How to aggregate data with condition using two arrays?





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I have M and W data sets and the structure is as follow:



M = [
'ModuleName': 'GDD',
{Fields: [
{'FieldID': 5, 'Date': '2018-12-01'},
{'FieldID': 6, 'Date': '2018-12-01'}
]
}
]

W = [
{'FieldID': 5, 'Value': 10, 'WDate': 2018-06-05'},
{'FieldID': 5, 'Value': 10, 'WDate': 2018-06-05'},
{'FieldID': 6, 'Value': 50, 'WDate': 2018-07-05'},
{'FieldID': 6, 'Value': 20, 'WDate': 2018-09-05'}
]


I want to calculate value of all fields from W data set and group by FieldID with date condition from M data set.



M.forEach(m => {
if (m.ModuleName === 'GDD') {
m.Fields.forEach(f => {
const sum = W.map(w => w.Value).reduce((acc, value) => acc + value, 0);
});
}
});


Condition: If Date from M.Fields is equal or more than date from W.wDate.



Since the data sets are huge, I also need to consider efficiency.



The expected output is to add another property and store sum of Value in the m.Fields field object.



M = [
'ModuleName': 'GDD',
{Fields: [
{'FieldID': 5, 'Date': '2018-10-01', 'sum': 20},
{'FieldID': 6, 'Date': '2018-10-01', 'sum': 70}
]
}
]









share|improve this question




















  • 1





    Can you pls also tell the expected output

    – Nitish Narang
    Nov 23 '18 at 17:07











  • Can you also please include a little more of your data? You've just included 1 object from both M and W.

    – slider
    Nov 23 '18 at 17:08











  • But why do you have 2 similar objects in Fields? Won't they have the same sum?

    – slider
    Nov 23 '18 at 17:16


















0















I have M and W data sets and the structure is as follow:



M = [
'ModuleName': 'GDD',
{Fields: [
{'FieldID': 5, 'Date': '2018-12-01'},
{'FieldID': 6, 'Date': '2018-12-01'}
]
}
]

W = [
{'FieldID': 5, 'Value': 10, 'WDate': 2018-06-05'},
{'FieldID': 5, 'Value': 10, 'WDate': 2018-06-05'},
{'FieldID': 6, 'Value': 50, 'WDate': 2018-07-05'},
{'FieldID': 6, 'Value': 20, 'WDate': 2018-09-05'}
]


I want to calculate value of all fields from W data set and group by FieldID with date condition from M data set.



M.forEach(m => {
if (m.ModuleName === 'GDD') {
m.Fields.forEach(f => {
const sum = W.map(w => w.Value).reduce((acc, value) => acc + value, 0);
});
}
});


Condition: If Date from M.Fields is equal or more than date from W.wDate.



Since the data sets are huge, I also need to consider efficiency.



The expected output is to add another property and store sum of Value in the m.Fields field object.



M = [
'ModuleName': 'GDD',
{Fields: [
{'FieldID': 5, 'Date': '2018-10-01', 'sum': 20},
{'FieldID': 6, 'Date': '2018-10-01', 'sum': 70}
]
}
]









share|improve this question




















  • 1





    Can you pls also tell the expected output

    – Nitish Narang
    Nov 23 '18 at 17:07











  • Can you also please include a little more of your data? You've just included 1 object from both M and W.

    – slider
    Nov 23 '18 at 17:08











  • But why do you have 2 similar objects in Fields? Won't they have the same sum?

    – slider
    Nov 23 '18 at 17:16














0












0








0








I have M and W data sets and the structure is as follow:



M = [
'ModuleName': 'GDD',
{Fields: [
{'FieldID': 5, 'Date': '2018-12-01'},
{'FieldID': 6, 'Date': '2018-12-01'}
]
}
]

W = [
{'FieldID': 5, 'Value': 10, 'WDate': 2018-06-05'},
{'FieldID': 5, 'Value': 10, 'WDate': 2018-06-05'},
{'FieldID': 6, 'Value': 50, 'WDate': 2018-07-05'},
{'FieldID': 6, 'Value': 20, 'WDate': 2018-09-05'}
]


I want to calculate value of all fields from W data set and group by FieldID with date condition from M data set.



M.forEach(m => {
if (m.ModuleName === 'GDD') {
m.Fields.forEach(f => {
const sum = W.map(w => w.Value).reduce((acc, value) => acc + value, 0);
});
}
});


Condition: If Date from M.Fields is equal or more than date from W.wDate.



Since the data sets are huge, I also need to consider efficiency.



The expected output is to add another property and store sum of Value in the m.Fields field object.



