How can I return a string with @Url.Action
How can I return a model property with url and put it on onclick like that:
Model:
public class MyModel
{
public string link {get;set;}
}
Controller:
public ActionResult Index()
{
MyModel oMyModel = new MyModel();
oMyModel.Link = "@Url.Action('" + "Index" + "', '" + "Users" + "')";
return View(oMyModel);
}
In view:
<a class="font" href="#" onclick="@Model.LINK">Click Here</a>
But in html it does not render corrently
c# html asp.net-mvc razor
asked Nov 22 '18 at 17:32
Vasco SilvaVasco Silva
66
|
show 3 more comments
How can I return a model property with url and put it on onclick like that:
Model:
public class MyModel
{
public string link {get;set;}
}
Controller:
public ActionResult Index()
{
MyModel oMyModel = new MyModel();
oMyModel.Link = "@Url.Action('" + "Index" + "', '" + "Users" + "')";
return View(oMyModel);
}
In view:
<a class="font" href="#" onclick="@Model.LINK">Click Here</a>
But in html it does not render corrently
c# html asp.net-mvc razor
asked Nov 22 '18 at 17:32
Vasco SilvaVasco Silva
66
2
model.Link = Url.Action(“actionName”,”controllerName”); this is the way to generate the url in your controller. For your case Link = Url.Action(“Index”,”Users”);
– akd
Nov 22 '18 at 17:34
Also it would be@Model.Link(Case sensitive) Although you have three different cases for that link property!
– Pete
Nov 22 '18 at 17:38
Also, use thehrefattribute of the anchor tag!
– Shyju
Nov 22 '18 at 17:40
It dont render correctly:the html result is <a class="child-font" href="#" onclick="Url.Action("Index","Cliente");">Visão Global</a>
– Vasco Silva
Nov 22 '18 at 17:41
1
it should be there - again, you need to remove the quotes and make sure you are using System.Web.Mvc;
– Pete
Nov 22 '18 at 17:48
|
show 3 more comments
How can I return a model property with url and put it on onclick like that:
Model:
public class MyModel
{
public string link {get;set;}
}
Controller:
public ActionResult Index()
{
MyModel oMyModel = new MyModel();
oMyModel.Link = "@Url.Action('" + "Index" + "', '" + "Users" + "')";
return View(oMyModel);
}
In view:
<a class="font" href="#" onclick="@Model.LINK">Click Here</a>
But in html it does not render corrently
c# html asp.net-mvc razor
asked Nov 22 '18 at 17:32
Vasco SilvaVasco Silva
66
How can I return a model property with url and put it on onclick like that:
Model:
public class MyModel
{
public string link {get;set;}
}
Controller:
public ActionResult Index()
{
MyModel oMyModel = new MyModel();
oMyModel.Link = "@Url.Action('" + "Index" + "', '" + "Users" + "')";
return View(oMyModel);
}
In view:
<a class="font" href="#" onclick="@Model.LINK">Click Here</a>
But in html it does not render corrently
c# html asp.net-mvc razor
c# html asp.net-mvc razor
asked Nov 22 '18 at 17:32
Vasco SilvaVasco Silva
66
asked Nov 22 '18 at 17:32
Vasco SilvaVasco Silva
66
edited Nov 22 '18 at 21:04
user3559349
asked Nov 22 '18 at 17:32
Vasco SilvaVasco Silva
66
asked Nov 22 '18 at 17:32
Vasco SilvaVasco Silva
66
asked Nov 22 '18 at 17:32
Vasco SilvaVasco Silva
66
66
2
model.Link = Url.Action(“actionName”,”controllerName”); this is the way to generate the url in your controller. For your case Link = Url.Action(“Index”,”Users”);
– akd
Nov 22 '18 at 17:34
Also it would be@Model.Link(Case sensitive) Although you have three different cases for that link property!
– Pete
Nov 22 '18 at 17:38
Also, use thehrefattribute of the anchor tag!
