Why errors appear at Ruby?
Objective
Add (uri, url) with port.
# Help for carlos-romero
# https://stackoverflow.com
# Help for mu-is-too-short
# https://stackoverflow.com
require 'uri'
require 'socket'
url = 'file://C://'
class Class1
def fileProtocol( url )
uri = URI(url) if scheme = uri.scheme
puts fileProtocol(url)
end
end
class Class2
def fileProtocolPort( server )
server = TCPServer.open(8080)
for i in 0..5
client = server.accept
client.puts(Time.now.ctime)
client.puts "Closing the connection. Bye!"
client.close
end
end
end
ruby show this errors
Traceback (most recent call last):
2: from main.rb:7:in<main>'open'
1: from main.rb:7:in
main.rb:7:in `initialize': Address already in use - bind(2) for nil port 8080 (Errno::EADDRINUSE)
So, what does that mean this error? Can you help me?
ruby sockets url uri protocols
asked Nov 21 '18 at 20:25
Eduardo Paulo MigoEduardo Paulo Migo
11
add a comment |
Objective
Add (uri, url) with port.
# Help for carlos-romero
# https://stackoverflow.com
# Help for mu-is-too-short
# https://stackoverflow.com
require 'uri'
require 'socket'
url = 'file://C://'
class Class1
def fileProtocol( url )
uri = URI(url) if scheme = uri.scheme
puts fileProtocol(url)
end
end
class Class2
def fileProtocolPort( server )
server = TCPServer.open(8080)
for i in 0..5
client = server.accept
client.puts(Time.now.ctime)
client.puts "Closing the connection. Bye!"
client.close
end
end
end
ruby show this errors
Traceback (most recent call last):
2: from main.rb:7:in<main>'open'
1: from main.rb:7:in
main.rb:7:in `initialize': Address already in use - bind(2) for nil port 8080 (Errno::EADDRINUSE)
So, what does that mean this error? Can you help me?
ruby sockets url uri protocols
asked Nov 21 '18 at 20:25
Eduardo Paulo MigoEduardo Paulo Migo
11
add a comment |
Objective
Add (uri, url) with port.
# Help for carlos-romero
# https://stackoverflow.com
# Help for mu-is-too-short
# https://stackoverflow.com
require 'uri'
require 'socket'
url = 'file://C://'
class Class1
def fileProtocol( url )
uri = URI(url) if scheme = uri.scheme
puts fileProtocol(url)
end
end
class Class2
def fileProtocolPort( server )
server = TCPServer.open(8080)
for i in 0..5
client = server.accept
client.puts(Time.now.ctime)
client.puts "Closing the connection. Bye!"
client.close
end
end
end
ruby show this errors
Traceback (most recent call last):
2: from main.rb:7:in<main>'open'
1: from main.rb:7:in
main.rb:7:in `initialize': Address already in use - bind(2) for nil port 8080 (Errno::EADDRINUSE)
So, what does that mean this error? Can you help me?
ruby sockets url uri protocols
asked Nov 21 '18 at 20:25
Eduardo Paulo MigoEduardo Paulo Migo
11
Objective
Add (uri, url) with port.
# Help for carlos-romero
# https://stackoverflow.com
# Help for mu-is-too-short
# https://stackoverflow.com
require 'uri'
require 'socket'
url = 'file://C://'
class Class1
def fileProtocol( url )
uri = URI(url) if scheme = uri.scheme
puts fileProtocol(url)
end
end
class Class2
def fileProtocolPort( server )
server = TCPServer.open(8080)
for i in 0..5
client = server.accept
client.puts(Time.now.ctime)
client.puts "Closing the connection. Bye!"
client.close
end
end
end
ruby show this errors
Traceback (most recent call last):
2: from main.rb:7:in<main>'open'
1: from main.rb:7:in
main.rb:7:in `initialize': Address already in use - bind(2) for nil port 8080 (Errno::EADDRINUSE)
So, what does that mean this error? Can you help me?