M = [
'ModuleName': 'GDD',
{Fields: [
{'FieldID': 5, 'Date': '2018-10-01', 'sum': 20},
{'FieldID': 6, 'Date': '2018-10-01', 'sum': 70}
]
}
]









share|improve this question
















I have M and W data sets and the structure is as follow:



M = [
'ModuleName': 'GDD',
{Fields: [
{'FieldID': 5, 'Date': '2018-12-01'},
{'FieldID': 6, 'Date': '2018-12-01'}
]
}
]

W = [
{'FieldID': 5, 'Value': 10, 'WDate': 2018-06-05'},
{'FieldID': 5, 'Value': 10, 'WDate': 2018-06-05'},
{'FieldID': 6, 'Value': 50, 'WDate': 2018-07-05'},
{'FieldID': 6, 'Value': 20, 'WDate': 2018-09-05'}
]


I want to calculate value of all fields from W data set and group by FieldID with date condition from M data set.



M.forEach(m => {
if (m.ModuleName === 'GDD') {
m.Fields.forEach(f => {
const sum = W.map(w => w.Value).reduce((acc, value) => acc + value, 0);
});
}
});


Condition: If Date from M.Fields is equal or more than date from W.wDate.



Since the data sets are huge, I also need to consider efficiency.



The expected output is to add another property and store sum of Value in the m.Fields field object.



M = [
'ModuleName': 'GDD',
{Fields: [
{'FieldID': 5, 'Date': '2018-10-01', 'sum': 20},
{'FieldID': 6, 'Date': '2018-10-01', 'sum': 70}
]
}
]






javascript






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 17:36







Maihan Nijat

















asked Nov 23 '18 at 17:06









Maihan NijatMaihan Nijat

2,99822550




2,99822550








  • 1





    Can you pls also tell the expected output

    – Nitish Narang
    Nov 23 '18 at 17:07











  • Can you also please include a little more of your data? You've just included 1 object from both M and W.

    – slider
    Nov 23 '18 at 17:08











  • But why do you have 2 similar objects in Fields? Won't they have the same sum?

    – slider
    Nov 23 '18 at 17:16














  • 1





    Can you pls also tell the expected output

    – Nitish Narang
    Nov 23 '18 at 17:07











  • Can you also please include a little more of your data? You've just included 1 object from both M and W.

    – slider
    Nov 23 '18 at 17:08











  • But why do you have 2 similar objects in Fields? Won't they have the same sum?

    – slider
    Nov 23 '18 at 17:16








1




1





Can you pls also tell the expected output

– Nitish Narang
Nov 23 '18 at 17:07





Can you pls also tell the expected output

– Nitish Narang
Nov 23 '18 at 17:07













Can you also please include a little more of your data? You've just included 1 object from both M and W.

– slider
Nov 23 '18 at 17:08





Can you also please include a little more of your data? You've just included 1 object from both M and W.

– slider
Nov 23 '18 at 17:08













But why do you have 2 similar objects in Fields? Won't they have the same sum?

– slider
Nov 23 '18 at 17:16





But why do you have 2 similar objects in Fields? Won't they have the same sum?

– slider
Nov 23 '18 at 17:16












1 Answer
1






active

oldest

votes


















1














For efficiency:




  1. Convert to an object for quicker accessibility

  2. Use for loops, not forEach





'use strict';

const M = {
'ModuleName': 'GDD',
Fields: [
{'FieldID': 5, 'Date': '2018-05-01'},
{'FieldID': 6, 'Date': '2018-05-01'}
]

};

const W = [
{'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
{'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
{'FieldID': 6, 'Value': 50, 'WDate': '2018-07-05'},
{'FieldID': 6, 'Value': 20, 'WDate': '2018-09-05'}
];


let d, e, f = {};
// build object for quicker findability
for (e of M.Fields) {
f[e.FieldID] = e;
e.sum = 0;
}

for (e of W) {
if (d = f[e.FieldID]) {
if (e.WDate >= d.Date) {
d.sum += e.Value;
}
} else {
console.log(`could not find FieldID ${e.FieldID}`)
}
}

console.log(JSON.stringify(M, null, 4));








share|improve this answer
























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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    For efficiency:




    1. Convert to an object for quicker accessibility

    2. Use for loops, not forEach





    'use strict';

    const M = {
    'ModuleName': 'GDD',
    Fields: [
    {'FieldID': 5, 'Date': '2018-05-01'},
    {'FieldID': 6, 'Date': '2018-05-01'}
    ]

    };

    const W = [
    {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
    {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
    {'FieldID': 6, 'Value': 50, 'WDate': '2018-07-05'},
    {'FieldID': 6, 'Value': 20, 'WDate': '2018-09-05'}
    ];


    let d, e, f = {};
    // build object for quicker findability
    for (e of M.Fields) {
    f[e.FieldID] = e;
    e.sum = 0;
    }

    for (e of W) {
    if (d = f[e.FieldID]) {
    if (e.WDate >= d.Date) {
    d.sum += e.Value;
    }
    } else {
    console.log(`could not find FieldID ${e.FieldID}`)
    }
    }

    console.log(JSON.stringify(M, null, 4));








    share|improve this answer




























      1














      For efficiency:




