InvocableMethod Through anonymous APEX












3















I have an invocablemethod that runs from a process builder that got broken for a few months I had a mapping issue and some fields didn't populate or create for various reasons. In the process builder you only need to pass the Opportunity Id and a string variable and it does the work.



I want to fix my error and pass in Opportunity Ids directly to the method however, I can't figure out how to populate the data to do it.



Example: 



@InvocableMethod(label='Perform Mapping' description='Performs a ConvertAnything mapping given a list of records.')

global static void generateAndInsertAllRecords(List<ContextRecord> contextRecords)

{

   // do stuff

}


ContextRecord is defined here:



global class SL_Mapping_Handler extends SL_Mapping_Handler_Helper {



// used for determining which records to perform the mapping from

global class ContextRecord {

    @InvocableVariable(label='Id' required=true)

    global Id Id;

    @InvocableVariable(label='Custom Mapping Identifier')

    global String customMappingIdentifier;

}


I'm in anon apex trying to do something like this:



SL_Mapping_Handler.ContextRecord cr = new SL_MApping_Handler.ContextRecord();

cr.Id = '006A000000YN0gd';

cr.customMappingIdentifier = 'Opp Auto Renewal';



List<ContextRecord> l = new List<ContextRecord>();

l.add(cr);

SL_Mapping_Handler.generateAndInsertAllRecords(l);


But I get an error:




Line: 3, Column: 1 Invalid type: ContextRecord




Is this possible to do? Is it just a syntax error?






apex invocable-method







share|improve this question





























    3















    I have an invocablemethod that runs from a process builder that got broken for a few months I had a mapping issue and some fields didn't populate or create for various reasons. In the process builder you only need to pass the Opportunity Id and a string variable and it does the work.



    I want to fix my error and pass in Opportunity Ids directly to the method however, I can't figure out how to populate the data to do it.



    Example: 



    @InvocableMethod(label='Perform Mapping' description='Performs a ConvertAnything mapping given a list of records.')
    
global static void generateAndInsertAllRecords(List<ContextRecord> contextRecords)
    
{
    
   // do stuff
    
}


    ContextRecord is defined here:



    global class SL_Mapping_Handler extends SL_Mapping_Handler_Helper {
    

    
// used for determining which records to perform the mapping from
    
global class ContextRecord {
    
    @InvocableVariable(label='Id' required=true)
    
    global Id Id;
    
    @InvocableVariable(label='Custom Mapping Identifier')
    
    global String customMappingIdentifier;
    
}


    I'm in anon apex trying to do something like this:



    SL_Mapping_Handler.ContextRecord cr = new SL_MApping_Handler.ContextRecord();
    
cr.Id = '006A000000YN0gd';
    
cr.customMappingIdentifier = 'Opp Auto Renewal';
    

    
List<ContextRecord> l = new List<ContextRecord>();
    
l.add(cr);
    
SL_Mapping_Handler.generateAndInsertAllRecords(l);


    But I get an error:




    Line: 3, Column: 1 Invalid type: ContextRecord




    Is this possible to do? Is it just a syntax error?






    apex invocable-method







    share|improve this question



























      3












      3








      3








      I have an invocablemethod that runs from a process builder that got broken for a few months I had a mapping issue and some fields didn't populate or create for various reasons. In the process builder you only need to pass the Opportunity Id and a string variable and it does the work.



      I want to fix my error and pass in Opportunity Ids directly to the method however, I can't figure out how to populate the data to do it.



      Example: 



      @InvocableMethod(label='Perform Mapping' description='Performs a ConvertAnything mapping given a list of records.')
      
global static void generateAndInsertAllRecords(List<ContextRecord> contextRecords)
      
{
      
   // do stuff
      
}


      ContextRecord is defined here:



      global class SL_Mapping_Handler extends SL_Mapping_Handler_Helper {
      

      
// used for determining which records to perform the mapping from
      
global class ContextRecord {
      
    @InvocableVariable(label='Id' required=true)
      
    global Id Id;
      
    @InvocableVariable(label='Custom Mapping Identifier')
      
    global String customMappingIdentifier;
      
