How do I resolve ClassNotFoundException?
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I am trying to run a Java application, but getting this error:
java.lang.ClassNotFoundException:
After the colon comes the location of the class that is missing. However, I know that that location does not exist since the class is located elsewhere. How can I update the path of that class? Does it have something to do with the class path?
java class classpath classnotfoundexception
add a comment |
I am trying to run a Java application, but getting this error:
java.lang.ClassNotFoundException:
After the colon comes the location of the class that is missing. However, I know that that location does not exist since the class is located elsewhere. How can I update the path of that class? Does it have something to do with the class path?
java class classpath classnotfoundexception
1
You must add the jar which has the missing class to the classptah
– Crom
Jul 1 '13 at 16:00
if your class has a package then go to the folder containing the class. e.g if package is package test.abc, then go to folder before test and then do java -cp . test.abc.CLASSNAME (without .class). If there's no package then go to folder containing class and say java -cp . CLASSNAME
– Optional
Jul 1 '13 at 16:05
Either a class was not deployed to your runtime (for example missing jar), or the class is not visible in a given class loader, check this this tool that helps troubleshooting these problems: jhades.org
– Angular University
Dec 6 '13 at 12:05
I also run into this sometimes. This exception clearly violates the rule of stating all necessary context in an exception message. It should mention where it tried to look for the thing, what is on your classpath. Please make better exception messages. Don't make us hunt for information which could help solve the problem.
– masterxilo
Nov 25 '18 at 14:12
add a comment |
I am trying to run a Java application, but getting this error:
java.lang.ClassNotFoundException:
After the colon comes the location of the class that is missing. However, I know that that location does not exist since the class is located elsewhere. How can I update the path of that class? Does it have something to do with the class path?
java class classpath classnotfoundexception
I am trying to run a Java application, but getting this error:
java.lang.ClassNotFoundException:
After the colon comes the location of the class that is missing. However, I know that that location does not exist since the class is located elsewhere. How can I update the path of that class? Does it have something to do with the class path?
java class classpath classnotfoundexception
java class classpath classnotfoundexception
edited Jun 5 '17 at 14:20
vaxquis
7,80853958
7,80853958
asked Jul 1 '13 at 15:58
user2426316user2426316
2,406134169
2,406134169
1
You must add the jar which has the missing class to the classptah
– Crom
Jul 1 '13 at 16:00
if your class has a package then go to the folder containing the class. e.g if package is package test.abc, then go to folder before test and then do java -cp . test.abc.CLASSNAME (without .class). If there's no package then go to folder containing class and say java -cp . CLASSNAME
– Optional
Jul 1 '13 at 16:05
Either a class was not deployed to your runtime (for example missing jar), or the class is not visible in a given class loader, check this this tool that helps troubleshooting these problems: jhades.org
– Angular University
Dec 6 '13 at 12:05
I also run into this sometimes. This exception clearly violates the rule of stating all necessary context in an exception message. It should mention where it tried to look for the thing, what is on your classpath. Please make better exception messages. Don't make us hunt for information which could help solve the problem.
– masterxilo
Nov 25 '18 at 14:12
add a comment |
1
You must add the jar which has the missing class to the classptah
– Crom
Jul 1 '13 at 16:00
if your class has a package then go to the folder containing the class. e.g if package is package test.abc, then go to folder before test and then do java -cp . test.abc.CLASSNAME (without .class). If there's no package then go to folder containing class and say java -cp . CLASSNAME
– Optional
Jul 1 '13 at 16:05
Either a class was not deployed to your runtime (for example missing jar), or the class is not visible in a given class loader, check this this tool that helps troubleshooting these problems: jhades.org
– Angular University
Dec 6 '13 at 12:05
I also run into this sometimes. This exception clearly violates the rule of stating all necessary context in an exception message. It should mention where it tried to look for the thing, what is on your classpath. Please make better exception messages. Don't make us hunt for information which could help solve the problem.
– masterxilo
Nov 25 '18 at 14:12
1
1
You must add the jar which has the missing class to the classptah
– Crom
Jul 1 '13 at 16:00
You must add the jar which has the missing class to the classptah
– Crom
Jul 1 '13 at 16:00
if your class has a package then go to the folder containing the class. e.g if package is package test.abc, then go to folder before test and then do java -cp . test.abc.CLASSNAME (without .class). If there's no package then go to folder containing class and say java -cp . CLASSNAME
– Optional
Jul 1 '13 at 16:05
if your class has a package then go to the folder containing the class. e.g if package is package test.abc, then go to folder before test and then do java -cp . test.abc.CLASSNAME (without .class). If there's no package then go to folder containing class and say java -cp . CLASSNAME
– Optional
Jul 1 '13 at 16:05
Either a class was not deployed to your runtime (for example missing jar), or the class is not visible in a given class loader, check this this tool that helps troubleshooting these problems: jhades.org
– Angular University
Dec 6 '13 at 12:05
Either a class was not deployed to your runtime (for example missing jar), or the class is not visible in a given class loader, check this this tool that helps troubleshooting these problems: jhades.org
– Angular University
Dec 6 '13 at 12:05
I also run into this sometimes. This exception clearly violates the rule of stating all necessary context in an exception message. It should mention where it tried to look for the thing, what is on your classpath. Please make better exception messages. Don't make us hunt for information which could help solve the problem.
– masterxilo
Nov 25 '18 at 14:12
I also run into this sometimes. This exception clearly violates the rule of stating all necessary context in an exception message. It should mention where it tried to look for the thing, what is on your classpath. Please make better exception messages. Don't make us hunt for information which could help solve the problem.
– masterxilo
Nov 25 '18 at 14:12
add a comment |
18 Answers
18
active
oldest
votes
Your classpath is broken (which is a very common problem in the Java world).
Depending on how you start your application, you need to revise the argument to -cp
, your Class-Path entry in MANIFEST.MF or your disk layout.
24
Can you please be more eclipse specific? What do I have to do?
– user2426316
Jul 1 '13 at 16:03
19
Your question does not contain enough information to provide a more specfiic answer. Consider adding that.
– Thorbjørn Ravn Andersen
Jul 1 '13 at 16:06
Dependency resolution/version mismatches is a very common problem in basically all programming environments. We could say that all any program ever does is resolve such definitions... the question is always what/where is the definition and which version did you mean?
– masterxilo
Nov 23 '18 at 22:44
@masterxilo What point are you trying to make?