ruby sockets url uri protocols
ruby sockets url uri protocols
asked Nov 21 '18 at 20:25
Eduardo Paulo MigoEduardo Paulo Migo
11
asked Nov 21 '18 at 20:25
Eduardo Paulo MigoEduardo Paulo Migo
11
edited Nov 22 '18 at 13:47
Eduardo Paulo Migo
asked Nov 21 '18 at 20:25
Eduardo Paulo MigoEduardo Paulo Migo
11
asked Nov 21 '18 at 20:25
Eduardo Paulo MigoEduardo Paulo Migo
11
asked Nov 21 '18 at 20:25
Eduardo Paulo MigoEduardo Paulo Migo
11
11
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I see a few problems there. In your method fileProtocol it seems like you are setting the value of uri with an inline if (do X if condition), so that end immediately following the if is unnecessary. Also, the = should be ==
I believe you want something like this:
def fileProtocol( url , server )
uri = URI(url, server) if scheme == uri.scheme
[url, server]
end
puts fileProtocol(url, server)
EDIT: Also, as @muistooshort pointed in the comments, the return value of the method (its last line) should wrap any multiple values you want to return in an array.
answered Nov 21 '18 at 20:48
Carlos RomeroCarlos Romero
237215
Thanks! I'll see if it works!
– Eduardo Paulo Migo
Nov 21 '18 at 20:52
syntax error, unexpected 'n', expecting '=' url, server
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
syntax error, unexpected end-of-input, expecting keyword_end puts fileProtocol(url)
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
these errors appeared
– Eduardo Paulo Migo
Nov 21 '18 at 20:58
1
I think you want[url, server]at the end of the method, Ruby doesn't really let you return multiple values, you explicitly return an array and then deconstruct it during the assignment.
– mu is too short
Nov 21 '18 at 21:11
|
show 1 more comment
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I see a few problems there. In your method fileProtocol it seems like you are setting the value of uri with an inline if (do X if condition), so that end immediately following the if is unnecessary. Also, the = should be ==
I believe you want something like this:
def fileProtocol( url , server )
uri = URI(url, server) if scheme == uri.scheme
[url, server]
end
puts fileProtocol(url, server)
EDIT: Also, as @muistooshort pointed in the comments, the return value of the method (its last line) should wrap any multiple values you want to return in an array.
answered Nov 21 '18 at 20:48
Carlos RomeroCarlos Romero
237215
Thanks! I'll see if it works!
– Eduardo Paulo Migo
Nov 21 '18 at 20:52
syntax error, unexpected 'n', expecting '=' url, server
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
syntax error, unexpected end-of-input, expecting keyword_end puts fileProtocol(url)
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
these errors appeared
– Eduardo Paulo Migo
Nov 21 '18 at 20:58
1
I think you want[url, server]at the end of the method, Ruby doesn't really let you return multiple values, you explicitly return an array and then deconstruct it during the assignment.
– mu is too short
Nov 21 '18 at 21:11
|
show 1 more comment
I see a few problems there. In your method fileProtocol it seems like you are setting the value of uri with an inline if (do X if condition), so that end immediately following the if is unnecessary. Also, the = should be ==
I believe you want something like this:
def fileProtocol( url , server )
uri = URI(url, server) if scheme == uri.scheme
[url, server]
end
puts fileProtocol(url, server)
EDIT: Also, as @muistooshort pointed in the comments, the return value of the method (its last line) should wrap any multiple values you want to return in an array.
answered Nov 21 '18 at 20:48
Carlos RomeroCarlos Romero
237215
Thanks! I'll see if it works!
– Eduardo Paulo Migo
Nov 21 '18 at 20:52
syntax error, unexpected 'n', expecting '=' url, server
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
syntax error, unexpected end-of-input, expecting keyword_end puts fileProtocol(url)
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
these errors appeared
– Eduardo Paulo Migo
Nov 21 '18 at 20:58
1
I think you want[url, server]at the end of the method, Ruby doesn't really let you return multiple values, you explicitly return an array and then deconstruct it during the assignment.
