Aggregate function after XMLTABLE returns empty result set





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I'm having troubles with a query in which I use the LISTAGG() function.



I start from table one in this form:



A   B
1 a:b:e
2 c:d:f


Then I transform it in table two this form:



A  B
1 a
1 b
1 e
2 c
2 d
2 f


Using this query:



SELECT A,
trim(COLUMN_VALUE) B
FROM one,
xmltable(('"'
|| REPLACE(B, ':', '","')
|| '"'))


Then I perform a



SELECT A,
LISTAGG(B, ', ') WITHIN GROUP (ORDER BY B)
FROM two
GROUP BY A


to go back again to the form:



A    B
1 a,b,e
2 c,d,f


The problem is that in the end the query returns an empty result set:



A    B


Instead of the one I'm expecting.
Unfortunately I can't recreate my problem with a simpler query and I cannot share the original query because it contains sensitive information.



I'm hoping this might be a known problem or maybe related to the field data type. I tried to add a TO_CHAR(B) inside the LISTAGG() function but with no success.










share|improve this question

























  • why are you converting from one table to another just do replace

    – nikhil sugandh
    Nov 23 '18 at 12:17






  • 2





    Your queries work correctly for me (although @nikhilsugandh's comment above and answer below are relevant). Something that you're not showing us is causing the problem, not any of the above. Best of luck.

    – Bob Jarvis
    Nov 23 '18 at 12:21











  • @BobJarvis In my original query I just perform a join with table two in order to filter out some rows later and then I put it back in the original form using LISTAGG. Here I din't include this passage because I've seen that the result is the same even if I don't execute the join, resulting in the steps that I listed above

    – jackscorrow
    Nov 23 '18 at 12:54


















0















I'm having troubles with a query in which I use the LISTAGG() function.



I start from table one in this form:



A   B
1 a:b:e
2 c:d:f


Then I transform it in table two this form:



A  B
1 a
1 b
1 e
2 c
2 d
2 f


Using this query:



SELECT A,
trim(COLUMN_VALUE) B
FROM one,
xmltable(('"'
|| REPLACE(B, ':', '","')
|| '"'))


Then I perform a



SELECT A,
LISTAGG(B, ', ') WITHIN GROUP (ORDER BY B)
FROM two
GROUP BY A


to go back again to the form:



A    B
1 a,b,e
2 c,d,f


The problem is that in the end the query returns an empty result set:



A    B


Instead of the one I'm expecting.
Unfortunately I can't recreate my problem with a simpler query and I cannot share the original query because it contains sensitive information.



I'm hoping this might be a known problem or maybe related to the field data type. I tried to add a TO_CHAR(B) inside the LISTAGG() function but with no success.










share|improve this question

























  • why are you converting from one table to another just do replace

    – nikhil sugandh
    Nov 23 '18 at 12:17






  • 2





    Your queries work correctly for me (although @nikhilsugandh's comment above and answer below are relevant). Something that you're not showing us is causing the problem, not any of the above. Best of luck.

    – Bob Jarvis
    Nov 23 '18 at 12:21











  • @BobJarvis In my original query I just perform a join with table two in order to filter out some rows later and then I put it back in the original form using LISTAGG. Here I din't include this passage because I've seen that the result is the same even if I don't execute the join, resulting in the steps that I listed above

    – jackscorrow
    Nov 23 '18 at 12:54














0












0








0








I'm having troubles with a query in which I use the LISTAGG() function.



I start from table one in this form:



A   B
1 a:b:e
2 c:d:f


Then I transform it in table two this form:



A  B
1 a
1 b
1 e
2 c
2 d
2 f


Using this query:



SELECT A,
trim(COLUMN_VALUE) B
FROM one,
xmltable(('"'
|| REPLACE(B, ':', '","')
|| '"'))


Then I perform a



SELECT A,
LISTAGG(B, ', ') WITHIN GROUP (ORDER BY B)
FROM two
GROUP BY A


to go back again to the form:



A    B
1 a,b,e
2 c,d,f


The problem is that in the end the query returns an empty result set:



A    B


Instead of the one I'm expecting.
Unfortunately I can't recreate my problem with a simpler query and I cannot share the original query because it contains sensitive information.



I'm hoping this might be a known problem or maybe related to the field data type. I tried to add a TO_CHAR(B) inside the LISTAGG() function but with no success.










share|improve this question
















I'm having troubles with a query in which I use the LISTAGG() function.



