Can't get directories inside root paths from fileshare in PowerShell












0















I am trying to get the names of files and directories that exist in the root path of a fileshare.



The following code:



$List = Get-ChildItem -Path "\filesharefiles" | Write-Output -InputObject $List


gives the files and directories of fileserverfiles as expected. But



$List = Get-ChildItem -Path "\fileshare*" | Write-Output -InputObject $List


results in a blank output. What is happening in PowerShell that is causing this issue?










share|improve this question























  • Does the path have spaces in it? Why? Also, you're not querying the list of files, you're just trying to list the files. So using the asterisk is pointless.

    – music2myear
    Jan 18 at 0:40











  • $List = Get-ChildItem -Path "\fileshare" results in a Cannot find path '\fileshare' because it does not exist. I want to get the list of the files, and perform specific actions on each item in the list via a loop.

    – Anonymous
    Jan 18 at 0:51













  • Can you be more specific what you are trying to accomplish? \fileserver* is not a valid path. A UNC path contains BOTH the server name and share name. \servernamesharenamefilename. At best, querying \fileshare will return a list of shares on the server named fileshare. Not files/folders.

    – Appleoddity
    Jan 18 at 1:52













  • fileshare is the name of the server. Everything on that server is being shared.

    – Anonymous
    Jan 18 at 3:26











  • You're missing a point @appleoddity made: everything on the server may be shared, but it's not being shared AS the server name, it's being shared as \servernamesharename

    – music2myear
    Jan 18 at 4:14
















0















I am trying to get the names of files and directories that exist in the root path of a fileshare.



The following code:



$List = Get-ChildItem -Path "\filesharefiles" | Write-Output -InputObject $List


gives the files and directories of fileserverfiles as expected. But



$List = Get-ChildItem -Path "\fileshare*" | Write-Output -InputObject $List


results in a blank output. What is happening in PowerShell that is causing this issue?










share|improve this question























  • Does the path have spaces in it? Why? Also, you're not querying the list of files, you're just trying to list the files. So using the asterisk is pointless.

    – music2myear
    Jan 18 at 0:40











  • $List = Get-ChildItem -Path "\fileshare" results in a Cannot find path '\fileshare' because it does not exist. I want to get the list of the files, and perform specific actions on each item in the list via a loop.

    – Anonymous
    Jan 18 at 0:51













  • Can you be more specific what you are trying to accomplish? \fileserver* is not a valid path. A UNC path contains BOTH the server name and share name. \servernamesharenamefilename. At best, querying \fileshare will return a list of shares on the server named fileshare. Not files/folders.

    – Appleoddity
    Jan 18 at 1:52













  • fileshare is the name of the server. Everything on that server is being shared.

    – Anonymous
    Jan 18 at 3:26











  • You're missing a point @appleoddity made: everything on the server may be shared, but it's not being shared AS the server name, it's being shared as \servernamesharename

    – music2myear
    Jan 18 at 4:14














0












0








0








I am trying to get the names of files and directories that exist in the root path of a fileshare.



The following code:



$List = Get-ChildItem -Path "\filesharefiles" | Write-Output -InputObject $List


gives the files and directories of fileserverfiles as expected. But



$List = Get-ChildItem -Path "\fileshare*" | Write-Output -InputObject $List


results in a blank output. What is happening in PowerShell that is causing this issue?










share|improve this question














I am trying to get the names of files and directories that exist in the root path of a fileshare.



The following code:



$List = Get-ChildItem -Path "\filesharefiles" | Write-Output -InputObject $List


gives the files and directories of fileserverfiles as expected. But



$List = Get-ChildItem -Path "\fileshare*" | Write-Output -InputObject $List


results in a blank output. What is happening in PowerShell that is causing this issue?







powershell






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 18 at 0:31









AnonymousAnonymous

1




1













  • Does the path have spaces in it? Why? Also, you're not querying the list of files, you're just trying to list the files. So using the asterisk is pointless.