– Thorbjørn Ravn Andersen
Nov 24 '18 at 1:13
2
I am just emphasizing that besides the Java world all of software has a fight with ensuring that correct versions of dependencies are found. I can mention dll-hell, package managers, version managers, spring boot bill of materials and docker containers as examples of this problem and possible solutions. The larger the fraction of foreign code becones the larger the problem gets.
– masterxilo
Nov 25 '18 at 14:08
|
show 1 more comment
A classpath is a list of locations to load classes from.
These 'locations' can either be directories, or jar files.
For directories, the JVM will follow an expected pattern for loading a class. If I have the directory C:/myproject/classes in my classpath, and I attempt to load a class com.mycompany.Foo, it will look under the classes directory for a directory called com, then under that a directory called mycompany, and finally it will look for a file called Foo.class in that directory.
In the second instance, for jar files, it will search the jar file for that class. A jar file is in reality just a zipped collection of directories like the above. If you unzip a jar file, you'll get a bunch of directories and class files following the pattern above.
So the JVM traverses a classpath from start to finish looking for the definition of the class when it attempts to load the class definition. For example, in the classpath :
C:/myproject/classes;C:/myproject/lib/stuff.jar;C:/myproject/lib/otherstuff.jar
The JVM will attempt to look in the directory classes first, then in stuff.jar and finally in otherstuff.jar.
When you get a ClassNotFoundException, it means the JVM has traversed the entire classpath and not found the class you've attempted to reference. The solution, as so often in the Java world, is to check your classpath.
You define a classpath on the command line by saying java -cp and then your classpath. In an IDE such as Eclipse, you'll have a menu option to specify your classpath.
But how do I actually find what my classpath is
– Philip Rego
2 days ago
add a comment |
This is the best solution I found so far.
Suppose we have a package called org.mypackage
containing the classes:
- HelloWorld (main class)
- SupportClass
- UtilClass
and the files defining this package are stored physically under the directory D:myprogram
(on Windows) or /home/user/myprogram
(on Linux).
The file structure will look like this:
When we invoke Java, we specify the name of the application to run: org.mypackage.HelloWorld
. However we must also tell Java where to look for the files and directories defining our package. So to launch the program, we have to use the following command:
NOTE: You have to execute the above
java
command no matter what your current location is. But this is not the case forjavac
. For
compiling you can even directly go into the directory where you have
your.java
files and directly executejavac ClassName.java
.
add a comment |
If you know the path of the class or the jar containing the class then add it to your classpath while running it. You can use the classpath as mentioned here:
on Windows
java -classpath .;yourjar.jar YourMainClass
on UNIX/Linux
java -classpath .:yourjar.jar YourMainClass
add a comment |
Try these if you use maven. I use maven for my project and when I do mvn clean install
and try to run a program it throws the exception. So, I clean the project and run it again and it works for me.
I use eclipse IDE.
For Class Not Found Exception when running Junit test, try running mvn clean test
once. It will compile all the test classes.
what directory were you in when you ran "mvn clean test"? is it in the same directory as the POM?
– TacoB0t
Mar 27 '18 at 16:19
1
Yes. Ran it from the directory where pom file is present.
– Arun
Mar 27 '18 at 18:26
add a comment |
To add the location of a class to your classpath via command line simply add -cp
or -classpath
and the location of the class while running it. I.E.
java -cp "c:/location/of/file" YourProgram
Or if you're running an IDE such as eclipse you can right click on the project -> build path -> configure build path
and add the external JAR containing your class to the build path then it should work fine.
add a comment |
Use ';' as the separator. If your environment variables are set correctly, you should see your settings. If your PATH and CLASSPATH is correct, windows should recognize those commands. You do NOT need to restart your computer when installing Java.
5
That is on windows (semicolon) , on unix/linux it is ':' (colon)
– Joeblade
Jan 19 '15 at 8:38
add a comment |
Add the full path of jar file to the CLASSPATH.
In linux use: export CLASSPATH=".:/full/path/to/file.jar:$CLASSPATH"
. Other way worked (without editing the CLASSPATH) was unzipping the jar in the current project folder.
Ways didn't work for me:
1) Using -cp
option with full path of jar file.
2) Using -cp
with only the name of jar when located in the current folder
3) Copying the jar to the current project folder
4) Copying the jar to standard location of java jars (/usr/share/java)
This solution is reported for class com.mysql.jdbc.Driver in mysql-connector-java.5-*.jar, working on linux with OpenJDK version 1.7
Only unzipping the JAR worked for me, none of the other solutions did
– OverCoder
Jun 5 '16 at 23:05
add a comment |
Go up to the top and remove the import statement if there is one, and re import the class. But if that isn't the case do a clean then build. Are you using Netbeans or Eclipse?
add a comment |
I ran into this as well and tried all of the other solutions. I did not have the .class file in my HTML folder, I only had the .java file. Once I added the .class file the program worked fine.
add a comment |
It could happen if your classpath is not correct
Let us posit a serializable class and deserializable class under same projectname. You run the serializable class, creating a serializable object in specific folder. Now you need the desearialized data. In the meantime, if you change the name of the project it will not work. You have to run the serializable class first and then deserialize the file.
add a comment |
If you are using maven
try to maven update all projects and force for snapshots.
It will clean as well and rebuilt all classpath..
It solved my problem..
add a comment |
I just did
1.Invalidate caches and restart
2.Rebuilt my project which solved the problem
add a comment |
I was trying to run .jar from C# code using Process
class. The java code ran successfully from eclipse but it doesn't from C# visual studio and even clicking directly on the jar file, it always stopped with ClassNotFoundException:
exception. Solution for my, was export the java program as "Runnable JAR file" instead of "JAR File". Hope it can help someone.
add a comment |
This can happen on Windows after a java update where the old version of the java SDK is missing and a new one is present. I would check if your IDE is using the installed java SDK version (IntelliJ: CTRL + SHIFT + ALT + S)
add a comment |
If you have added multiple (Third-Party)**libraries and Extends **Application class
Then it might occur.
For that, you have to set multiDexEnabled true
and replace your extended Application
class with MultiDexApplication
.
It will be solved.
add a comment |
Basic Generic Question - Simplest Generic Answer ;)
Given the information I will make the assumption that you might be trying a basic approach to coding, building/compiling and running a simple console app like "Hello World", using some simple text editor and some Command Shell.
This error occurs in the fallowing scenario:
..SomePath>javac HelloWorld.java
..SomePath>java HelloWorld.class
In other words, use:
..SomePath>java HelloWorld
P.S. The adding the file extension .class produces the same mistake.
