Summarize multiple values with jq reduce
2
How to use jq's reduce function to handle multiple manipulations?
Given a model like:
{
"usage" : {
"os:linux" : {
"2018_11_18" : {
"amount" : 601046342,
"credits" : 99783
},
"2018_10_18" : {
"amount" : 839785106,
"credits" : 173121
}
}
}
}
And JQ file:
reduce .usage."os:linux" as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits
)
I Get:
{
"credits": 272904,
"minutes": 0
}
Cool, But I want to toal both fields, something like:
reduce .usage."os:linux" as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits,
."minutes" += $item.amount /1000/60
)
Semi-colons cause errors, commas pass, but just handles the last task, i,e,
{
"credits": 0,
"minutes": 24013.85746666667
}
json jq reduce
edited Nov 22 '18 at 7:42
peak
32.3k93959
asked Nov 21 '18 at 20:31
EddieEddie
6,28033245
add a comment |
2
How to use jq's reduce function to handle multiple manipulations?
Given a model like:
{
"usage" : {
"os:linux" : {
"2018_11_18" : {
"amount" : 601046342,
"credits" : 99783
},
"2018_10_18" : {
"amount" : 839785106,
"credits" : 173121
}
}
}
}
And JQ file:
reduce .usage."os:linux" as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits
)
I Get:
{
"credits": 272904,
"minutes": 0
}
Cool, But I want to toal both fields, something like:
reduce .usage."os:linux" as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits,
."minutes" += $item.amount /1000/60
)
Semi-colons cause errors, commas pass, but just handles the last task, i,e,
{
"credits": 0,
"minutes": 24013.85746666667
}
json jq reduce
edited Nov 22 '18 at 7:42
peak
32.3k93959
asked Nov 21 '18 at 20:31
EddieEddie
6,28033245
add a comment |
2
2
2
How to use jq's reduce function to handle multiple manipulations?
Given a model like:
{
"usage" : {
"os:linux" : {
"2018_11_18" : {
"amount" : 601046342,
"credits" : 99783
},
"2018_10_18" : {
"amount" : 839785106,
"credits" : 173121
}
}
}
}
And JQ file:
reduce .usage."os:linux" as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits
)
I Get:
{
"credits": 272904,
"minutes": 0
}
Cool, But I want to toal both fields, something like:
reduce .usage."os:linux" as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits,
."minutes" += $item.amount /1000/60
)
Semi-colons cause errors, commas pass, but just handles the last task, i,e,
{
"credits": 0,
"minutes": 24013.85746666667
}
json jq reduce
edited Nov 22 '18 at 7:42
peak
32.3k93959
asked Nov 21 '18 at 20:31
EddieEddie
6,28033245
How to use jq's reduce function to handle multiple manipulations?
Given a model like:
{
"usage" : {
"os:linux" : {
"2018_11_18" : {
"amount" : 601046342,
"credits" : 99783
},
"2018_10_18" : {
"amount" : 839785106,
"credits" : 173121
}
}
}
}
And JQ file:
reduce .usage."os:linux" as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits
)
I Get:
{
"credits": 272904,
"minutes": 0
}
Cool, But I want to toal both fields, something like:
reduce .usage."os:linux" as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits,
."minutes" += $item.amount /1000/60
)
Semi-colons cause errors, commas pass, but just handles the last task, i,e,
{
"credits": 0,
"minutes": 24013.85746666667
}
json jq reduce
json jq reduce
edited Nov 22 '18 at 7:42
peak
32.3k93959
asked Nov 21 '18 at 20:31
EddieEddie
6,28033245
edited Nov 22 '18 at 7:42
peak
32.3k93959
asked Nov 21 '18 at 20:31
EddieEddie
6,28033245
edited Nov 22 '18 at 7:42
peak
32.3k93959
edited Nov 22 '18 at 7:42
peak
32.3k93959
edited Nov 22 '18 at 7:42
peak
32.3k93959
32.3k93959
asked Nov 21 '18 at 20:31
EddieEddie
6,28033245
asked Nov 21 '18 at 20:31
EddieEddie
6,28033245
asked Nov 21 '18 at 20:31
EddieEddie
6,28033245
6,28033245
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
There's always the explicit way:
reduce .usage."os:linux" as $item (
{"credits": 0, "minutes": 0 };
{
"credits": (.credits + $item.credits),
"minutes": (.minutes + $item.amount / 60000)
}
)
answered Nov 21 '18 at 20:37
hobbshobbs
142k14150236
add a comment |
0
Or more succintly:
reduce .usage."os:linux" as $item (
{};
.credits += $item.credits
| .minutes += ($item.amount / 60000) )
Or ...