– Shyju
Nov 22 '18 at 17:40
It dont render correctly:the html result is <a class="child-font" href="#" onclick="Url.Action("Index","Cliente");">Visão Global</a>
– Vasco Silva
Nov 22 '18 at 17:41
1
it should be there - again, you need to remove the quotes and make sure you are using System.Web.Mvc;
– Pete
Nov 22 '18 at 17:48
|
show 3 more comments
2
model.Link = Url.Action(“actionName”,”controllerName”); this is the way to generate the url in your controller. For your case Link = Url.Action(“Index”,”Users”);
– akd
Nov 22 '18 at 17:34
Also it would be@Model.Link(Case sensitive) Although you have three different cases for that link property!
– Pete
Nov 22 '18 at 17:38
Also, use thehrefattribute of the anchor tag!
– Shyju
Nov 22 '18 at 17:40
It dont render correctly:the html result is <a class="child-font" href="#" onclick="Url.Action("Index","Cliente");">Visão Global</a>
– Vasco Silva
Nov 22 '18 at 17:41
1
it should be there - again, you need to remove the quotes and make sure you are using System.Web.Mvc;
– Pete
Nov 22 '18 at 17:48
2
2
model.Link = Url.Action(“actionName”,”controllerName”); this is the way to generate the url in your controller. For your case Link = Url.Action(“Index”,”Users”);
– akd
Nov 22 '18 at 17:34
model.Link = Url.Action(“actionName”,”controllerName”); this is the way to generate the url in your controller. For your case Link = Url.Action(“Index”,”Users”);
– akd
Nov 22 '18 at 17:34
Also it would be
@Model.Link (Case sensitive) Although you have three different cases for that link property!– Pete
Nov 22 '18 at 17:38
Also it would be
@Model.Link (Case sensitive) Although you have three different cases for that link property!– Pete
Nov 22 '18 at 17:38
Also, use the
href attribute of the anchor tag!– Shyju
Nov 22 '18 at 17:40
Also, use the
href attribute of the anchor tag!– Shyju
Nov 22 '18 at 17:40
It dont render correctly:the html result is <a class="child-font" href="#" onclick="Url.Action("Index","Cliente");">Visão Global</a>
– Vasco Silva
Nov 22 '18 at 17:41
It dont render correctly:the html result is <a class="child-font" href="#" onclick="Url.Action("Index","Cliente");">Visão Global</a>
– Vasco Silva
Nov 22 '18 at 17:41
1
1
it should be there - again, you need to remove the quotes and make sure you are using System.Web.Mvc;
– Pete
Nov 22 '18 at 17:48
it should be there - again, you need to remove the quotes and make sure you are using System.Web.Mvc;
– Pete
Nov 22 '18 at 17:48
|
show 3 more comments
1 Answer
1
active
oldest
votes
First, decide on a case. You're using link in your model, Link in your controller, and LINK in your view. In C#, those all mean different things. Choose one and make them all the same.
Second, the @ notation is Razor syntax. You are adding it to a string and then using razor to inject that string into your view. But by that time, it's not going to get processed by Razor again, so it stays as @Url.Action....
You should either do this in your controller, so it sets the variable to the actual URL (not just "@Url.Action..."):
oMyModel.Link = Url.Action("Index", "Users");
Or preferably, just call Url.Action in your view, which will give you the exact same result:
<a class="font" href="@Url.Action("Index", "Users")">Click Here</a>
answered Nov 22 '18 at 17:45
Gabriel LuciGabriel Luci
11.2k11525
But I want define url in controller and use in view. In controller, URL is not recognized.
– Vasco Silva
Nov 22 '18 at 17:47
Make sure you're using the right case. It'sUrl, notURL.Url.Actionis recognized in a controller. I just tried it.
– Gabriel Luci
Nov 22 '18 at 17:49
Urlis a property ofController, so make sure your controller class is inheriting fromController(although I don't know how your app could even work if it wasn't)
– Gabriel Luci
Nov 22 '18 at 17:53
It only render onclick="/Users" , not onclick="/Users/Index" . Error: Invalid regular expression: missing /
– Vasco Silva
Nov 22 '18 at 18:02
TheIndexaction is always the default, so "/Users" will use theIndexaction in theUserscontroller.
– Gabriel Luci
Nov 22 '18 at 18:04
|
show 3 more comments
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1 Answer
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First, decide on a case. You're using link in your model, Link in your controller, and LINK in your view. In C#, those all mean different things. Choose one and make them all the same.
Second, the @ notation is Razor syntax. You are adding it to a string and then using razor to inject that string into your view. But by that time, it's not going to get processed by Razor again, so it stays as @Url.Action....