Also be sure to have the Java's (JDK/JRE) bin folder in the operating system's Environment Variables's PATH.(Lookup for more details other posts on this)
P.P.S Was I correct in my assumption/s?
add a comment |
Put all the code in try block then catch exception in a catch block
try
{
// code
}
catch(ClassNotFoundException e1)
{
e1.getmessage();
}
2
This does not resolve the exception. This hides the exception. Furthermore, "e1.getmessage()" is a) the wrong capitalisation of getMessage() and b) not going to do very much as it returns a string with a message and you're not printing it or logging it or anything!
– IBBoard
Aug 30 '16 at 12:15
add a comment |
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18 Answers
18
active
oldest
votes
18 Answers
18
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your classpath is broken (which is a very common problem in the Java world).
Depending on how you start your application, you need to revise the argument to -cp
, your Class-Path entry in MANIFEST.MF or your disk layout.
24
Can you please be more eclipse specific? What do I have to do?
– user2426316
Jul 1 '13 at 16:03
19
Your question does not contain enough information to provide a more specfiic answer. Consider adding that.
– Thorbjørn Ravn Andersen
Jul 1 '13 at 16:06
Dependency resolution/version mismatches is a very common problem in basically all programming environments. We could say that all any program ever does is resolve such definitions... the question is always what/where is the definition and which version did you mean?
– masterxilo
Nov 23 '18 at 22:44
@masterxilo What point are you trying to make?
– Thorbjørn Ravn Andersen
Nov 24 '18 at 1:13
2
I am just emphasizing that besides the Java world all of software has a fight with ensuring that correct versions of dependencies are found. I can mention dll-hell, package managers, version managers, spring boot bill of materials and docker containers as examples of this problem and possible solutions. The larger the fraction of foreign code becones the larger the problem gets.
– masterxilo
Nov 25 '18 at 14:08
|
show 1 more comment
Your classpath is broken (which is a very common problem in the Java world).
Depending on how you start your application, you need to revise the argument to -cp
, your Class-Path entry in MANIFEST.MF or your disk layout.
24
Can you please be more eclipse specific? What do I have to do?
– user2426316
Jul 1 '13 at 16:03
19
Your question does not contain enough information to provide a more specfiic answer. Consider adding that.
– Thorbjørn Ravn Andersen
Jul 1 '13 at 16:06
Dependency resolution/version mismatches is a very common problem in basically all programming environments. We could say that all any program ever does is resolve such definitions... the question is always what/where is the definition and which version did you mean?
– masterxilo
Nov 23 '18 at 22:44
@masterxilo What point are you trying to make?
– Thorbjørn Ravn Andersen
Nov 24 '18 at 1:13
2
I am just emphasizing that besides the Java world all of software has a fight with ensuring that correct versions of dependencies are found. I can mention dll-hell, package managers, version managers, spring boot bill of materials and docker containers as examples of this problem and possible solutions. The larger the fraction of foreign code becones the larger the problem gets.
– masterxilo
Nov 25 '18 at 14:08
|
show 1 more comment
Your classpath is broken (which is a very common problem in the Java world).
Depending on how you start your application, you need to revise the argument to -cp
, your Class-Path entry in MANIFEST.MF or your disk layout.
Your classpath is broken (which is a very common problem in the Java world).
Depending on how you start your application, you need to revise the argument to -cp
, your Class-Path entry in MANIFEST.MF or your disk layout.
answered Jul 1 '13 at 16:02
Thorbjørn Ravn AndersenThorbjørn Ravn Andersen
58.3k25151291
58.3k25151291
24
Can you please be more eclipse specific? What do I have to do?
– user2426316
Jul 1 '13 at 16:03
19
Your question does not contain enough information to provide a more specfiic answer. Consider adding that.
– Thorbjørn Ravn Andersen
Jul 1 '13 at 16:06
Dependency resolution/version mismatches is a very common problem in basically all programming environments. We could say that all any program ever does is resolve such definitions... the question is always what/where is the definition and which version did you mean?
– masterxilo
Nov 23 '18 at 22:44
@masterxilo What point are you trying to make?
– Thorbjørn Ravn Andersen
Nov 24 '18 at 1:13
2
I am just emphasizing that besides the Java world all of software has a fight with ensuring that correct versions of dependencies are found. I can mention dll-hell, package managers, version managers, spring boot bill of materials and docker containers as examples of this problem and possible solutions. The larger the fraction of foreign code becones the larger the problem gets.
– masterxilo
Nov 25 '18 at 14:08
|
show 1 more comment
24
Can you please be more eclipse specific? What do I have to do?
– user2426316
Jul 1 '13 at 16:03
19
Your question does not contain enough information to provide a more specfiic answer. Consider adding that.
– Thorbjørn Ravn Andersen
Jul 1 '13 at 16:06
Dependency resolution/version mismatches is a very common problem in basically all programming environments. We could say that all any program ever does is resolve such definitions... the question is always what/where is the definition and which version did you mean?
– masterxilo
Nov 23 '18 at 22:44
@masterxilo What point are you trying to make?
– Thorbjørn Ravn Andersen
Nov 24 '18 at 1:13
2
I am just emphasizing that besides the Java world all of software has a fight with ensuring that correct versions of dependencies are found. I can mention dll-hell, package managers, version managers, spring boot bill of materials and docker containers as examples of this problem and possible solutions. The larger the fraction of foreign code becones the larger the problem gets.
– masterxilo
Nov 25 '18 at 14:08
24
24
Can you please be more eclipse specific? What do I have to do?
– user2426316
Jul 1 '13 at 16:03
Can you please be more eclipse specific? What do I have to do?
– user2426316
Jul 1 '13 at 16:03
19
19
Your question does not contain enough information to provide a more specfiic answer. Consider adding that.
– Thorbjørn Ravn Andersen
Jul 1 '13 at 16:06
Your question does not contain enough information to provide a more specfiic answer. Consider adding that.
– Thorbjørn Ravn Andersen
Jul 1 '13 at 16:06
Dependency resolution/version mismatches is a very common problem in basically all programming environments. We could say that all any program ever does is resolve such definitions... the question is always what/where is the definition and which version did you mean?
– masterxilo
Nov 23 '18 at 22:44
Dependency resolution/version mismatches is a very common problem in basically all programming environments. We could say that all any program ever does is resolve such definitions... the question is always what/where is the definition and which version did you mean?
– masterxilo
Nov 23 '18 at 22:44
@masterxilo What point are you trying to make?