I start from table one in this form:



A   B
1 a:b:e
2 c:d:f


Then I transform it in table two this form:



A  B
1 a
1 b
1 e
2 c
2 d
2 f


Using this query:



SELECT A,
trim(COLUMN_VALUE) B
FROM one,
xmltable(('"'
|| REPLACE(B, ':', '","')
|| '"'))


Then I perform a



SELECT A,
LISTAGG(B, ', ') WITHIN GROUP (ORDER BY B)
FROM two
GROUP BY A


to go back again to the form:



A    B
1 a,b,e
2 c,d,f


The problem is that in the end the query returns an empty result set:



A    B


Instead of the one I'm expecting.
Unfortunately I can't recreate my problem with a simpler query and I cannot share the original query because it contains sensitive information.



I'm hoping this might be a known problem or maybe related to the field data type. I tried to add a TO_CHAR(B) inside the LISTAGG() function but with no success.







sql oracle






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edited Nov 23 '18 at 14:00







jackscorrow

















asked Nov 23 '18 at 11:26









jackscorrowjackscorrow

336317




336317













  • why are you converting from one table to another just do replace

    – nikhil sugandh
    Nov 23 '18 at 12:17






  • 2





    Your queries work correctly for me (although @nikhilsugandh's comment above and answer below are relevant). Something that you're not showing us is causing the problem, not any of the above. Best of luck.

    – Bob Jarvis
    Nov 23 '18 at 12:21











  • @BobJarvis In my original query I just perform a join with table two in order to filter out some rows later and then I put it back in the original form using LISTAGG. Here I din't include this passage because I've seen that the result is the same even if I don't execute the join, resulting in the steps that I listed above

    – jackscorrow
    Nov 23 '18 at 12:54



















  • why are you converting from one table to another just do replace

    – nikhil sugandh
    Nov 23 '18 at 12:17






  • 2





    Your queries work correctly for me (although @nikhilsugandh's comment above and answer below are relevant). Something that you're not showing us is causing the problem, not any of the above. Best of luck.

    – Bob Jarvis
    Nov 23 '18 at 12:21











  • @BobJarvis In my original query I just perform a join with table two in order to filter out some rows later and then I put it back in the original form using LISTAGG. Here I din't include this passage because I've seen that the result is the same even if I don't execute the join, resulting in the steps that I listed above

    – jackscorrow
    Nov 23 '18 at 12:54

















why are you converting from one table to another just do replace

– nikhil sugandh
Nov 23 '18 at 12:17





why are you converting from one table to another just do replace

– nikhil sugandh
Nov 23 '18 at 12:17




2




2





Your queries work correctly for me (although @nikhilsugandh's comment above and answer below are relevant). Something that you're not showing us is causing the problem, not any of the above. Best of luck.

– Bob Jarvis
Nov 23 '18 at 12:21





Your queries work correctly for me (although @nikhilsugandh's comment above and answer below are relevant). Something that you're not showing us is causing the problem, not any of the above. Best of luck.

– Bob Jarvis
Nov 23 '18 at 12:21













@BobJarvis In my original query I just perform a join with table two in order to filter out some rows later and then I put it back in the original form using LISTAGG. Here I din't include this passage because I've seen that the result is the same even if I don't execute the join, resulting in the steps that I listed above

– jackscorrow
Nov 23 '18 at 12:54





@BobJarvis In my original query I just perform a join with table two in order to filter out some rows later and then I put it back in the original form using LISTAGG. Here I din't include this passage because I've seen that the result is the same even if I don't execute the join, resulting in the steps that I listed above

– jackscorrow
Nov 23 '18 at 12:54












3 Answers
3






active

oldest

votes


















1














You can try below



DEMO



SELECT A,
LISTAGG(B, ', ') WITHIN GROUP (ORDER BY B)
FROM
(SELECT A,
trim(COLUMN_VALUE) B
FROM one,
xmltable(('"'
|| REPLACE(B, ':', '","')
|| '"'))
) two GROUP BY A


OUTPUT:



A   B
1 a, b, e
2 c, d, f





share|improve this answer































    1














    this will work:



    select a.*,REPLACE(a.B, ':', ',') from NS a;


    sql fiddle:http://sqlfiddle.com/#!9/2c1e9d/2/0






    share|improve this answer
























    • My aim is not to replace the ":" with ",". The example I posted here is a simplification. Once I have my table two I have to filter out some rows and then put it back in the previous form. In my question I din't include this passage because I've seen that the result is the same even if I do just the steps that I listed above

      – jackscorrow
      Nov 23 '18 at 12:52











    • @jackscorrow whats your original question then post that??