    – music2myear
    Jan 18 at 0:40











  • $List = Get-ChildItem -Path "\fileshare" results in a Cannot find path '\fileshare' because it does not exist. I want to get the list of the files, and perform specific actions on each item in the list via a loop.

    – Anonymous
    Jan 18 at 0:51













  • Can you be more specific what you are trying to accomplish? \fileserver* is not a valid path. A UNC path contains BOTH the server name and share name. \servernamesharenamefilename. At best, querying \fileshare will return a list of shares on the server named fileshare. Not files/folders.

    – Appleoddity
    Jan 18 at 1:52













  • fileshare is the name of the server. Everything on that server is being shared.

    – Anonymous
    Jan 18 at 3:26











  • You're missing a point @appleoddity made: everything on the server may be shared, but it's not being shared AS the server name, it's being shared as \servernamesharename

    – music2myear
    Jan 18 at 4:14



















  • Does the path have spaces in it? Why? Also, you're not querying the list of files, you're just trying to list the files. So using the asterisk is pointless.

    – music2myear
    Jan 18 at 0:40











  • $List = Get-ChildItem -Path "\fileshare" results in a Cannot find path '\fileshare' because it does not exist. I want to get the list of the files, and perform specific actions on each item in the list via a loop.

    – Anonymous
    Jan 18 at 0:51













  • Can you be more specific what you are trying to accomplish? \fileserver* is not a valid path. A UNC path contains BOTH the server name and share name. \servernamesharenamefilename. At best, querying \fileshare will return a list of shares on the server named fileshare. Not files/folders.

    – Appleoddity
    Jan 18 at 1:52













  • fileshare is the name of the server. Everything on that server is being shared.

    – Anonymous
    Jan 18 at 3:26











  • You're missing a point @appleoddity made: everything on the server may be shared, but it's not being shared AS the server name, it's being shared as \servernamesharename

    – music2myear
    Jan 18 at 4:14

















Does the path have spaces in it? Why? Also, you're not querying the list of files, you're just trying to list the files. So using the asterisk is pointless.

– music2myear
Jan 18 at 0:40





Does the path have spaces in it? Why? Also, you're not querying the list of files, you're just trying to list the files. So using the asterisk is pointless.

– music2myear
Jan 18 at 0:40













$List = Get-ChildItem -Path "\fileshare" results in a Cannot find path '\fileshare' because it does not exist. I want to get the list of the files, and perform specific actions on each item in the list via a loop.

– Anonymous
Jan 18 at 0:51







$List = Get-ChildItem -Path "\fileshare" results in a Cannot find path '\fileshare' because it does not exist. I want to get the list of the files, and perform specific actions on each item in the list via a loop.

– Anonymous
Jan 18 at 0:51















Can you be more specific what you are trying to accomplish? \fileserver* is not a valid path. A UNC path contains BOTH the server name and share name. \servernamesharenamefilename. At best, querying \fileshare will return a list of shares on the server named fileshare. Not files/folders.

– Appleoddity
Jan 18 at 1:52







Can you be more specific what you are trying to accomplish? \fileserver* is not a valid path. A UNC path contains BOTH the server name and share name. \servernamesharenamefilename. At best, querying \fileshare will return a list of shares on the server named fileshare. Not files/folders.

– Appleoddity
Jan 18 at 1:52















fileshare is the name of the server. Everything on that server is being shared.

– Anonymous
Jan 18 at 3:26





fileshare is the name of the server. Everything on that server is being shared.

– Anonymous
Jan 18 at 3:26













You're missing a point @appleoddity made: everything on the server may be shared, but it's not being shared AS the server name, it's being shared as \servernamesharename

– music2myear
Jan 18 at 4:14





You're missing a point @appleoddity made: everything on the server may be shared, but it's not being shared AS the server name, it's being shared as \servernamesharename

– music2myear
Jan 18 at 4:14










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