I am solving below problem but all test cases not getting pass in java












0















There are a number of genes in a chromosome and your bioinformatic friend wants to check if a particular chromosome has a series of genes or not.
The sequence in which genes occur is important. You want to help your friend in this matter.
He gives you n chromosomes and a series of genes he wants to check. Help him identify whether these genes are present in the
chromosome in the given order.



Because you are not a biology student, he’s made things easier for you. He represents genes by a letter, number or special character present in ASCII.
Spaces do NOT represent a gene.



Example



If the chromosome is abdfgc, and the genes he’s querying for is abc, these are present (in the correct order) in the chromosome (marked in bold).
a*b*dfg*c*. However if the query is bca, this is not present in the correct order in the chromosome.



Input



The first line of input consists of an integer n which is the number of test cases.



Each test case consists of two lines of input:




  • The first line contains the chromosome

  • The second line contains the gene you are querying for
    Output


The output for that chromosome-gene pair should be “YES” if the genes, taken in order, are contained in the chromosome and “NO” otherwise.
The output should have n lines containing YES/NO.



Constraints



1 <= n <= 10000

1 <= |chromosome| <100

1 <= |gene| < |chromosome|


Sample Input



4
12sd78f
sf
12345efd
1e3d
ijkfgds
jkf
1111456
116


Sample Output



YES
NO
YES
YES


Code



import java.io.BufferedReader;
import java.io.InputStreamReader;

public class solution {

private static String checkGem(String ch, String gem) {

int prevIndex = 0;
for(int n=0; n < gem.length(); n++) {
if(ch.indexOf(gem.charAt(n), prevIndex)==-1) {
return "NO";
}
else {
prevIndex = ch.indexOf(gem.charAt(n), prevIndex);
}
}

return "YES";
}
public static void main(String args) throws Exception {

//Scanner sc = new Scanner(System.in);
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String test = br.readLine();

int t = Integer.parseInt(test);

for(int i=0; i<t; i++) {
String ch = br.readLine();
String gem = br.readLine();
ch = ch.replaceAll("\s","");
gem = gem.replaceAll("\s","");
String ans = checkGem(ch, gem);
System.out.println(ans);
}

}
}









share|improve this question




















  • 1





    When you step through the code in your debugger, where does it not do what you expected?

    – Peter Lawrey
    Nov 22 '18 at 17:34











  • I did launch you code and all works well. Give an example of the test, that does not pass correctly.

    – Valentyn Hruzytskyi
    Nov 22 '18 at 17:51











  • prevIndex + 1 do not start next search from the same place

    – Dmitry Bychenko
    Nov 22 '18 at 17:56













  • where are you having problems

    – preciousbetine
    Nov 22 '18 at 17:59











  • I dont have test cases, only output i am getting as test case failed.

    – Nitin
    Nov 22 '18 at 18:01
















0















There are a number of genes in a chromosome and your bioinformatic friend wants to check if a particular chromosome has a series of genes or not.
The sequence in which genes occur is important. You want to help your friend in this matter.
He gives you n chromosomes and a series of genes he wants to check. Help him identify whether these genes are present in the
chromosome in the given order.



Because you are not a biology student, he’s made things easier for you. He represents genes by a letter, number or special character present in ASCII.
Spaces do NOT represent a gene.



Example



If the chromosome is abdfgc, and the genes he’s querying for is abc, these are present (in the correct order) in the chromosome (marked in bold).
a*b*dfg*c*. However if the query is bca, this is not present in the correct order in the chromosome.



Input



The first line of input consists of an integer n which is the number of test cases.



Each test case consists of two lines of input:




  • The first line contains the chromosome

  • The second line contains the gene you are querying for
    Output


The output for that chromosome-gene pair should be “YES” if the genes, taken in order, are contained in the chromosome and “NO” otherwise.
The output should have n lines containing YES/NO.



Constraints



1 <= n <= 10000

1 <= |chromosome| <100

1 <= |gene| < |chromosome|


Sample Input



4
12sd78f
sf
12345efd
1e3d
ijkfgds
jkf
1111456
116


Sample Output



YES
NO
YES
YES


Code



import java.io.BufferedReader;
import java.io.InputStreamReader;

public class solution {

private static String checkGem(String ch, String gem) {

int prevIndex = 0;
for(int n=0; n < gem.length(); n++) {
if(ch.indexOf(gem.charAt(n), prevIndex)==-1) {
return "NO";
}
else {
prevIndex = ch.indexOf(gem.charAt(n), prevIndex);
}
}

return "YES";
}
public static void main(String args) throws Exception {

//Scanner sc = new Scanner(System.in);
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String test = br.readLine();

int t = Integer.parseInt(test);

for(int i=0; i<t; i++) {
String ch = br.readLine();
String gem = br.readLine();
ch = ch.replaceAll("\s","");
gem = gem.replaceAll("\s","");
String ans = checkGem(ch, gem);
System.out.println(ans);
}

}
}









share|improve this question




















  • 1





    When you step through the code in your debugger, where does it not do what you expected?

    – Peter Lawrey
    Nov 22 '18 at 17:34











  • I did launch you code and all works well. Give an example of the test, that does not pass correctly.

    – Valentyn Hruzytskyi
    Nov 22 '18 at 17:51











  • prevIndex + 1 do not start next search from the same place

    – Dmitry Bychenko
    Nov 22 '18 at 17:56













  • where are you having problems

    – preciousbetine
    Nov 22 '18 at 17:59











  • I dont have test cases, only output i am getting as test case failed.

    – Nitin
    Nov 22 '18 at 18:01














0












0








0








There are a number of genes in a chromosome and your bioinformatic friend wants to check if a particular chromosome has a series of genes or not.
The sequence in which genes occur is important. You want to help your friend in this matter.
He gives you n chromosomes and a series of genes he wants to check. Help him identify whether these genes are present in the
chromosome in the given order.



Because you are not a biology student, he’s made things easier for you. He represents genes by a letter, number or special character present in ASCII.
Spaces do NOT represent a gene.



Example



If the chromosome is abdfgc, and the genes he’s querying for is abc, these are present (in the correct order) in the chromosome (marked in bold).
a*b*dfg*c*. However if the query is bca, this is not present in the correct order in the chromosome.



Input



The first line of input consists of an integer n which is the number of test cases.



Each test case consists of two lines of input:




  • The first line contains the chromosome

  • The second line contains the gene you are querying for
    Output


The output for that chromosome-gene pair should be “YES” if the genes, taken in order, are contained in the chromosome and “NO” otherwise.
The output should have n lines containing YES/NO.



Constraints



1 <= n <= 10000

1 <= |chromosome| <100

1 <= |gene| < |chromosome|


Sample Input



4
12sd78f
sf
12345efd
1e3d
ijkfgds
jkf
1111456
116


Sample Output



YES
NO
YES
YES


Code



import java.io.BufferedReader;
import java.io.InputStreamReader;

public class solution {

private static String checkGem(String ch, String gem) {

int prevIndex = 0;
for(int n=0; n < gem.length(); n++) {
if(ch.indexOf(gem.charAt(n), prevIndex)==-1) {
return "NO";
}
else {
prevIndex = ch.indexOf(gem.charAt(n), prevIndex);
}
}

return "YES";
}
public static void main(String args) throws Exception {

//Scanner sc = new Scanner(System.in);
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String test = br.readLine();

int t = Integer.parseInt(test);

for(int i=0; i<t; i++) {
String ch = br.readLine();
String gem = br.readLine();
ch = ch.replaceAll("\s","");
gem = gem.replaceAll("\s","");
String ans = checkGem(ch, gem);
System.out.println(ans);
}

}
}









share|improve this question
















There are a number of genes in a chromosome and your bioinformatic friend wants to check if a particular chromosome has a series of genes or not.
The sequence in which genes occur is important. You want to help your friend in this matter.
He gives you n chromosomes and a series of genes he wants to check. Help him identify whether these genes are present in the
chromosome in the given order.



Because you are not a biology student, he’s made things easier for you. He represents genes by a letter, number or special character present in ASCII.
Spaces do NOT represent a gene.



Example



If the chromosome is abdfgc, and the genes he’s querying for is abc, these are present (in the correct order) in the chromosome (marked in bold).
a*b*dfg*c*. However if the query is bca, this is not present in the correct order in the chromosome.



Input



The first line of input consists of an integer n which is the number of test cases.



Each test case consists of two lines of input:




  • The first line contains the chromosome

  • The second line contains the gene you are querying for
    Output


The output for that chromosome-gene pair should be “YES” if the genes, taken in order, are contained in the chromosome and “NO” otherwise.
The output should have n lines containing YES/NO.



Constraints



1 <= n <= 10000

1 <= |chromosome| <100

1 <= |gene| < |chromosome|


Sample Input



4
12sd78f
sf
12345efd
1e3d
ijkfgds
jkf
1111456
116


Sample Output



YES
NO
YES
YES


Code



import java.io.BufferedReader;
import java.io.InputStreamReader;

public class solution {

private static String checkGem(String ch, String gem) {

int prevIndex = 0;
for(int n=0; n < gem.length(); n++) {
if(ch.indexOf(gem.charAt(n), prevIndex)==-1) {
return "NO";
}
else {
prevIndex = ch.indexOf(gem.charAt(n), prevIndex);
}
}

return "YES";
}
public static void main(String args) throws Exception {

//Scanner sc = new Scanner(System.in);
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String test = br.readLine();

int t = Integer.parseInt(test);

for(int i=0; i<t; i++) {
String ch = br.readLine();
String gem = br.readLine();
ch = ch.replaceAll("\s","");
gem = gem.replaceAll("\s","");
String ans = checkGem(ch, gem);
System.out.println(ans);
}

}
}






java






share|improve this question















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share|improve this question




share|improve this question








edited Nov 22 '18 at 17:47









Valentyn Hruzytskyi

321113




321113










asked Nov 22 '18 at 17:32









NitinNitin

61




61








  • 1





    When you step through the code in your debugger, where does it not do what you expected?

