Allow to create mutilple model from foreign key in one view (with generic createview)
With django, I'm looking for a way to create easily a model which point to another models using Foreign Key in only one view using the generic create view.
with an example, it should be easier to understant..
models.py
# models.py
from django.contrib.auth.models import User
class Group(models.Model):
name = models.CharField(
_("Group name"), max_length=128, blank=False, null=False)
comment = models.TextField(max_length=512, blank=False, null=False)
def get_absolute_url(self):
return reverse('group_detail', kwargs={'pk': self.pk})
def __str__(self):
return _("%(name)s Group") % {'name': self.name}
class UserAcl(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE)
group = models.ForeignKey(Group, blank=True, null=True, on_delete=models.SET_NULL)
comment = models.CharField(
_("comment"), max_length=128, blank=False, null=False)
views.py
# views.py
class SettingsView(LoginRequiredMixin, UserPassesTestMixin, generic.ListView):
model = UserAcl
template_name = 'my_app/settings.html'
When I display that view, I would like to access to all fields from User django class, all fields from Group class and of course all fields from UserAcl class.
So 3 objects will be created in one time :
- User
- Group
- and UserAcl.
Whereas currently, only 3 fields are visible (those from UserAcl) with the choice of User/Group which are already in DB.
How can I do that? can you help/suggest me ?
Thx
django django-generic-views
add a comment |
With django, I'm looking for a way to create easily a model which point to another models using Foreign Key in only one view using the generic create view.
with an example, it should be easier to understant..
models.py
# models.py
from django.contrib.auth.models import User
class Group(models.Model):
name = models.CharField(
_("Group name"), max_length=128, blank=False, null=False)
comment = models.TextField(max_length=512, blank=False, null=False)
def get_absolute_url(self):
return reverse('group_detail', kwargs={'pk': self.pk})
def __str__(self):
return _("%(name)s Group") % {'name': self.name}
class UserAcl(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE)
group = models.ForeignKey(Group, blank=True, null=True, on_delete=models.SET_NULL)
comment = models.CharField(
_("comment"), max_length=128, blank=False, null=False)
views.py
# views.py
class SettingsView(LoginRequiredMixin, UserPassesTestMixin, generic.ListView):
model = UserAcl
template_name = 'my_app/settings.html'
When I display that view, I would like to access to all fields from User django class, all fields from Group class and of course all fields from UserAcl class.
So 3 objects will be created in one time :
- User
- Group
- and UserAcl.
Whereas currently, only 3 fields are visible (those from UserAcl) with the choice of User/Group which are already in DB.
How can I do that? can you help/suggest me ?
Thx
django django-generic-views
add a comment |
With django, I'm looking for a way to create easily a model which point to another models using Foreign Key in only one view using the generic create view.
with an example, it should be easier to understant..
models.py
# models.py
from django.contrib.auth.models import User
class Group(models.Model):
name = models.CharField(
_("Group name"), max_length=128, blank=False, null=False)
comment = models.TextField(max_length=512, blank=False, null=False)
def get_absolute_url(self):
return reverse('group_detail', kwargs={'pk': self.pk})
def __str__(self):
return _("%(name)s Group") % {'name': self.name}
class UserAcl(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE)
group = models.ForeignKey(Group, blank=True, null=True, on_delete=models.SET_NULL)
comment = models.CharField(
_("comment"), max_length=128, blank=False, null=False)
views.py
# views.py
class SettingsView(LoginRequiredMixin, UserPassesTestMixin, generic.ListView):
model = UserAcl
template_name = 'my_app/settings.html'
When I display that view, I would like to access to all fields from User django class, all fields from Group class and of course all fields from UserAcl class.
So 3 objects will be created in one time :
- User
- Group
- and UserAcl.
Whereas currently, only 3 fields are visible (those from UserAcl) with the choice of User/Group which are already in DB.
How can I do that? can you help/suggest me ?
Thx
django django-generic-views
With django, I'm looking for a way to create easily a model which point to another models using Foreign Key in only one view using the generic create view.
with an example, it should be easier to understant..
models.py
# models.py
from django.contrib.auth.models import User
class Group(models.Model):
name = models.CharField(
_("Group name"), max_length=128, blank=False, null=False)
comment = models.TextField(max_length=512, blank=False, null=False)
def get_absolute_url(self):
return reverse('group_detail', kwargs={'pk': self.pk})
def __str__(self):
return _("%(name)s Group") % {'name': self.name}
class UserAcl(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE)
group = models.ForeignKey(Group, blank=True, null=True, on_delete=models.SET_NULL)
comment = models.CharField(
_("comment"), max_length=128, blank=False, null=False)
views.py
# views.py
class SettingsView(LoginRequiredMixin, UserPassesTestMixin, generic.ListView):
model = UserAcl
template_name = 'my_app/settings.html'
When I display that view, I would like to access to all fields from User django class, all fields from Group class and of course all fields from UserAcl class.
So 3 objects will be created in one time :
- User
- Group
- and UserAcl.
Whereas currently, only 3 fields are visible (those from UserAcl) with the choice of User/Group which are already in DB.
How can I do that? can you help/suggest me ?
Thx
django django-generic-views
django django-generic-views
edited Nov 23 '18 at 8:51
Tounnbounn
asked Nov 22 '18 at 14:35
TounnbounnTounnbounn
63
63
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53433218%2fallow-to-create-mutilple-model-from-foreign-key-in-one-view-with-generic-create%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53433218%2fallow-to-create-mutilple-model-from-foreign-key-in-one-view-with-generic-create%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown