share|improve this answer



















          • 2





            You may also use the replace method directly like so: input.replace(/./g, c => dict[c] || c).

            – Elias Toivanen
            Nov 20 '18 at 19:09














          2












          2








          2







          Build up a dictionary:



           const dict = { A: "D", D: "A", /*...*/ };


          Then split the string into an array, map that to a new array by applying the replacement and join the array back to a string:



           const output = input.split("").map(char => dict[char]).join("");





          share|improve this answer













          Build up a dictionary:



           const dict = { A: "D", D: "A", /*...*/ };


          Then split the string into an array, map that to a new array by applying the replacement and join the array back to a string:



           const output = input.split("").map(char => dict[char]).join("");






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 '18 at 18:54









          Jonas WilmsJonas Wilms

          56k42851




          56k42851








          • 2





            You may also use the replace method directly like so: input.replace(/./g, c => dict[c] || c).

            – Elias Toivanen
            Nov 20 '18 at 19:09














          • 2





            You may also use the replace method directly like so: input.replace(/./g, c => dict[c] || c).

            – Elias Toivanen
            Nov 20 '18 at 19:09








          2




          2





          You may also use the replace method directly like so: input.replace(/./g, c => dict[c] || c).

          – Elias Toivanen
          Nov 20 '18 at 19:09





          You may also use the replace method directly like so: input.replace(/./g, c => dict[c] || c).

          – Elias Toivanen
          Nov 20 '18 at 19:09


















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