– Thorbjørn Ravn Andersen
Nov 24 '18 at 1:13
@masterxilo What point are you trying to make?
– Thorbjørn Ravn Andersen
Nov 24 '18 at 1:13
2
2
I am just emphasizing that besides the Java world all of software has a fight with ensuring that correct versions of dependencies are found. I can mention dll-hell, package managers, version managers, spring boot bill of materials and docker containers as examples of this problem and possible solutions. The larger the fraction of foreign code becones the larger the problem gets.
– masterxilo
Nov 25 '18 at 14:08
I am just emphasizing that besides the Java world all of software has a fight with ensuring that correct versions of dependencies are found. I can mention dll-hell, package managers, version managers, spring boot bill of materials and docker containers as examples of this problem and possible solutions. The larger the fraction of foreign code becones the larger the problem gets.
– masterxilo
Nov 25 '18 at 14:08
|
show 1 more comment
A classpath is a list of locations to load classes from.
These 'locations' can either be directories, or jar files.
For directories, the JVM will follow an expected pattern for loading a class. If I have the directory C:/myproject/classes in my classpath, and I attempt to load a class com.mycompany.Foo, it will look under the classes directory for a directory called com, then under that a directory called mycompany, and finally it will look for a file called Foo.class in that directory.
In the second instance, for jar files, it will search the jar file for that class. A jar file is in reality just a zipped collection of directories like the above. If you unzip a jar file, you'll get a bunch of directories and class files following the pattern above.
So the JVM traverses a classpath from start to finish looking for the definition of the class when it attempts to load the class definition. For example, in the classpath :
C:/myproject/classes;C:/myproject/lib/stuff.jar;C:/myproject/lib/otherstuff.jar
The JVM will attempt to look in the directory classes first, then in stuff.jar and finally in otherstuff.jar.
When you get a ClassNotFoundException, it means the JVM has traversed the entire classpath and not found the class you've attempted to reference. The solution, as so often in the Java world, is to check your classpath.
You define a classpath on the command line by saying java -cp and then your classpath. In an IDE such as Eclipse, you'll have a menu option to specify your classpath.
But how do I actually find what my classpath is
– Philip Rego
2 days ago
add a comment |
A classpath is a list of locations to load classes from.
These 'locations' can either be directories, or jar files.
For directories, the JVM will follow an expected pattern for loading a class. If I have the directory C:/myproject/classes in my classpath, and I attempt to load a class com.mycompany.Foo, it will look under the classes directory for a directory called com, then under that a directory called mycompany, and finally it will look for a file called Foo.class in that directory.
In the second instance, for jar files, it will search the jar file for that class. A jar file is in reality just a zipped collection of directories like the above. If you unzip a jar file, you'll get a bunch of directories and class files following the pattern above.
So the JVM traverses a classpath from start to finish looking for the definition of the class when it attempts to load the class definition. For example, in the classpath :
C:/myproject/classes;C:/myproject/lib/stuff.jar;C:/myproject/lib/otherstuff.jar
The JVM will attempt to look in the directory classes first, then in stuff.jar and finally in otherstuff.jar.
When you get a ClassNotFoundException, it means the JVM has traversed the entire classpath and not found the class you've attempted to reference. The solution, as so often in the Java world, is to check your classpath.
You define a classpath on the command line by saying java -cp and then your classpath. In an IDE such as Eclipse, you'll have a menu option to specify your classpath.
But how do I actually find what my classpath is
– Philip Rego
2 days ago
add a comment |
A classpath is a list of locations to load classes from.
These 'locations' can either be directories, or jar files.
For directories, the JVM will follow an expected pattern for loading a class. If I have the directory C:/myproject/classes in my classpath, and I attempt to load a class com.mycompany.Foo, it will look under the classes directory for a directory called com, then under that a directory called mycompany, and finally it will look for a file called Foo.class in that directory.
In the second instance, for jar files, it will search the jar file for that class. A jar file is in reality just a zipped collection of directories like the above. If you unzip a jar file, you'll get a bunch of directories and class files following the pattern above.
So the JVM traverses a classpath from start to finish looking for the definition of the class when it attempts to load the class definition. For example, in the classpath :
C:/myproject/classes;C:/myproject/lib/stuff.jar;C:/myproject/lib/otherstuff.jar
The JVM will attempt to look in the directory classes first, then in stuff.jar and finally in otherstuff.jar.
When you get a ClassNotFoundException, it means the JVM has traversed the entire classpath and not found the class you've attempted to reference. The solution, as so often in the Java world, is to check your classpath.
You define a classpath on the command line by saying java -cp and then your classpath. In an IDE such as Eclipse, you'll have a menu option to specify your classpath.
A classpath is a list of locations to load classes from.
These 'locations' can either be directories, or jar files.
For directories, the JVM will follow an expected pattern for loading a class. If I have the directory C:/myproject/classes in my classpath, and I attempt to load a class com.mycompany.Foo, it will look under the classes directory for a directory called com, then under that a directory called mycompany, and finally it will look for a file called Foo.class in that directory.
In the second instance, for jar files, it will search the jar file for that class. A jar file is in reality just a zipped collection of directories like the above. If you unzip a jar file, you'll get a bunch of directories and class files following the pattern above.
So the JVM traverses a classpath from start to finish looking for the definition of the class when it attempts to load the class definition. For example, in the classpath :
C:/myproject/classes;C:/myproject/lib/stuff.jar;C:/myproject/lib/otherstuff.jar
The JVM will attempt to look in the directory classes first, then in stuff.jar and finally in otherstuff.jar.
When you get a ClassNotFoundException, it means the JVM has traversed the entire classpath and not found the class you've attempted to reference. The solution, as so often in the Java world, is to check your classpath.
You define a classpath on the command line by saying java -cp and then your classpath. In an IDE such as Eclipse, you'll have a menu option to specify your classpath.
answered Jul 1 '13 at 16:20
user2000590user2000590
38122
38122
But how do I actually find what my classpath is
– Philip Rego
2 days ago
add a comment |
But how do I actually find what my classpath is
– Philip Rego
2 days ago
But how do I actually find what my classpath is
– Philip Rego
2 days ago
But how do I actually find what my classpath is
– Philip Rego
2 days ago
add a comment |
This is the best solution I found so far.
Suppose we have a package called org.mypackage
containing the classes:
- HelloWorld (main class)
- SupportClass
- UtilClass
and the files defining this package are stored physically under the directory D:myprogram
(on Windows) or /home/user/myprogram
(on Linux).