– mu is too short
Nov 21 '18 at 21:11
|
show 1 more comment
I see a few problems there. In your method fileProtocol it seems like you are setting the value of uri with an inline if (do X if condition), so that end immediately following the if is unnecessary. Also, the = should be ==
I believe you want something like this:
def fileProtocol( url , server )
uri = URI(url, server) if scheme == uri.scheme
[url, server]
end
puts fileProtocol(url, server)
EDIT: Also, as @muistooshort pointed in the comments, the return value of the method (its last line) should wrap any multiple values you want to return in an array.
answered Nov 21 '18 at 20:48
Carlos RomeroCarlos Romero
237215
I see a few problems there. In your method fileProtocol it seems like you are setting the value of uri with an inline if (do X if condition), so that end immediately following the if is unnecessary. Also, the = should be ==
I believe you want something like this:
def fileProtocol( url , server )
uri = URI(url, server) if scheme == uri.scheme
[url, server]
end
puts fileProtocol(url, server)
EDIT: Also, as @muistooshort pointed in the comments, the return value of the method (its last line) should wrap any multiple values you want to return in an array.
answered Nov 21 '18 at 20:48
Carlos RomeroCarlos Romero
237215
edited Nov 22 '18 at 11:40
answered Nov 21 '18 at 20:48
Carlos RomeroCarlos Romero
237215
answered Nov 21 '18 at 20:48
Carlos RomeroCarlos Romero
237215
answered Nov 21 '18 at 20:48
Carlos RomeroCarlos Romero
237215
237215
Thanks! I'll see if it works!
– Eduardo Paulo Migo
Nov 21 '18 at 20:52
syntax error, unexpected 'n', expecting '=' url, server
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
syntax error, unexpected end-of-input, expecting keyword_end puts fileProtocol(url)
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
these errors appeared
– Eduardo Paulo Migo
Nov 21 '18 at 20:58
1
I think you want[url, server]at the end of the method, Ruby doesn't really let you return multiple values, you explicitly return an array and then deconstruct it during the assignment.
– mu is too short
Nov 21 '18 at 21:11
|
show 1 more comment
Thanks! I'll see if it works!
– Eduardo Paulo Migo
Nov 21 '18 at 20:52
syntax error, unexpected 'n', expecting '=' url, server
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
syntax error, unexpected end-of-input, expecting keyword_end puts fileProtocol(url)
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
these errors appeared
– Eduardo Paulo Migo
Nov 21 '18 at 20:58
1
I think you want[url, server]at the end of the method, Ruby doesn't really let you return multiple values, you explicitly return an array and then deconstruct it during the assignment.
– mu is too short
Nov 21 '18 at 21:11
Thanks! I'll see if it works!
– Eduardo Paulo Migo
Nov 21 '18 at 20:52
Thanks! I'll see if it works!
– Eduardo Paulo Migo
Nov 21 '18 at 20:52
syntax error, unexpected 'n', expecting '=' url, server
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
syntax error, unexpected 'n', expecting '=' url, server
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
syntax error, unexpected end-of-input, expecting keyword_end puts fileProtocol(url)
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
syntax error, unexpected end-of-input, expecting keyword_end puts fileProtocol(url)
– Eduardo Paulo Migo
Nov 21 '18 at 20:57
these errors appeared
– Eduardo Paulo Migo
Nov 21 '18 at 20:58
these errors appeared
– Eduardo Paulo Migo
Nov 21 '18 at 20:58
1
1
I think you want
[url, server] at the end of the method, Ruby doesn't really let you return multiple values, you explicitly return an array and then deconstruct it during the assignment.– mu is too short
Nov 21 '18 at 21:11
I think you want
[url, server] at the end of the method, Ruby doesn't really let you return multiple values, you explicitly return an array and then deconstruct it during the assignment.– mu is too short
Nov 21 '18 at 21:11
|
show 1 more comment
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