You should either do this in your controller, so it sets the variable to the actual URL (not just "@Url.Action..."):
oMyModel.Link = Url.Action("Index", "Users");
Or preferably, just call Url.Action in your view, which will give you the exact same result:
<a class="font" href="@Url.Action("Index", "Users")">Click Here</a>
answered Nov 22 '18 at 17:45
Gabriel LuciGabriel Luci
11.2k11525
But I want define url in controller and use in view. In controller, URL is not recognized.
– Vasco Silva
Nov 22 '18 at 17:47
Make sure you're using the right case. It'sUrl, notURL.Url.Actionis recognized in a controller. I just tried it.
– Gabriel Luci
Nov 22 '18 at 17:49
Urlis a property ofController, so make sure your controller class is inheriting fromController(although I don't know how your app could even work if it wasn't)
– Gabriel Luci
Nov 22 '18 at 17:53
It only render onclick="/Users" , not onclick="/Users/Index" . Error: Invalid regular expression: missing /
– Vasco Silva
Nov 22 '18 at 18:02
TheIndexaction is always the default, so "/Users" will use theIndexaction in theUserscontroller.
– Gabriel Luci
Nov 22 '18 at 18:04
|
show 3 more comments
First, decide on a case. You're using link in your model, Link in your controller, and LINK in your view. In C#, those all mean different things. Choose one and make them all the same.
Second, the @ notation is Razor syntax. You are adding it to a string and then using razor to inject that string into your view. But by that time, it's not going to get processed by Razor again, so it stays as @Url.Action....
You should either do this in your controller, so it sets the variable to the actual URL (not just "@Url.Action..."):
oMyModel.Link = Url.Action("Index", "Users");
Or preferably, just call Url.Action in your view, which will give you the exact same result:
<a class="font" href="@Url.Action("Index", "Users")">Click Here</a>
answered Nov 22 '18 at 17:45
Gabriel LuciGabriel Luci
11.2k11525
But I want define url in controller and use in view. In controller, URL is not recognized.
– Vasco Silva
Nov 22 '18 at 17:47
Make sure you're using the right case. It'sUrl, notURL.Url.Actionis recognized in a controller. I just tried it.
– Gabriel Luci
Nov 22 '18 at 17:49
Urlis a property ofController, so make sure your controller class is inheriting fromController(although I don't know how your app could even work if it wasn't)
– Gabriel Luci
Nov 22 '18 at 17:53
It only render onclick="/Users" , not onclick="/Users/Index" . Error: Invalid regular expression: missing /
– Vasco Silva
Nov 22 '18 at 18:02
TheIndexaction is always the default, so "/Users" will use theIndexaction in theUserscontroller.
– Gabriel Luci
Nov 22 '18 at 18:04
|
show 3 more comments
First, decide on a case. You're using link in your model, Link in your controller, and LINK in your view. In C#, those all mean different things. Choose one and make them all the same.
Second, the @ notation is Razor syntax. You are adding it to a string and then using razor to inject that string into your view. But by that time, it's not going to get processed by Razor again, so it stays as @Url.Action....
You should either do this in your controller, so it sets the variable to the actual URL (not just "@Url.Action..."):
oMyModel.Link = Url.Action("Index", "Users");
Or preferably, just call Url.Action in your view, which will give you the exact same result:
<a class="font" href="@Url.Action("Index", "Users")">Click Here</a>
answered Nov 22 '18 at 17:45
Gabriel LuciGabriel Luci
11.2k11525
First, decide on a case. You're using link in your model, Link in your controller, and LINK in your view. In C#, those all mean different things. Choose one and make them all the same.
Second, the @ notation is Razor syntax. You are adding it to a string and then using razor to inject that string into your view. But by that time, it's not going to get processed by Razor again, so it stays as @Url.Action....
You should either do this in your controller, so it sets the variable to the actual URL (not just "@Url.Action..."):
oMyModel.Link = Url.Action("Index", "Users");
Or preferably, just call Url.Action in your view, which will give you the exact same result:
<a class="font" href="@Url.Action("Index", "Users")">Click Here</a>
answered Nov 22 '18 at 17:45
Gabriel LuciGabriel Luci
11.2k11525
edited Nov 22 '18 at 18:17
answered Nov 22 '18 at 17:45
Gabriel LuciGabriel Luci
11.2k11525
answered Nov 22 '18 at 17:45
Gabriel LuciGabriel Luci
11.2k11525
answered Nov 22 '18 at 17:45
Gabriel LuciGabriel Luci
11.2k11525
11.2k11525
But I want define url in controller and use in view. In controller, URL is not recognized.