}


      I'm in anon apex trying to do something like this:



      SL_Mapping_Handler.ContextRecord cr = new SL_MApping_Handler.ContextRecord();
      
cr.Id = '006A000000YN0gd';
      
cr.customMappingIdentifier = 'Opp Auto Renewal';
      

      
List<ContextRecord> l = new List<ContextRecord>();
      
l.add(cr);
      
SL_Mapping_Handler.generateAndInsertAllRecords(l);


      But I get an error:




      Line: 3, Column: 1 Invalid type: ContextRecord




      Is this possible to do? Is it just a syntax error?






      apex invocable-method







      share|improve this question
















      I have an invocablemethod that runs from a process builder that got broken for a few months I had a mapping issue and some fields didn't populate or create for various reasons. In the process builder you only need to pass the Opportunity Id and a string variable and it does the work.



      I want to fix my error and pass in Opportunity Ids directly to the method however, I can't figure out how to populate the data to do it.



      Example: 



      @InvocableMethod(label='Perform Mapping' description='Performs a ConvertAnything mapping given a list of records.')
      
global static void generateAndInsertAllRecords(List<ContextRecord> contextRecords)
      
{
      
   // do stuff
      
}


      ContextRecord is defined here:



      global class SL_Mapping_Handler extends SL_Mapping_Handler_Helper {
      

      
// used for determining which records to perform the mapping from
      
global class ContextRecord {
      
    @InvocableVariable(label='Id' required=true)
      
    global Id Id;
      
    @InvocableVariable(label='Custom Mapping Identifier')
      
    global String customMappingIdentifier;
      
}


      I'm in anon apex trying to do something like this:



      SL_Mapping_Handler.ContextRecord cr = new SL_MApping_Handler.ContextRecord();
      
cr.Id = '006A000000YN0gd';
      
cr.customMappingIdentifier = 'Opp Auto Renewal';
      

      
List<ContextRecord> l = new List<ContextRecord>();
      
l.add(cr);
      
SL_Mapping_Handler.generateAndInsertAllRecords(l);


      But I get an error:




      Line: 3, Column: 1 Invalid type: ContextRecord




      Is this possible to do? Is it just a syntax error?






      apex invocable-method




      apex invocable-method






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 11 hours ago









      Adrian Larson♦

      108k19115243




      108k19115243










      asked 11 hours ago









      Dan WoodingDan Wooding

      1,9671137




      1,9671137






















          1 Answer
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          4














          You will need to declare the list in your snippet as:



          List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();


          Replaces:



          List<ContextRecord> l = new List<ContextRecord>();





          share|improve this answer





















          • 1





            Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're inside SL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.

            – Derek F
            11 hours ago











          Your Answer








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          1 Answer
          1






          active

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          oldest

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          active

          oldest

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          4














          You will need to declare the list in your snippet as:



          List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();


          Replaces:



          List<ContextRecord> l = new List<ContextRecord>();





          share|improve this answer





















          • 1





            Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're inside SL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.

            – Derek F
            11 hours ago
















          4














          You will need to declare the list in your snippet as:



          List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();


          Replaces:



          List<ContextRecord> l = new List<ContextRecord>();





          share|improve this answer





















          • 1





            Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're inside SL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.

            – Derek F
            11 hours ago














          4












          4








          4







          You will need to declare the list in your snippet as:



          List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();


          Replaces:



          List<ContextRecord> l = new List<ContextRecord>();





          share|improve this answer















          You will need to declare the list in your snippet as:



          List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();


          Replaces:



          List<ContextRecord> l = new List<ContextRecord>();






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 11 hours ago









          Daniel Ballinger

          73k15149394




          73k15149394










          answered 11 hours ago









          Jayant DasJayant Das

          14.3k2824




          14.3k2824








          • 1





            Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're inside SL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.

            – Derek F
            11 hours ago














          • 1





            Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're inside SL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.

            – Derek F
            11 hours ago








          1




          1





          Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're inside SL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.

          – Derek F
          11 hours ago





          Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're inside SL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.

          – Derek F
          11 hours ago


















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