      1. Convert to an object for quicker accessibility

      2. Use for loops, not forEach





      'use strict';

      const M = {
      'ModuleName': 'GDD',
      Fields: [
      {'FieldID': 5, 'Date': '2018-05-01'},
      {'FieldID': 6, 'Date': '2018-05-01'}
      ]

      };

      const W = [
      {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
      {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
      {'FieldID': 6, 'Value': 50, 'WDate': '2018-07-05'},
      {'FieldID': 6, 'Value': 20, 'WDate': '2018-09-05'}
      ];


      let d, e, f = {};
      // build object for quicker findability
      for (e of M.Fields) {
      f[e.FieldID] = e;
      e.sum = 0;
      }

      for (e of W) {
      if (d = f[e.FieldID]) {
      if (e.WDate >= d.Date) {
      d.sum += e.Value;
      }
      } else {
      console.log(`could not find FieldID ${e.FieldID}`)
      }
      }

      console.log(JSON.stringify(M, null, 4));








      share|improve this answer


























        1












        1








        1







        For efficiency:




        1. Convert to an object for quicker accessibility

        2. Use for loops, not forEach





        'use strict';

        const M = {
        'ModuleName': 'GDD',
        Fields: [
        {'FieldID': 5, 'Date': '2018-05-01'},
        {'FieldID': 6, 'Date': '2018-05-01'}
        ]

        };

        const W = [
        {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
        {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
        {'FieldID': 6, 'Value': 50, 'WDate': '2018-07-05'},
        {'FieldID': 6, 'Value': 20, 'WDate': '2018-09-05'}
        ];


        let d, e, f = {};
        // build object for quicker findability
        for (e of M.Fields) {
        f[e.FieldID] = e;
        e.sum = 0;
        }

        for (e of W) {
        if (d = f[e.FieldID]) {
        if (e.WDate >= d.Date) {
        d.sum += e.Value;
        }
        } else {
        console.log(`could not find FieldID ${e.FieldID}`)
        }
        }

        console.log(JSON.stringify(M, null, 4));








        share|improve this answer













        For efficiency:




        1. Convert to an object for quicker accessibility

        2. Use for loops, not forEach





        'use strict';

        const M = {
        'ModuleName': 'GDD',
        Fields: [
        {'FieldID': 5, 'Date': '2018-05-01'},
        {'FieldID': 6, 'Date': '2018-05-01'}
        ]

        };

        const W = [
        {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
        {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
        {'FieldID': 6, 'Value': 50, 'WDate': '2018-07-05'},
        {'FieldID': 6, 'Value': 20, 'WDate': '2018-09-05'}
        ];


        let d, e, f = {};
        // build object for quicker findability
        for (e of M.Fields) {
        f[e.FieldID] = e;
        e.sum = 0;
        }

        for (e of W) {
        if (d = f[e.FieldID]) {
        if (e.WDate >= d.Date) {
        d.sum += e.Value;
        }
        } else {
        console.log(`could not find FieldID ${e.FieldID}`)
        }
        }

        console.log(JSON.stringify(M, null, 4));








        'use strict';

        const M = {
        'ModuleName': 'GDD',
        Fields: [
        {'FieldID': 5, 'Date': '2018-05-01'},
        {'FieldID': 6, 'Date': '2018-05-01'}
        ]

        };

        const W = [
        {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
        {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
        {'FieldID': 6, 'Value': 50, 'WDate': '2018-07-05'},
        {'FieldID': 6, 'Value': 20, 'WDate': '2018-09-05'}
        ];


        let d, e, f = {};
        // build object for quicker findability
        for (e of M.Fields) {
        f[e.FieldID] = e;
        e.sum = 0;
        }

        for (e of W) {
        if (d = f[e.FieldID]) {
        if (e.WDate >= d.Date) {
        d.sum += e.Value;
        }
        } else {
        console.log(`could not find FieldID ${e.FieldID}`)
        }
        }

        console.log(JSON.stringify(M, null, 4));





        'use strict';

        const M = {
        'ModuleName': 'GDD',
        Fields: [
        {'FieldID': 5, 'Date': '2018-05-01'},
        {'FieldID': 6, 'Date': '2018-05-01'}
        ]

        };

        const W = [
        {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
        {'FieldID': 5, 'Value': 10, 'WDate': '2018-06-05'},
        {'FieldID': 6, 'Value': 50, 'WDate': '2018-07-05'},
        {'FieldID': 6, 'Value': 20, 'WDate': '2018-09-05'}
        ];


        let d, e, f = {};
        // build object for quicker findability
        for (e of M.Fields) {
        f[e.FieldID] = e;
        e.sum = 0;
        }

        for (e of W) {
        if (d = f[e.FieldID]) {
        if (e.WDate >= d.Date) {
        d.sum += e.Value;
        }
        } else {
        console.log(`could not find FieldID ${e.FieldID}`)
        }
        }

        console.log(JSON.stringify(M, null, 4));






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 23 '18 at 17:47









        niryniry

        1,4791222




        1,4791222
































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