– Vasco Silva
Nov 22 '18 at 17:47
Make sure you're using the right case. It'sUrl, notURL.Url.Actionis recognized in a controller. I just tried it.
– Gabriel Luci
Nov 22 '18 at 17:49
Urlis a property ofController, so make sure your controller class is inheriting fromController(although I don't know how your app could even work if it wasn't)
– Gabriel Luci
Nov 22 '18 at 17:53
It only render onclick="/Users" , not onclick="/Users/Index" . Error: Invalid regular expression: missing /
– Vasco Silva
Nov 22 '18 at 18:02
TheIndexaction is always the default, so "/Users" will use theIndexaction in theUserscontroller.
– Gabriel Luci
Nov 22 '18 at 18:04
|
show 3 more comments
But I want define url in controller and use in view. In controller, URL is not recognized.
– Vasco Silva
Nov 22 '18 at 17:47
Make sure you're using the right case. It'sUrl, notURL.Url.Actionis recognized in a controller. I just tried it.
– Gabriel Luci
Nov 22 '18 at 17:49
Urlis a property ofController, so make sure your controller class is inheriting fromController(although I don't know how your app could even work if it wasn't)
– Gabriel Luci
Nov 22 '18 at 17:53
It only render onclick="/Users" , not onclick="/Users/Index" . Error: Invalid regular expression: missing /
– Vasco Silva
Nov 22 '18 at 18:02
TheIndexaction is always the default, so "/Users" will use theIndexaction in theUserscontroller.
– Gabriel Luci
Nov 22 '18 at 18:04
But I want define url in controller and use in view. In controller, URL is not recognized.
– Vasco Silva
Nov 22 '18 at 17:47
But I want define url in controller and use in view. In controller, URL is not recognized.
– Vasco Silva
Nov 22 '18 at 17:47
Make sure you're using the right case. It's
Url, not URL. Url.Action is recognized in a controller. I just tried it.– Gabriel Luci
Nov 22 '18 at 17:49
Make sure you're using the right case. It's
Url, not URL. Url.Action is recognized in a controller. I just tried it.– Gabriel Luci
Nov 22 '18 at 17:49
Url is a property of Controller, so make sure your controller class is inheriting from Controller (although I don't know how your app could even work if it wasn't)– Gabriel Luci
Nov 22 '18 at 17:53
Url is a property of Controller, so make sure your controller class is inheriting from Controller (although I don't know how your app could even work if it wasn't)– Gabriel Luci
Nov 22 '18 at 17:53
It only render onclick="/Users" , not onclick="/Users/Index" . Error: Invalid regular expression: missing /
– Vasco Silva
Nov 22 '18 at 18:02
It only render onclick="/Users" , not onclick="/Users/Index" . Error: Invalid regular expression: missing /
– Vasco Silva
Nov 22 '18 at 18:02
The
Index action is always the default, so "/Users" will use the Index action in the Users controller.– Gabriel Luci
Nov 22 '18 at 18:04
The
Index action is always the default, so "/Users" will use the Index action in the Users controller.– Gabriel Luci
Nov 22 '18 at 18:04
|
show 3 more comments
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2
model.Link = Url.Action(“actionName”,”controllerName”); this is the way to generate the url in your controller. For your case Link = Url.Action(“Index”,”Users”);
– akd
Nov 22 '18 at 17:34
Also it would be
@Model.Link(Case sensitive) Although you have three different cases for that link property!– Pete
Nov 22 '18 at 17:38
Also, use the
hrefattribute of the anchor tag!– Shyju
Nov 22 '18 at 17:40
It dont render correctly:the html result is <a class="child-font" href="#" onclick="Url.Action("Index","Cliente");">Visão Global</a>
– Vasco Silva
Nov 22 '18 at 17:41
1
it should be there - again, you need to remove the quotes and make sure you are using System.Web.Mvc;
– Pete
Nov 22 '18 at 17:48