      – nikhil sugandh
      Nov 23 '18 at 18:19



















    0














    My hunch about possible data type issues was correct.



    The function xmltable returns a column of type XMLTYPE, in my case column B. The aggregate function failed whenever trying to aggregate a field of that data type.



    I fixed the problem by converting the XMLTYPE column to string obtaining this query:



    SELECT A,
    trim((COLUMN_VALUE).getstringval()) B
    FROM one,
    xmltable(('"'
    || REPLACE(B, ':', '","')
    || '"'))


    Using this query the returned result is correct.



    Many thanks to everybody who tried to help.






    share|improve this answer
























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      You can try below



      DEMO



      SELECT A,
      LISTAGG(B, ', ') WITHIN GROUP (ORDER BY B)
      FROM
      (SELECT A,
      trim(COLUMN_VALUE) B
      FROM one,
      xmltable(('"'
      || REPLACE(B, ':', '","')
      || '"'))
      ) two GROUP BY A


      OUTPUT:



      A   B
      1 a, b, e
      2 c, d, f





      share|improve this answer




























        1














        You can try below



        DEMO



        SELECT A,
        LISTAGG(B, ', ') WITHIN GROUP (ORDER BY B)
        FROM
        (SELECT A,
        trim(COLUMN_VALUE) B
        FROM one,
        xmltable(('"'
        || REPLACE(B, ':', '","')
        || '"'))
        ) two GROUP BY A


        OUTPUT:



        A   B
        1 a, b, e
        2 c, d, f





        share|improve this answer


























          1












          1








          1







          You can try below



          DEMO



          SELECT A,
          LISTAGG(B, ', ') WITHIN GROUP (ORDER BY B)
          FROM
          (SELECT A,
          trim(COLUMN_VALUE) B
          FROM one,
          xmltable(('"'
          || REPLACE(B, ':', '","')
          || '"'))
          ) two GROUP BY A


          OUTPUT:



          A   B
          1 a, b, e
          2 c, d, f





          share|improve this answer













          You can try below



          DEMO



          SELECT A,
          LISTAGG(B, ', ') WITHIN GROUP (ORDER BY B)
          FROM
          (SELECT A,
          trim(COLUMN_VALUE) B
          FROM one,
          xmltable(('"'
          || REPLACE(B, ':', '","')
          || '"'))
          ) two GROUP BY A


          OUTPUT:



          A   B
          1 a, b, e
          2 c, d, f






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 23 '18 at 11:30









          fa06fa06

          19k21019




          19k21019

























              1














              this will work:



              select a.*,REPLACE(a.B, ':', ',') from NS a;


              sql fiddle:http://sqlfiddle.com/#!9/2c1e9d/2/0






              share|improve this answer
























              • My aim is not to replace the ":" with ",". The example I posted here is a simplification. Once I have my table two I have to filter out some rows and then put it back in the previous form. In my question I din't include this passage because I've seen that the result is the same even if I do just the steps that I listed above

                – jackscorrow
                Nov 23 '18 at 12:52











              • @jackscorrow whats your original question then post that??

                – nikhil sugandh
                Nov 23 '18 at 18:19
















              1














              this will work:



              select a.*,REPLACE(a.B, ':', ',') from NS a;


              sql fiddle:http://sqlfiddle.com/#!9/2c1e9d/2/0






              share|improve this answer
























              • My aim is not to replace the ":" with ",". The example I posted here is a simplification. Once I have my table two I have to filter out some rows and then put it back in the previous form. In my question I din't include this passage because I've seen that the result is the same even if I do just the steps that I listed above

                – jackscorrow
                Nov 23 '18 at 12:52











              • @jackscorrow whats your original question then post that??