The file structure will look like this:
When we invoke Java, we specify the name of the application to run: org.mypackage.HelloWorld
. However we must also tell Java where to look for the files and directories defining our package. So to launch the program, we have to use the following command:
NOTE: You have to execute the above
java
command no matter what your current location is. But this is not the case forjavac
. For
compiling you can even directly go into the directory where you have
your.java
files and directly executejavac ClassName.java
.
add a comment |
This is the best solution I found so far.
Suppose we have a package called org.mypackage
containing the classes:
- HelloWorld (main class)
- SupportClass
- UtilClass
and the files defining this package are stored physically under the directory D:myprogram
(on Windows) or /home/user/myprogram
(on Linux).
The file structure will look like this:
When we invoke Java, we specify the name of the application to run: org.mypackage.HelloWorld
. However we must also tell Java where to look for the files and directories defining our package. So to launch the program, we have to use the following command:
NOTE: You have to execute the above
java
command no matter what your current location is. But this is not the case forjavac
. For
compiling you can even directly go into the directory where you have
your.java
files and directly executejavac ClassName.java
.
add a comment |
This is the best solution I found so far.
Suppose we have a package called org.mypackage
containing the classes:
- HelloWorld (main class)
- SupportClass
- UtilClass
and the files defining this package are stored physically under the directory D:myprogram
(on Windows) or /home/user/myprogram
(on Linux).
The file structure will look like this:
When we invoke Java, we specify the name of the application to run: org.mypackage.HelloWorld
. However we must also tell Java where to look for the files and directories defining our package. So to launch the program, we have to use the following command:
NOTE: You have to execute the above
java
command no matter what your current location is. But this is not the case forjavac
. For
compiling you can even directly go into the directory where you have
your.java
files and directly executejavac ClassName.java
.
This is the best solution I found so far.
Suppose we have a package called org.mypackage
containing the classes:
- HelloWorld (main class)
- SupportClass
- UtilClass
and the files defining this package are stored physically under the directory D:myprogram
(on Windows) or /home/user/myprogram
(on Linux).
The file structure will look like this:
When we invoke Java, we specify the name of the application to run: org.mypackage.HelloWorld
. However we must also tell Java where to look for the files and directories defining our package. So to launch the program, we have to use the following command:
NOTE: You have to execute the above
java
command no matter what your current location is. But this is not the case forjavac
. For
compiling you can even directly go into the directory where you have
your.java
files and directly executejavac ClassName.java
.
edited Oct 5 '15 at 6:51
answered Oct 5 '15 at 6:44
Ram PatraRam Patra
10.4k104562
10.4k104562
add a comment |
add a comment |
If you know the path of the class or the jar containing the class then add it to your classpath while running it. You can use the classpath as mentioned here:
on Windows
java -classpath .;yourjar.jar YourMainClass
on UNIX/Linux
java -classpath .:yourjar.jar YourMainClass
add a comment |
If you know the path of the class or the jar containing the class then add it to your classpath while running it. You can use the classpath as mentioned here:
on Windows
java -classpath .;yourjar.jar YourMainClass
on UNIX/Linux
java -classpath .:yourjar.jar YourMainClass
add a comment |
If you know the path of the class or the jar containing the class then add it to your classpath while running it. You can use the classpath as mentioned here:
on Windows
java -classpath .;yourjar.jar YourMainClass
on UNIX/Linux
java -classpath .:yourjar.jar YourMainClass
If you know the path of the class or the jar containing the class then add it to your classpath while running it. You can use the classpath as mentioned here:
on Windows
java -classpath .;yourjar.jar YourMainClass
on UNIX/Linux
java -classpath .:yourjar.jar YourMainClass
edited Jul 1 '13 at 16:05
answered Jul 1 '13 at 16:00
Juned AhsanJuned Ahsan
55.3k970105
55.3k970105
add a comment |
add a comment |
Try these if you use maven. I use maven for my project and when I do mvn clean install
and try to run a program it throws the exception. So, I clean the project and run it again and it works for me.
I use eclipse IDE.
For Class Not Found Exception when running Junit test, try running mvn clean test
once. It will compile all the test classes.
what directory were you in when you ran "mvn clean test"? is it in the same directory as the POM?
– TacoB0t
Mar 27 '18 at 16:19
1
Yes. Ran it from the directory where pom file is present.
– Arun
Mar 27 '18 at 18:26
add a comment |
Try these if you use maven. I use maven for my project and when I do mvn clean install
and try to run a program it throws the exception. So, I clean the project and run it again and it works for me.
I use eclipse IDE.
For Class Not Found Exception when running Junit test, try running mvn clean test
once. It will compile all the test classes.
what directory were you in when you ran "mvn clean test"? is it in the same directory as the POM?
– TacoB0t
Mar 27 '18 at 16:19
1
Yes. Ran it from the directory where pom file is present.
– Arun
Mar 27 '18 at 18:26
add a comment |
Try these if you use maven. I use maven for my project and when I do mvn clean install
and try to run a program it throws the exception. So, I clean the project and run it again and it works for me.
I use eclipse IDE.
For Class Not Found Exception when running Junit test, try running mvn clean test
once. It will compile all the test classes.
Try these if you use maven. I use maven for my project and when I do mvn clean install
and try to run a program it throws the exception. So, I clean the project and run it again and it works for me.
I use eclipse IDE.
For Class Not Found Exception when running Junit test, try running mvn clean test
once. It will compile all the test classes.
edited Sep 5 '18 at 6:29
answered Apr 22 '15 at 19:48
ArunArun
1,17711326
1,17711326
what directory were you in when you ran "mvn clean test"? is it in the same directory as the POM?
– TacoB0t
Mar 27 '18 at 16:19
1
Yes. Ran it from the directory where pom file is present.
– Arun
Mar 27 '18 at 18:26
add a comment |
what directory were you in when you ran "mvn clean test"? is it in the same directory as the POM?
– TacoB0t
Mar 27 '18 at 16:19
1
Yes. Ran it from the directory where pom file is present.
– Arun
Mar 27 '18 at 18:26
what directory were you in when you ran "mvn clean test"? is it in the same directory as the POM?
– TacoB0t
Mar 27 '18 at 16:19
what directory were you in when you ran "mvn clean test"? is it in the same directory as the POM?
– TacoB0t
Mar 27 '18 at 16:19
1
1
Yes. Ran it from the directory where pom file is present.
– Arun
Mar 27 '18 at 18:26
Yes. Ran it from the directory where pom file is present.