Or abstracting the reduction into the general-purpose utility function sigma/1:
def sigma(s): reduce s as $s (null; . + $s);
.usage."os:linux"
| {credits: sigma(..credits),
minutes: (sigma(..amount) / 60000) }
answered Nov 21 '18 at 21:13
peakpeak
32.3k93959
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
There's always the explicit way:
reduce .usage."os:linux" as $item (
{"credits": 0, "minutes": 0 };
{
"credits": (.credits + $item.credits),
"minutes": (.minutes + $item.amount / 60000)
}
)
answered Nov 21 '18 at 20:37
hobbshobbs
142k14150236
add a comment |
1
There's always the explicit way:
reduce .usage."os:linux" as $item (
{"credits": 0, "minutes": 0 };
{
"credits": (.credits + $item.credits),
"minutes": (.minutes + $item.amount / 60000)
}
)
answered Nov 21 '18 at 20:37
hobbshobbs
142k14150236
add a comment |
1
1
1
There's always the explicit way:
reduce .usage."os:linux" as $item (
{"credits": 0, "minutes": 0 };
{
"credits": (.credits + $item.credits),
"minutes": (.minutes + $item.amount / 60000)
}
)
answered Nov 21 '18 at 20:37
hobbshobbs
142k14150236
There's always the explicit way:
reduce .usage."os:linux" as $item (
{"credits": 0, "minutes": 0 };
{
"credits": (.credits + $item.credits),
"minutes": (.minutes + $item.amount / 60000)
}
)
answered Nov 21 '18 at 20:37
hobbshobbs
142k14150236
answered Nov 21 '18 at 20:37
hobbshobbs
142k14150236
answered Nov 21 '18 at 20:37
hobbshobbs
142k14150236
answered Nov 21 '18 at 20:37
hobbshobbs
142k14150236
142k14150236
add a comment |
add a comment |
0
Or more succintly:
reduce .usage."os:linux" as $item (
{};
.credits += $item.credits
| .minutes += ($item.amount / 60000) )
Or ...
Or abstracting the reduction into the general-purpose utility function sigma/1:
def sigma(s): reduce s as $s (null; . + $s);
.usage."os:linux"
| {credits: sigma(..credits),
minutes: (sigma(..amount) / 60000) }
answered Nov 21 '18 at 21:13
peakpeak
32.3k93959
add a comment |
0
Or more succintly:
reduce .usage."os:linux" as $item (
{};
.credits += $item.credits
| .minutes += ($item.amount / 60000) )
Or ...
Or abstracting the reduction into the general-purpose utility function sigma/1:
def sigma(s): reduce s as $s (null; . + $s);
.usage."os:linux"
| {credits: sigma(..credits),
minutes: (sigma(..amount) / 60000) }
answered Nov 21 '18 at 21:13
peakpeak
32.3k93959
add a comment |
0
0
0
Or more succintly:
reduce .usage."os:linux" as $item (
{};
.credits += $item.credits
| .minutes += ($item.amount / 60000) )
Or ...
Or abstracting the reduction into the general-purpose utility function sigma/1:
def sigma(s): reduce s as $s (null; . + $s);
.usage."os:linux"
| {credits: sigma(..credits),
minutes: (sigma(..amount) / 60000) }
answered Nov 21 '18 at 21:13
peakpeak
32.3k93959
Or more succintly:
reduce .usage."os:linux" as $item (
{};
.credits += $item.credits
| .minutes += ($item.amount / 60000) )
Or ...
Or abstracting the reduction into the general-purpose utility function sigma/1:
def sigma(s): reduce s as $s (null; . + $s);
.usage."os:linux"
| {credits: sigma(..credits),
minutes: (sigma(..amount) / 60000) }
answered Nov 21 '18 at 21:13
peakpeak
32.3k93959
edited Nov 22 '18 at 8:22
answered Nov 21 '18 at 21:13
peakpeak
32.3k93959
answered Nov 21 '18 at 21:13
peakpeak
32.3k93959
answered Nov 21 '18 at 21:13
peakpeak
32.3k93959
32.3k93959
add a comment |
add a comment |
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