                – nikhil sugandh
                Nov 23 '18 at 18:19














              1












              1








              1







              this will work:



              select a.*,REPLACE(a.B, ':', ',') from NS a;


              sql fiddle:http://sqlfiddle.com/#!9/2c1e9d/2/0






              share|improve this answer













              this will work:



              select a.*,REPLACE(a.B, ':', ',') from NS a;


              sql fiddle:http://sqlfiddle.com/#!9/2c1e9d/2/0







              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Nov 23 '18 at 11:44









              nikhil sugandhnikhil sugandh

              1,3542820




              1,3542820













              • My aim is not to replace the ":" with ",". The example I posted here is a simplification. Once I have my table two I have to filter out some rows and then put it back in the previous form. In my question I din't include this passage because I've seen that the result is the same even if I do just the steps that I listed above

                – jackscorrow
                Nov 23 '18 at 12:52











              • @jackscorrow whats your original question then post that??

                – nikhil sugandh
                Nov 23 '18 at 18:19



















              • My aim is not to replace the ":" with ",". The example I posted here is a simplification. Once I have my table two I have to filter out some rows and then put it back in the previous form. In my question I din't include this passage because I've seen that the result is the same even if I do just the steps that I listed above

                – jackscorrow
                Nov 23 '18 at 12:52











              • @jackscorrow whats your original question then post that??

                – nikhil sugandh
                Nov 23 '18 at 18:19

















              My aim is not to replace the ":" with ",". The example I posted here is a simplification. Once I have my table two I have to filter out some rows and then put it back in the previous form. In my question I din't include this passage because I've seen that the result is the same even if I do just the steps that I listed above

              – jackscorrow
              Nov 23 '18 at 12:52





              My aim is not to replace the ":" with ",". The example I posted here is a simplification. Once I have my table two I have to filter out some rows and then put it back in the previous form. In my question I din't include this passage because I've seen that the result is the same even if I do just the steps that I listed above

              – jackscorrow
              Nov 23 '18 at 12:52













              @jackscorrow whats your original question then post that??

              – nikhil sugandh
              Nov 23 '18 at 18:19





              @jackscorrow whats your original question then post that??

              – nikhil sugandh
              Nov 23 '18 at 18:19











              0














              My hunch about possible data type issues was correct.



              The function xmltable returns a column of type XMLTYPE, in my case column B. The aggregate function failed whenever trying to aggregate a field of that data type.



              I fixed the problem by converting the XMLTYPE column to string obtaining this query:



              SELECT A,
              trim((COLUMN_VALUE).getstringval()) B
              FROM one,
              xmltable(('"'
              || REPLACE(B, ':', '","')
              || '"'))


              Using this query the returned result is correct.



              Many thanks to everybody who tried to help.






              share|improve this answer




























                0














                My hunch about possible data type issues was correct.



                The function xmltable returns a column of type XMLTYPE, in my case column B. The aggregate function failed whenever trying to aggregate a field of that data type.



                I fixed the problem by converting the XMLTYPE column to string obtaining this query:



                SELECT A,
                trim((COLUMN_VALUE).getstringval()) B
                FROM one,
                xmltable(('"'
                || REPLACE(B, ':', '","')
                || '"'))


                Using this query the returned result is correct.



                Many thanks to everybody who tried to help.






                share|improve this answer


























                  0












                  0








                  0







                  My hunch about possible data type issues was correct.



                  The function xmltable returns a column of type XMLTYPE, in my case column B. The aggregate function failed whenever trying to aggregate a field of that data type.



                  I fixed the problem by converting the XMLTYPE column to string obtaining this query:



                  SELECT A,
                  trim((COLUMN_VALUE).getstringval()) B
                  FROM one,
                  xmltable(('"'
                  || REPLACE(B, ':', '","')
                  || '"'))


                  Using this query the returned result is correct.



                  Many thanks to everybody who tried to help.






                  share|improve this answer













                  My hunch about possible data type issues was correct.



                  The function xmltable returns a column of type XMLTYPE, in my case column B. The aggregate function failed whenever trying to aggregate a field of that data type.



                  I fixed the problem by converting the XMLTYPE column to string obtaining this query:



                  SELECT A,
                  trim((COLUMN_VALUE).getstringval()) B
                  FROM one,
                  xmltable(('"'
                  || REPLACE(B, ':', '","')
                  || '"'))


                  Using this query the returned result is correct.



                  Many thanks to everybody who tried to help.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 23 '18 at 14:06









                  jackscorrowjackscorrow

                  336317




                  336317






























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