– Arun
Mar 27 '18 at 18:26
add a comment |
To add the location of a class to your classpath via command line simply add -cp
or -classpath
and the location of the class while running it. I.E.
java -cp "c:/location/of/file" YourProgram
Or if you're running an IDE such as eclipse you can right click on the project -> build path -> configure build path
and add the external JAR containing your class to the build path then it should work fine.
add a comment |
To add the location of a class to your classpath via command line simply add -cp
or -classpath
and the location of the class while running it. I.E.
java -cp "c:/location/of/file" YourProgram
Or if you're running an IDE such as eclipse you can right click on the project -> build path -> configure build path
and add the external JAR containing your class to the build path then it should work fine.
add a comment |
To add the location of a class to your classpath via command line simply add -cp
or -classpath
and the location of the class while running it. I.E.
java -cp "c:/location/of/file" YourProgram
Or if you're running an IDE such as eclipse you can right click on the project -> build path -> configure build path
and add the external JAR containing your class to the build path then it should work fine.
To add the location of a class to your classpath via command line simply add -cp
or -classpath
and the location of the class while running it. I.E.
java -cp "c:/location/of/file" YourProgram
Or if you're running an IDE such as eclipse you can right click on the project -> build path -> configure build path
and add the external JAR containing your class to the build path then it should work fine.
edited Jul 1 '13 at 16:23
Imane Fateh
2,17531221
2,17531221
answered Jul 1 '13 at 16:05
invictvs1invictvs1
119315
119315
add a comment |
add a comment |
Use ';' as the separator. If your environment variables are set correctly, you should see your settings. If your PATH and CLASSPATH is correct, windows should recognize those commands. You do NOT need to restart your computer when installing Java.
5
That is on windows (semicolon) , on unix/linux it is ':' (colon)
– Joeblade
Jan 19 '15 at 8:38
add a comment |
Use ';' as the separator. If your environment variables are set correctly, you should see your settings. If your PATH and CLASSPATH is correct, windows should recognize those commands. You do NOT need to restart your computer when installing Java.
5
That is on windows (semicolon) , on unix/linux it is ':' (colon)
– Joeblade
Jan 19 '15 at 8:38
add a comment |
Use ';' as the separator. If your environment variables are set correctly, you should see your settings. If your PATH and CLASSPATH is correct, windows should recognize those commands. You do NOT need to restart your computer when installing Java.
Use ';' as the separator. If your environment variables are set correctly, you should see your settings. If your PATH and CLASSPATH is correct, windows should recognize those commands. You do NOT need to restart your computer when installing Java.
answered Jan 19 '15 at 8:33
Kiran S KulkarniKiran S Kulkarni
100211
100211
5
That is on windows (semicolon) , on unix/linux it is ':' (colon)
– Joeblade
Jan 19 '15 at 8:38
add a comment |
5
That is on windows (semicolon) , on unix/linux it is ':' (colon)
– Joeblade
Jan 19 '15 at 8:38
5
5
That is on windows (semicolon) , on unix/linux it is ':' (colon)
– Joeblade
Jan 19 '15 at 8:38
That is on windows (semicolon) , on unix/linux it is ':' (colon)
– Joeblade
Jan 19 '15 at 8:38
add a comment |
Add the full path of jar file to the CLASSPATH.
In linux use: export CLASSPATH=".:/full/path/to/file.jar:$CLASSPATH"
. Other way worked (without editing the CLASSPATH) was unzipping the jar in the current project folder.
Ways didn't work for me:
1) Using -cp
option with full path of jar file.
2) Using -cp
with only the name of jar when located in the current folder
3) Copying the jar to the current project folder
4) Copying the jar to standard location of java jars (/usr/share/java)
This solution is reported for class com.mysql.jdbc.Driver in mysql-connector-java.5-*.jar, working on linux with OpenJDK version 1.7
Only unzipping the JAR worked for me, none of the other solutions did
– OverCoder
Jun 5 '16 at 23:05
add a comment |
Add the full path of jar file to the CLASSPATH.
In linux use: export CLASSPATH=".:/full/path/to/file.jar:$CLASSPATH"
. Other way worked (without editing the CLASSPATH) was unzipping the jar in the current project folder.
Ways didn't work for me:
1) Using -cp
option with full path of jar file.
2) Using -cp
with only the name of jar when located in the current folder
3) Copying the jar to the current project folder
4) Copying the jar to standard location of java jars (/usr/share/java)
This solution is reported for class com.mysql.jdbc.Driver in mysql-connector-java.5-*.jar, working on linux with OpenJDK version 1.7
Only unzipping the JAR worked for me, none of the other solutions did
– OverCoder
Jun 5 '16 at 23:05
add a comment |
Add the full path of jar file to the CLASSPATH.
In linux use: export CLASSPATH=".:/full/path/to/file.jar:$CLASSPATH"
. Other way worked (without editing the CLASSPATH) was unzipping the jar in the current project folder.
Ways didn't work for me:
1) Using -cp
option with full path of jar file.
2) Using -cp
with only the name of jar when located in the current folder
3) Copying the jar to the current project folder
4) Copying the jar to standard location of java jars (/usr/share/java)
This solution is reported for class com.mysql.jdbc.Driver in mysql-connector-java.5-*.jar, working on linux with OpenJDK version 1.7
Add the full path of jar file to the CLASSPATH.
In linux use: export CLASSPATH=".:/full/path/to/file.jar:$CLASSPATH"
. Other way worked (without editing the CLASSPATH) was unzipping the jar in the current project folder.
Ways didn't work for me:
1) Using -cp
option with full path of jar file.
2) Using -cp
with only the name of jar when located in the current folder
3) Copying the jar to the current project folder
4) Copying the jar to standard location of java jars (/usr/share/java)
This solution is reported for class com.mysql.jdbc.Driver in mysql-connector-java.5-*.jar, working on linux with OpenJDK version 1.7
edited Dec 4 '15 at 9:10
answered Dec 4 '15 at 9:05
Annonnymous PersonAnnonnymous Person
312
312
Only unzipping the JAR worked for me, none of the other solutions did
– OverCoder
Jun 5 '16 at 23:05
add a comment |
Only unzipping the JAR worked for me, none of the other solutions did
– OverCoder
Jun 5 '16 at 23:05
Only unzipping the JAR worked for me, none of the other solutions did
– OverCoder
Jun 5 '16 at 23:05
Only unzipping the JAR worked for me, none of the other solutions did
– OverCoder
Jun 5 '16 at 23:05
add a comment |
Go up to the top and remove the import statement if there is one, and re import the class. But if that isn't the case do a clean then build. Are you using Netbeans or Eclipse?
add a comment |
Go up to the top and remove the import statement if there is one, and re import the class. But if that isn't the case do a clean then build. Are you using Netbeans or Eclipse?
add a comment |
Go up to the top and remove the import statement if there is one, and re import the class. But if that isn't the case do a clean then build. Are you using Netbeans or Eclipse?
