how open image with url in javafx
I have banner an I wont to put it in my javaFX application.
And when user click on the image open default browser.
try {
String path = "http://developer.am/webservice/banner728x90.gif";
URL url = new URL(path);
BufferedImage image = ImageIO.read(url);
label = new JLabel(new ImageIcon(image));
} catch (Exception exp) {
exp.printStackTrace();
}
also I am trying to convert above code from awt in JavaFX
javafx
add a comment |
I have banner an I wont to put it in my javaFX application.
And when user click on the image open default browser.
try {
String path = "http://developer.am/webservice/banner728x90.gif";
URL url = new URL(path);
BufferedImage image = ImageIO.read(url);
label = new JLabel(new ImageIcon(image));
} catch (Exception exp) {
exp.printStackTrace();
}
also I am trying to convert above code from awt in JavaFX
javafx
add a comment |
I have banner an I wont to put it in my javaFX application.
And when user click on the image open default browser.
try {
String path = "http://developer.am/webservice/banner728x90.gif";
URL url = new URL(path);
BufferedImage image = ImageIO.read(url);
label = new JLabel(new ImageIcon(image));
} catch (Exception exp) {
exp.printStackTrace();
}
also I am trying to convert above code from awt in JavaFX
javafx
I have banner an I wont to put it in my javaFX application.
And when user click on the image open default browser.
try {
String path = "http://developer.am/webservice/banner728x90.gif";
URL url = new URL(path);
BufferedImage image = ImageIO.read(url);
label = new JLabel(new ImageIcon(image));
} catch (Exception exp) {
exp.printStackTrace();
}
also I am trying to convert above code from awt in JavaFX
javafx
javafx
asked Nov 17 '14 at 13:32
Hayk HarutyunyanHayk Harutyunyan
52115
52115
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Lets see. First the ingredients:
- Image
- Button
- ImageView
- Open Link in System Browser with JavaFX
Putting this together:
String path = "http://...";
String pathToOpen = "http://...";
Image image = new Image(path);
ImageView imageView = new ImageView(image);
Button button = new Button("clickMe!", imageView);
button.setOnAction(ev -> getHostServices().showDocument(pathToOpen));
thanks, very helpfull
– Hayk Harutyunyan
Nov 18 '14 at 6:27
No problem. And if this answers your question, please mark this answer accordingly ;-)
– eckig
Nov 18 '14 at 7:15
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Lets see. First the ingredients:
- Image
- Button
- ImageView
- Open Link in System Browser with JavaFX
Putting this together:
String path = "http://...";
String pathToOpen = "http://...";
Image image = new Image(path);
ImageView imageView = new ImageView(image);
Button button = new Button("clickMe!", imageView);
button.setOnAction(ev -> getHostServices().showDocument(pathToOpen));
thanks, very helpfull
– Hayk Harutyunyan
Nov 18 '14 at 6:27
No problem. And if this answers your question, please mark this answer accordingly ;-)
– eckig
Nov 18 '14 at 7:15
add a comment |
Lets see. First the ingredients:
- Image
- Button
- ImageView
- Open Link in System Browser with JavaFX
Putting this together:
String path = "http://...";
String pathToOpen = "http://...";
Image image = new Image(path);
ImageView imageView = new ImageView(image);
Button button = new Button("clickMe!", imageView);
button.setOnAction(ev -> getHostServices().showDocument(pathToOpen));
thanks, very helpfull
– Hayk Harutyunyan
Nov 18 '14 at 6:27
No problem. And if this answers your question, please mark this answer accordingly ;-)
– eckig
Nov 18 '14 at 7:15
add a comment |
Lets see. First the ingredients:
- Image
- Button
- ImageView
- Open Link in System Browser with JavaFX
Putting this together:
String path = "http://...";
String pathToOpen = "http://...";
Image image = new Image(path);
ImageView imageView = new ImageView(image);
Button button = new Button("clickMe!", imageView);
button.setOnAction(ev -> getHostServices().showDocument(pathToOpen));
Lets see. First the ingredients:
- Image
- Button
- ImageView
- Open Link in System Browser with JavaFX
Putting this together:
String path = "http://...";
String pathToOpen = "http://...";
Image image = new Image(path);
ImageView imageView = new ImageView(image);
Button button = new Button("clickMe!", imageView);
button.setOnAction(ev -> getHostServices().showDocument(pathToOpen));
edited May 23 '17 at 12:17
Community♦
11
11
answered Nov 17 '14 at 19:27
eckigeckig
8,60442442
8,60442442
thanks, very helpfull
– Hayk Harutyunyan
Nov 18 '14 at 6:27
No problem. And if this answers your question, please mark this answer accordingly ;-)
– eckig
Nov 18 '14 at 7:15
add a comment |
thanks, very helpfull
– Hayk Harutyunyan
Nov 18 '14 at 6:27
No problem. And if this answers your question, please mark this answer accordingly ;-)
– eckig
Nov 18 '14 at 7:15
thanks, very helpfull
– Hayk Harutyunyan
Nov 18 '14 at 6:27
thanks, very helpfull
– Hayk Harutyunyan
Nov 18 '14 at 6:27
No problem. And if this answers your question, please mark this answer accordingly ;-)
– eckig
Nov 18 '14 at 7:15
No problem. And if this answers your question, please mark this answer accordingly ;-)
– eckig
Nov 18 '14 at 7:15
add a comment |
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