    – Peter Lawrey
    Nov 22 '18 at 17:34











  • I did launch you code and all works well. Give an example of the test, that does not pass correctly.

    – Valentyn Hruzytskyi
    Nov 22 '18 at 17:51











  • prevIndex + 1 do not start next search from the same place

    – Dmitry Bychenko
    Nov 22 '18 at 17:56













  • where are you having problems

    – preciousbetine
    Nov 22 '18 at 17:59











  • I dont have test cases, only output i am getting as test case failed.

    – Nitin
    Nov 22 '18 at 18:01














  • 1





    When you step through the code in your debugger, where does it not do what you expected?

    – Peter Lawrey
    Nov 22 '18 at 17:34











  • I did launch you code and all works well. Give an example of the test, that does not pass correctly.

    – Valentyn Hruzytskyi
    Nov 22 '18 at 17:51











  • prevIndex + 1 do not start next search from the same place

    – Dmitry Bychenko
    Nov 22 '18 at 17:56













  • where are you having problems

    – preciousbetine
    Nov 22 '18 at 17:59











  • I dont have test cases, only output i am getting as test case failed.

    – Nitin
    Nov 22 '18 at 18:01








1




1





When you step through the code in your debugger, where does it not do what you expected?

– Peter Lawrey
Nov 22 '18 at 17:34





When you step through the code in your debugger, where does it not do what you expected?

– Peter Lawrey
Nov 22 '18 at 17:34













I did launch you code and all works well. Give an example of the test, that does not pass correctly.

– Valentyn Hruzytskyi
Nov 22 '18 at 17:51





I did launch you code and all works well. Give an example of the test, that does not pass correctly.

– Valentyn Hruzytskyi
Nov 22 '18 at 17:51













prevIndex + 1 do not start next search from the same place

– Dmitry Bychenko
Nov 22 '18 at 17:56







prevIndex + 1 do not start next search from the same place

– Dmitry Bychenko
Nov 22 '18 at 17:56















where are you having problems

– preciousbetine
Nov 22 '18 at 17:59





where are you having problems

– preciousbetine
Nov 22 '18 at 17:59













I dont have test cases, only output i am getting as test case failed.

– Nitin
Nov 22 '18 at 18:01





I dont have test cases, only output i am getting as test case failed.

– Nitin
Nov 22 '18 at 18:01












1 Answer
1






active

oldest

votes


















0














You have a bug in your code. You can try this test case:



1
a
aaaaa


This one should be "NO", but your code output is "YES".



The problem is that you need to advance prevIndex it should be:



prevIndex = ch.indexOf(gem.charAt(n), prevIndex) + 1; 





share|improve this answer
























  • Thanks a lot its working Now

    – Nitin
    Nov 22 '18 at 19:27











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









0














You have a bug in your code. You can try this test case:



1
a
aaaaa


This one should be "NO", but your code output is "YES".



The problem is that you need to advance prevIndex it should be:



prevIndex = ch.indexOf(gem.charAt(n), prevIndex) + 1; 





share|improve this answer
























  • Thanks a lot its working Now

    – Nitin
    Nov 22 '18 at 19:27
















0














You have a bug in your code. You can try this test case:



1
a
aaaaa


This one should be "NO", but your code output is "YES".



The problem is that you need to advance prevIndex it should be:



prevIndex = ch.indexOf(gem.charAt(n), prevIndex) + 1; 





share|improve this answer
























  • Thanks a lot its working Now

    – Nitin
    Nov 22 '18 at 19:27














0












0








0







You have a bug in your code. You can try this test case:



1
a
aaaaa


This one should be "NO", but your code output is "YES".



The problem is that you need to advance prevIndex it should be:



prevIndex = ch.indexOf(gem.charAt(n), prevIndex) + 1; 





share|improve this answer













You have a bug in your code. You can try this test case:



1
a
aaaaa


This one should be "NO", but your code output is "YES".



The problem is that you need to advance prevIndex it should be:



prevIndex = ch.indexOf(gem.charAt(n), prevIndex) + 1; 






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 22 '18 at 18:08









Mahmoud HanafyMahmoud Hanafy

97011528




97011528













  • Thanks a lot its working Now

    – Nitin
    Nov 22 '18 at 19:27



















  • Thanks a lot its working Now

    – Nitin
    Nov 22 '18 at 19:27

















Thanks a lot its working Now

– Nitin
Nov 22 '18 at 19:27





Thanks a lot its working Now

– Nitin
Nov 22 '18 at 19:27




















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