Go up to the top and remove the import statement if there is one, and re import the class. But if that isn't the case do a clean then build. Are you using Netbeans or Eclipse?
answered Jul 1 '13 at 16:04
yamsyams
14331952
14331952
add a comment |
add a comment |
I ran into this as well and tried all of the other solutions. I did not have the .class file in my HTML folder, I only had the .java file. Once I added the .class file the program worked fine.
add a comment |
I ran into this as well and tried all of the other solutions. I did not have the .class file in my HTML folder, I only had the .java file. Once I added the .class file the program worked fine.
add a comment |
I ran into this as well and tried all of the other solutions. I did not have the .class file in my HTML folder, I only had the .java file. Once I added the .class file the program worked fine.
I ran into this as well and tried all of the other solutions. I did not have the .class file in my HTML folder, I only had the .java file. Once I added the .class file the program worked fine.
answered Jan 13 '14 at 15:35
Jason RobertsonJason Robertson
211
211
add a comment |
add a comment |
It could happen if your classpath is not correct
Let us posit a serializable class and deserializable class under same projectname. You run the serializable class, creating a serializable object in specific folder. Now you need the desearialized data. In the meantime, if you change the name of the project it will not work. You have to run the serializable class first and then deserialize the file.
add a comment |
It could happen if your classpath is not correct
Let us posit a serializable class and deserializable class under same projectname. You run the serializable class, creating a serializable object in specific folder. Now you need the desearialized data. In the meantime, if you change the name of the project it will not work. You have to run the serializable class first and then deserialize the file.
add a comment |
It could happen if your classpath is not correct
Let us posit a serializable class and deserializable class under same projectname. You run the serializable class, creating a serializable object in specific folder. Now you need the desearialized data. In the meantime, if you change the name of the project it will not work. You have to run the serializable class first and then deserialize the file.
It could happen if your classpath is not correct
Let us posit a serializable class and deserializable class under same projectname. You run the serializable class, creating a serializable object in specific folder. Now you need the desearialized data. In the meantime, if you change the name of the project it will not work. You have to run the serializable class first and then deserialize the file.
edited Feb 10 '14 at 22:24
Nathaniel Ford
13.7k155675
13.7k155675
answered Feb 10 '14 at 22:05
Omar Faroque AnikOmar Faroque Anik
1,9622130
1,9622130
add a comment |
add a comment |
If you are using maven
try to maven update all projects and force for snapshots.
It will clean as well and rebuilt all classpath..
It solved my problem..
add a comment |
If you are using maven
try to maven update all projects and force for snapshots.
It will clean as well and rebuilt all classpath..
It solved my problem..
add a comment |
If you are using maven
try to maven update all projects and force for snapshots.
It will clean as well and rebuilt all classpath..
It solved my problem..
If you are using maven
try to maven update all projects and force for snapshots.
It will clean as well and rebuilt all classpath..
It solved my problem..
answered Jan 11 '17 at 8:16
ibrahimgunesibrahimgunes
967
967
add a comment |
add a comment |
I just did
1.Invalidate caches and restart
2.Rebuilt my project which solved the problem
add a comment |
I just did
1.Invalidate caches and restart
2.Rebuilt my project which solved the problem
add a comment |
I just did
1.Invalidate caches and restart
2.Rebuilt my project which solved the problem
I just did
1.Invalidate caches and restart
2.Rebuilt my project which solved the problem
answered Feb 19 '18 at 11:27
Jyoti JKJyoti JK
1,5971728
1,5971728
add a comment |
add a comment |
I was trying to run .jar from C# code using Process
class. The java code ran successfully from eclipse but it doesn't from C# visual studio and even clicking directly on the jar file, it always stopped with ClassNotFoundException:
exception. Solution for my, was export the java program as "Runnable JAR file" instead of "JAR File". Hope it can help someone.
add a comment |
I was trying to run .jar from C# code using Process
class. The java code ran successfully from eclipse but it doesn't from C# visual studio and even clicking directly on the jar file, it always stopped with ClassNotFoundException:
exception. Solution for my, was export the java program as "Runnable JAR file" instead of "JAR File". Hope it can help someone.
add a comment |
I was trying to run .jar from C# code using Process
class. The java code ran successfully from eclipse but it doesn't from C# visual studio and even clicking directly on the jar file, it always stopped with ClassNotFoundException:
exception. Solution for my, was export the java program as "Runnable JAR file" instead of "JAR File". Hope it can help someone.
I was trying to run .jar from C# code using Process
class. The java code ran successfully from eclipse but it doesn't from C# visual studio and even clicking directly on the jar file, it always stopped with ClassNotFoundException:
exception. Solution for my, was export the java program as "Runnable JAR file" instead of "JAR File". Hope it can help someone.
answered Feb 14 '18 at 13:24
Dani AyaDani Aya
1158
1158
add a comment |
add a comment |
This can happen on Windows after a java update where the old version of the java SDK is missing and a new one is present. I would check if your IDE is using the installed java SDK version (IntelliJ: CTRL + SHIFT + ALT + S)
add a comment |
This can happen on Windows after a java update where the old version of the java SDK is missing and a new one is present. I would check if your IDE is using the installed java SDK version (IntelliJ: CTRL + SHIFT + ALT + S)
add a comment |
This can happen on Windows after a java update where the old version of the java SDK is missing and a new one is present. I would check if your IDE is using the installed java SDK version (IntelliJ: CTRL + SHIFT + ALT + S)
This can happen on Windows after a java update where the old version of the java SDK is missing and a new one is present. I would check if your IDE is using the installed java SDK version (IntelliJ: CTRL + SHIFT + ALT + S)
answered Apr 3 '18 at 14:03
s5ss5s
2,429114583
2,429114583
add a comment |
add a comment |
If you have added multiple (Third-Party)**libraries and Extends **Application class
Then it might occur.
For that, you have to set multiDexEnabled true
and replace your extended Application
class with MultiDexApplication
.
It will be solved.
add a comment |
If you have added multiple (Third-Party)**libraries and Extends **Application class
Then it might occur.
For that, you have to set multiDexEnabled true
and replace your extended Application
class with MultiDexApplication
.
It will be solved.
add a comment |
If you have added multiple (Third-Party)**libraries and Extends **Application class
Then it might occur.
For that, you have to set multiDexEnabled true
and replace your extended Application
class with MultiDexApplication
.
It will be solved.
If you have added multiple (Third-Party)**libraries and Extends **Application class
Then it might occur.
For that, you have to set multiDexEnabled true
and replace your extended Application
class with MultiDexApplication
.
It will be solved.
answered Sep 22 '18 at 9:41
Parth PatelParth Patel
53069
53069
add a comment |
add a comment |
Basic Generic Question - Simplest Generic Answer ;)
Given the information I will make the assumption that you might be trying a basic approach to coding, building/compiling and running a simple console app like "Hello World", using some simple text editor and some Command Shell.
This error occurs in the fallowing scenario:
..SomePath>javac HelloWorld.java
..SomePath>java HelloWorld.class
In other words, use:
..SomePath>java HelloWorld
P.S. The adding the file extension .class produces the same mistake.
Also be sure to have the Java's (JDK/JRE) bin folder in the operating system's Environment Variables's PATH.(Lookup for more details other posts on this)
P.P.S Was I correct in my assumption/s?
add a comment |
Basic Generic Question - Simplest Generic Answer ;)
Given the information I will make the assumption that you might be trying a basic approach to coding, building/compiling and running a simple console app like "Hello World", using some simple text editor and some Command Shell.
This error occurs in the fallowing scenario:
..SomePath>javac HelloWorld.java
..SomePath>java HelloWorld.class
In other words, use:
..SomePath>java HelloWorld
P.S. The adding the file extension .class produces the same mistake.
Also be sure to have the Java's (JDK/JRE) bin folder in the operating system's Environment Variables's PATH.(Lookup for more details other posts on this)
P.P.S Was I correct in my assumption/s?
add a comment |
Basic Generic Question - Simplest Generic Answer ;)
Given the information I will make the assumption that you might be trying a basic approach to coding, building/compiling and running a simple console app like "Hello World", using some simple text editor and some Command Shell.
This error occurs in the fallowing scenario:
..SomePath>javac HelloWorld.java
..SomePath>java HelloWorld.class
In other words, use:
..SomePath>java HelloWorld
P.S. The adding the file extension .class produces the same mistake.
Also be sure to have the Java's (JDK/JRE) bin folder in the operating system's Environment Variables's PATH.(Lookup for more details other posts on this)
P.P.S Was I correct in my assumption/s?
Basic Generic Question - Simplest Generic Answer ;)
Given the information I will make the assumption that you might be trying a basic approach to coding, building/compiling and running a simple console app like "Hello World", using some simple text editor and some Command Shell.
This error occurs in the fallowing scenario:
..SomePath>javac HelloWorld.java
..SomePath>java HelloWorld.class
In other words, use:
..SomePath>java HelloWorld
P.S. The adding the file extension .class produces the same mistake.
Also be sure to have the Java's (JDK/JRE) bin folder in the operating system's Environment Variables's PATH.(Lookup for more details other posts on this)
P.P.S Was I correct in my assumption/s?
answered Feb 13 at 18:43
VasilVasil
1115
1115
add a comment |
add a comment |
Put all the code in try block then catch exception in a catch block
try
{
// code
}
catch(ClassNotFoundException e1)
{
e1.getmessage();
}
2
This does not resolve the exception. This hides the exception. Furthermore, "e1.getmessage()" is a) the wrong capitalisation of getMessage() and b) not going to do very much as it returns a string with a message and you're not printing it or logging it or anything!
– IBBoard
Aug 30 '16 at 12:15
add a comment |
Put all the code in try block then catch exception in a catch block
try
{
// code
}
catch(ClassNotFoundException e1)
{
e1.getmessage();
}
2
This does not resolve the exception. This hides the exception. Furthermore, "e1.getmessage()" is a) the wrong capitalisation of getMessage() and b) not going to do very much as it returns a string with a message and you're not printing it or logging it or anything!
– IBBoard
Aug 30 '16 at 12:15
add a comment |
Put all the code in try block then catch exception in a catch block
try
{
// code
}
catch(ClassNotFoundException e1)
{
e1.getmessage();
}
Put all the code in try block then catch exception in a catch block
try
{
// code
}
catch(ClassNotFoundException e1)
{
e1.getmessage();
}
edited Feb 24 '15 at 1:48
C. Leung
4,74521431
4,74521431
answered Feb 23 '15 at 15:53
sharukhsharukh
17
17
2
This does not resolve the exception. This hides the exception. Furthermore, "e1.getmessage()" is a) the wrong capitalisation of getMessage() and b) not going to do very much as it returns a string with a message and you're not printing it or logging it or anything!
– IBBoard
Aug 30 '16 at 12:15
add a comment |
2
This does not resolve the exception. This hides the exception. Furthermore, "e1.getmessage()" is a) the wrong capitalisation of getMessage() and b) not going to do very much as it returns a string with a message and you're not printing it or logging it or anything!
– IBBoard
Aug 30 '16 at 12:15
2
2
This does not resolve the exception. This hides the exception. Furthermore, "e1.getmessage()" is a) the wrong capitalisation of getMessage() and b) not going to do very much as it returns a string with a message and you're not printing it or logging it or anything!
– IBBoard
Aug 30 '16 at 12:15
This does not resolve the exception. This hides the exception. Furthermore, "e1.getmessage()" is a) the wrong capitalisation of getMessage() and b) not going to do very much as it returns a string with a message and you're not printing it or logging it or anything!
– IBBoard
Aug 30 '16 at 12:15
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protected by Community♦ Jul 9 '16 at 17:57
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You must add the jar which has the missing class to the classptah
– Crom
Jul 1 '13 at 16:00
if your class has a package then go to the folder containing the class. e.g if package is package test.abc, then go to folder before test and then do java -cp . test.abc.CLASSNAME (without .class). If there's no package then go to folder containing class and say java -cp . CLASSNAME
– Optional
Jul 1 '13 at 16:05
Either a class was not deployed to your runtime (for example missing jar), or the class is not visible in a given class loader, check this this tool that helps troubleshooting these problems: jhades.org
– Angular University
Dec 6 '13 at 12:05
I also run into this sometimes. This exception clearly violates the rule of stating all necessary context in an exception message. It should mention where it tried to look for the thing, what is on your classpath. Please make better exception messages. Don't make us hunt for information which could help solve the problem.
– masterxilo
Nov 25 '18 at 14:12